Convert an array to list with specific range in Java 8












6














I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8







share|improve this question


















  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago


















6














I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8







share|improve this question


















  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago
















6












6








6


3





I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8







share|improve this question













I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8




java java-8






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









manjunath ramigani

501415




501415








  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago
















  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago










1




1




ArrayList class have a subList method, which can be used to slice the list.
– raviraja
1 hour ago




ArrayList class have a subList method, which can be used to slice the list.
– raviraja
1 hour ago




1




1




Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
– nullpointer
1 hour ago






Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
– nullpointer
1 hour ago














7 Answers
7






active

oldest

votes


















6














You can use Stream.skip():



List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





share|improve this answer





















  • the only challenge with skip would be selecting initial elements instead of skipping
    – nullpointer
    1 hour ago






  • 1




    @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
    – Robby Cornelissen
    1 hour ago



















6














You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



List<String> list = Arrays.stream(optArr, 1, optArr.length)

                          .collect(Collectors.toList());



Returns a sequential Stream with the specified range of the specified
array as its source.





Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





share|improve this answer































    1














    One non Java 8 option might be to just create a view on top of your current list which omits the first element:



    List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
    
List<String> viewList = list.subList(1, list.size());


    This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






    share|improve this answer























    • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
      – Tim Biegeleisen
      1 hour ago



















    0














    List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


    I think it must work.



    See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






    share|improve this answer








    New contributor




    Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.


























      0














      One method use List.sublist(int,int)



      List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
      
System.out.println(list);


      Second method use Stream



      List<String> list = Arrays.stream(optArr)
      
    .skip(1)
      
    .collect(Collectors.toList());
      
System.out.println(list);





      share|improve this answer





























        0














        It should be like this.



        List<String> al = new ArrayList<>(Arrays.asList(optArr));
        
List actualList = list.subList(1, al.size());





        share|improve this answer





























          0














          Looking at your data you might consider :



          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


          But if you just want to filter the first index sublist is the way to go.
          You do not need to use stream whatever of are you can.






          share|improve this answer



















          • 1




            not content based, but index based
            – nullpointer
            1 hour ago











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          7 Answers
          7






          active

          oldest

          votes








          7 Answers
          7






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          6














          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





          share|improve this answer





















          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago
















          6














          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





          share|improve this answer





















          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago














          6












          6








          6






          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





          share|improve this answer












          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 1 hour ago









          Robby Cornelissen

          43.2k126789




          43.2k126789












          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago


















          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago
















          the only challenge with skip would be selecting initial elements instead of skipping
          – nullpointer
          1 hour ago




          the only challenge with skip would be selecting initial elements instead of skipping
          – nullpointer
          1 hour ago




          1




          1




          @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
          – Robby Cornelissen
          1 hour ago




          @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
          – Robby Cornelissen
          1 hour ago













          6














          You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



          List<String> list = Arrays.stream(optArr, 1, optArr.length)
          
                          .collect(Collectors.toList());



          Returns a sequential Stream with the specified range of the specified
          array as its source          .





          Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



          List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





          share|improve this answer




























            6














            You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



            List<String> list = Arrays.stream(optArr, 1, optArr.length)
            
                          .collect(Collectors.toList());



            Returns a sequential Stream with the specified range of the specified
            array as its source            .





            Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



            List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





            share|improve this answer


























              6












              6








              6






              You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



              List<String> list = Arrays.stream(optArr, 1, optArr.length)
              
                          .collect(Collectors.toList());



              Returns a sequential Stream with the specified range of the specified
              array as its source              .





              Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



              List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





              share|improve this answer














              You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



              List<String> list = Arrays.stream(optArr, 1, optArr.length)
              
                          .collect(Collectors.toList());



              Returns a sequential Stream with the specified range of the specified
              array as its source              .





              Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



              List<String> list = Arrays.asList(optArr).subList(1, optArr.length);






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 1 hour ago

























              answered 1 hour ago









              nullpointer

              41.2k1086173




              41.2k1086173























                  1














                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






                  share|improve this answer























                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago
















                  1














                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






                  share|improve this answer























                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago














                  1












                  1








                  1






                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






                  share|improve this answer














                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 1 hour ago

























                  answered 1 hour ago









                  Tim Biegeleisen

                  216k1386139




                  216k1386139












                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago


















                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago
















                  @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                  – Tim Biegeleisen
                  1 hour ago




                  @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                  – Tim Biegeleisen
                  1 hour ago











                  0














                  List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                  I think it must work.



                  See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






                  share|improve this answer








                  New contributor




                  Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.























                    0














                    List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                    I think it must work.



                    See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






                    share|improve this answer








                    New contributor




                    Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.





















                      0












                      0








                      0






                      List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                      I think it must work.



                      See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






                      share|improve this answer








                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct. 









                      List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                      I think it must work.



                      See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html







                      share|improve this answer








                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      share|improve this answer



                      share|improve this answer






                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      answered 1 hour ago









                      Crutch Master

                      313




                      313




                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.





                      New contributor





                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.























                          0














                          One method use List.sublist(int,int)



                          List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                          
System.out.println(list);


                          Second method use Stream



                          List<String> list = Arrays.stream(optArr)
                          
    .skip(1)
                          
    .collect(Collectors.toList());
                          
System.out.println(list);





                          share|improve this answer


























                            0














                            One method use List.sublist(int,int)



                            List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                            
System.out.println(list);


                            Second method use Stream



                            List<String> list = Arrays.stream(optArr)
                            
    .skip(1)
                            
    .collect(Collectors.toList());
                            
System.out.println(list);





                            share|improve this answer
























                              0












                              0








                              0






                              One method use List.sublist(int,int)



                              List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                              
System.out.println(list);


                              Second method use Stream



                              List<String> list = Arrays.stream(optArr)
                              
    .skip(1)
                              
    .collect(Collectors.toList());
                              
System.out.println(list);





                              share|improve this answer












                              One method use List.sublist(int,int)



                              List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                              
System.out.println(list);


                              Second method use Stream



                              List<String> list = Arrays.stream(optArr)
                              
    .skip(1)
                              
    .collect(Collectors.toList());
                              
System.out.println(list);






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 1 hour ago









                              TongChen

                              1046




                              1046























                                  0














                                  It should be like this.



