An option is not seeing an argument (that is a variable) in bash, please help?
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#!/bin/bash counter=2 while [ $counter -lt 19 ] do username= head -n $counter ./user_sheet.csv | tail -n 1 | cut -d ';' -f1 psswd= head -n $counter ./user_sheet.csv | tail -n 1 | cut -d ';' -f2 full_name= head -n $counter ./user_sheet.csv | tail -n 1 | cut -d ';' -f3 group= head -n $counter ./user_sheet.csv | tail -n 1 | cut -d ';' -f4 second_group= head -n $counter ./user_sheet.csv | tail -n 1 | cut -d ';' -f5 sudo useradd $username -m -g $group -s /bin/bash -c $full_name if [ second_group = LPGestionnaires ] then usermod -a -G $second_group $user fi #echo "$username:$psswd" | chpasswd ((counter++)) done echo Execution comp...