Bdtyktl

I am really a beginner in the field of language, please excuse me in advance.

I would like to return the value of a command in a parameter, ie return the value of ls -l in $1.

I also can't do the ls -l eq 0. It's obviously wrong what I wrote, but I don't understand at all how to do it

My entire wish of the code is to delete all the "empty" files from a folder.

thank you in advance

If you want to save the return value of a command in bash you can do something like

ls -l 2>&1 > /dev/null

VAR=$?

echo $VAR

(though there is probably a much simpler way to do it :'D)

For deleting empty directories, to check if they're empty try this

COUNT=$(ls -l | wc -l)

echo $COUNT

For checking for empty files

if [ -s file.ext ]; then

    echo "file.ext is NOT empty"

fi

Here is a general outline of what it is you want to be doing

#!/bin/bash



for file in $(ls -l);

do

    if [ -f $file ]; then

        if [ ! -s $file ];then

            echo "$file is an empty file"

        fi

    fi

done

Please all you bash experts critique me and give me some pointers, on how terrible (or good :) ) this is. I am in no way an expert :'D

You can use the following simple bash script:

#!/bin/bash

for file in *

do

  siz=`stat -c %s "$file"`

  if [ $siz -eq 0 ]; then

    echo Deleting the file "$file"

    rm -f "$file"

  fi

done

This script iterates over all files in the current directory, then gets the size of every file with the stat -c %s command. If this size is zero, it executes the block within the if clause, outputs the name of the file and then removes it without regard to its attributes.