                                  List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                  
List actualList = list.subList(1, al.size());





                                  share|improve this answer


























                                    0














                                    It should be like this.



                                    List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                    
List actualList = list.subList(1, al.size());





                                    share|improve this answer
























                                      0












                                      0








                                      0






                                      It should be like this.



                                      List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                      
List actualList = list.subList(1, al.size());





                                      share|improve this answer












                                      It should be like this.



                                      List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                      
List actualList = list.subList(1, al.size());






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered 1 hour ago









                                      TheSprinter

                                      244110




                                      244110























                                          0














                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.






                                          share|improve this answer



















                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago
















                                          0














                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.






                                          share|improve this answer



















                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago














                                          0












                                          0








                                          0






                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.






                                          share|improve this answer














                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.







                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited 1 hour ago

























                                          answered 1 hour ago









                                          fastcodejava

                                          23.8k19109161




                                          23.8k19109161








                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago














                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago








                                          1




                                          1




                                          not content based, but index based
                                          – nullpointer
                                          1 hour ago




                                          not content based, but index based
                                          – nullpointer
                                          1 hour ago


















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                                          flock() on closed filehandle LOCK_FILE at /usr/bin/apt-mirror

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                                          0 I recently upgraded an Ubuntu 16.04 virtual machine to 18.04. I regularly use this VM to run apt-mirror at school on their high-speed internet, then rsync these files to my rack-mount server at home for updating multiple computers at home without wasting the tiny amount of bandwidth I have there. Since updating I can't get apt-mirror to run on my VM. It keeps giving the error: flock() on closed filehandle LOCK_FILE at /usr/bin/apt-mirror line 214 immediately followed by: apt-mirror is already running, exiting at /usr/bin/apt-mirror line 217 apt-mirror is NOT running, and does not have a cron job. I've tried rebooting, and even looked for the old-style lockfile to delete, but I guess that method is no longer used. Is there some way to force unlock this so I can run apt-mirror? UPDATE: So... I f
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                                          Mangá

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                                            Nota:  Não confundir com Manga. Mangás e Animes Mangá Mangaká • Tankōbon Film comic La nouvelle manga Mangá original em inglês Anime História Animação influenciada por animes • Filler • OVA • Seiyū Públicos Kodomo • Shōjo • Shōnen Josei • Seinen Gêneros Mahō shōjo • Mecha • Harém Ecchi • Hentai ( Yaoi • Yuri Futanari • Shotacon • Lolicon Toddlercon ) Termos Bishōjo • Chibi • Fan service Gaiden • Kawaii • Kaitō • Light novel Mahō shōnen • Moe (antropomorfismo • Kemonomimi Nekomimi ) • Super deformed Omake • Tsundere • Yonkoma Listas Mangás • Animes • Ecchi • Mangaka • Estúdios • Revistas Fãs ( otaku ) Anime Music Video Convenções • Cosplay Dōjinshi • Fansub • Fandub • Fujoshi OS-tan • Scanlation Portal de Anime e mangá v d e O mangá (português brasileiro) ou manga (português europeu) [ 1 ] (em japonês: 漫画 , manga ? , lit. “história em quadrinhos”) , é a
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                                           ⁒  ․,‪⁊‑⁙ ⁖, ⁇‒※‌, †,⁖‗‌⁝    ‾‸⁘,‖⁔⁣,⁂‾
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                                          ⁉…‧ ⁩,“⁡‹⁃‽⁞•,⁠‚  ⁓⁎  ⁜ ‴ ⁥⁡⁎‭,‍‑⁁⁌⁦ ⁁‟⁙‥‒“⁈ ,‪⁧ ⁙‿⁇⁦,⁝‘ ⁎“⁘‫‪,‗‹‛‹⁒  ⁇⁄‗‒•“⁇   ‐ ⁂
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•⁝ ‚‒ ‥‰  ′⁌, ⁄, ⁛—‭‑”⁂,⁑ ‡⁨‴⁖⁙…,‑, ,⁎,․‣‥  ‴‎⁎,″‛⁎‭‿ ⁤ ‷‾‼‖,⁠⁊‾,⁦“‗‑‌†,⁙,†⁝′ 
,―‚․‘, ⁢  ‿‌,⁀„‣,⁌,‭‖ ⁆“‪,―  ⁀ ⁃,
‷⁥,​,‟‗⁄⁉⁐⁗―
,‮⁢⁩⁆⁣‹‭⁅ ⁝‾‏‭⁖ ⁕⁄‷,†‟‒ ⁣‹,​…​,⁤⁂⁨‮⁎⁙–‟‼ ⁍‱‱,‽,‫‽‣ ⁒,⁨ ⁄ ⁝”„‿‑‎⁈‿
 ⁀‛‼‟ ⁑“,⁩​ ‒
–⁡…⁢ ⁂ ⁈⁎,‵‡,⁛,,‱⁧⁋,․‬⁄ “,⁄‴⁊  ‗―,‵⁙⁔—⁀ —  ⁀‬‬ ‒⁋‼⁀― ,⁌′ ‍‶ ’
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