Subnetting an IP address (172.16.0.0/12) into 2 subnets
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Say I have the private network address 172.16.0.0/12 and I want to split it into 2 subnets.
There are 12 bits used for the network number leaving 20 bit for the host number. I use 1 of these host bits as a subnet number giving me 2 subnets and leaving me with 19 bits for the host number.
This will mean I will have 2^19 - 2 = 524286 IP addresses per subnet?
And the second subnet address will be 172.24.0.0. The broadcast address of the second subnet will be 172.31.255.255
Have I got that correct?
networking ip routing subnet
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up vote
1
down vote
favorite
Say I have the private network address 172.16.0.0/12 and I want to split it into 2 subnets.
There are 12 bits used for the network number leaving 20 bit for the host number. I use 1 of these host bits as a subnet number giving me 2 subnets and leaving me with 19 bits for the host number.
This will mean I will have 2^19 - 2 = 524286 IP addresses per subnet?
And the second subnet address will be 172.24.0.0. The broadcast address of the second subnet will be 172.31.255.255
Have I got that correct?
networking ip routing subnet
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Say I have the private network address 172.16.0.0/12 and I want to split it into 2 subnets.
There are 12 bits used for the network number leaving 20 bit for the host number. I use 1 of these host bits as a subnet number giving me 2 subnets and leaving me with 19 bits for the host number.
This will mean I will have 2^19 - 2 = 524286 IP addresses per subnet?
And the second subnet address will be 172.24.0.0. The broadcast address of the second subnet will be 172.31.255.255
Have I got that correct?
networking ip routing subnet
Say I have the private network address 172.16.0.0/12 and I want to split it into 2 subnets.
There are 12 bits used for the network number leaving 20 bit for the host number. I use 1 of these host bits as a subnet number giving me 2 subnets and leaving me with 19 bits for the host number.
This will mean I will have 2^19 - 2 = 524286 IP addresses per subnet?
And the second subnet address will be 172.24.0.0. The broadcast address of the second subnet will be 172.31.255.255
Have I got that correct?
networking ip routing subnet
networking ip routing subnet
asked Mar 11 '13 at 12:00
sonicboom
127127
127127
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1 Answer
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Yes, these numbers are correct. There are several IP subnet calculators on the internet that will help confirm these types of calculation, as well as phone apps.
Note that it is only in niche scenarios that such a large network would be useful, let alone a good idea.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Yes, these numbers are correct. There are several IP subnet calculators on the internet that will help confirm these types of calculation, as well as phone apps.
Note that it is only in niche scenarios that such a large network would be useful, let alone a good idea.
add a comment |
up vote
3
down vote
accepted
Yes, these numbers are correct. There are several IP subnet calculators on the internet that will help confirm these types of calculation, as well as phone apps.
Note that it is only in niche scenarios that such a large network would be useful, let alone a good idea.
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Yes, these numbers are correct. There are several IP subnet calculators on the internet that will help confirm these types of calculation, as well as phone apps.
Note that it is only in niche scenarios that such a large network would be useful, let alone a good idea.
Yes, these numbers are correct. There are several IP subnet calculators on the internet that will help confirm these types of calculation, as well as phone apps.
Note that it is only in niche scenarios that such a large network would be useful, let alone a good idea.
answered Mar 11 '13 at 12:09
Paul
47.8k13121147
47.8k13121147
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