Calculate area with read and function











up vote
1
down vote

favorite












I intend to calculate area of a circle.



#! /usr/local/bin/bash
read -p "Enter a radius: "
area () {
a=$(( 3 * $REPLY * 2 ))
return $a
}
echo $(area)


Run but return nothing



$ bash area.sh
Enter a radius: 9


Then to refactor it by quoting



#! /usr/local/bin/bash
read -p "Enter a radius: " radius
area (radius) {
a=$(( 3 * $radius * 2 ))
return "$a"
}
echo "$(area)"


It still not work properly.



bash area.sh
Enter a radius: 9
area.sh: line 3: syntax error near unexpected token `radius'
area.sh: line 3: `area (radius) {'


How to do such a calculation?










share|improve this question




















  • 1




    The script you're running and the script you have shown as seem to be different. (There is no area (radius) { in your script.) Double check whatever it is you're running. Also, return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.
    – muru
    Apr 10 at 2:18












  • ty. I modified the question.
    – JawSaw
    Apr 10 at 2:26















up vote
1
down vote

favorite












I intend to calculate area of a circle.



#! /usr/local/bin/bash
read -p "Enter a radius: "
area () {
a=$(( 3 * $REPLY * 2 ))
return $a
}
echo $(area)


Run but return nothing



$ bash area.sh
Enter a radius: 9


Then to refactor it by quoting



#! /usr/local/bin/bash
read -p "Enter a radius: " radius
area (radius) {
a=$(( 3 * $radius * 2 ))
return "$a"
}
echo "$(area)"


It still not work properly.



bash area.sh
Enter a radius: 9
area.sh: line 3: syntax error near unexpected token `radius'
area.sh: line 3: `area (radius) {'


How to do such a calculation?










share|improve this question




















  • 1




    The script you're running and the script you have shown as seem to be different. (There is no area (radius) { in your script.) Double check whatever it is you're running. Also, return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.
    – muru
    Apr 10 at 2:18












  • ty. I modified the question.
    – JawSaw
    Apr 10 at 2:26













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I intend to calculate area of a circle.



#! /usr/local/bin/bash
read -p "Enter a radius: "
area () {
a=$(( 3 * $REPLY * 2 ))
return $a
}
echo $(area)


Run but return nothing



$ bash area.sh
Enter a radius: 9


Then to refactor it by quoting



#! /usr/local/bin/bash
read -p "Enter a radius: " radius
area (radius) {
a=$(( 3 * $radius * 2 ))
return "$a"
}
echo "$(area)"


It still not work properly.



bash area.sh
Enter a radius: 9
area.sh: line 3: syntax error near unexpected token `radius'
area.sh: line 3: `area (radius) {'


How to do such a calculation?










share|improve this question















I intend to calculate area of a circle.



#! /usr/local/bin/bash
read -p "Enter a radius: "
area () {
a=$(( 3 * $REPLY * 2 ))
return $a
}
echo $(area)


Run but return nothing



$ bash area.sh
Enter a radius: 9


Then to refactor it by quoting



#! /usr/local/bin/bash
read -p "Enter a radius: " radius
area (radius) {
a=$(( 3 * $radius * 2 ))
return "$a"
}
echo "$(area)"


It still not work properly.



bash area.sh
Enter a radius: 9
area.sh: line 3: syntax error near unexpected token `radius'
area.sh: line 3: `area (radius) {'


How to do such a calculation?







bash






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 10 at 2:25

























asked Apr 10 at 2:02









JawSaw

425312




425312








  • 1




    The script you're running and the script you have shown as seem to be different. (There is no area (radius) { in your script.) Double check whatever it is you're running. Also, return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.
    – muru
    Apr 10 at 2:18












  • ty. I modified the question.
    – JawSaw
    Apr 10 at 2:26














  • 1




    The script you're running and the script you have shown as seem to be different. (There is no area (radius) { in your script.) Double check whatever it is you're running. Also, return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.
    – muru
    Apr 10 at 2:18












  • ty. I modified the question.
    – JawSaw
    Apr 10 at 2:26








1




1




The script you're running and the script you have shown as seem to be different. (There is no area (radius) { in your script.) Double check whatever it is you're running. Also, return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.
– muru
Apr 10 at 2:18






The script you're running and the script you have shown as seem to be different. (There is no area (radius) { in your script.) Double check whatever it is you're running. Also, return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.
– muru
Apr 10 at 2:18














ty. I modified the question.
– JawSaw
Apr 10 at 2:26




ty. I modified the question.
– JawSaw
Apr 10 at 2:26










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










Functions in bash do not have named parameters. You cannot do:



area (foo) { ...
function area (foo) { ...


You can do:



area () {
local radius a # set a local variable that does not leak outside the function
radius=$1 # Save the first parameter to local variable
a=$(( 3 * radius * 2 ))
echo "$a"
}


And then:



echo "$(area "$REPLY")"  # use $REPLY as the first argument


Since return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.



Also, while bash does not support floating-point arithmetic, it does support exponentiation:



$ bash -c 'echo $((3 * 3 ** 2))'
27





share|improve this answer






























    up vote
    5
    down vote













    This is a quick script taking the input of the radius then feeding it to the function of area() then echoing out the return value. This works with bc or binary calculator installed.



    #!/bin/bash
    function area(){
    circ=$(echo "3.14 * $1^2" | bc)
    }

    #Read in radius
    read -p "Enter a radius: "

    #Send REPLY to function
    area $REPLY

    #Print output
    echo "Area of a circle is $circ"


    Example:



    terrance@terrance-ubuntu:~$ ./circ.bsh 
    Enter a radius: 6
    Area of a circle is 113.04


    Or I have expanded on the script a little to show more of reading in a variable either from the command line or from the script itself:



    #!/bin/bash
    function area(){
    areacirc=$(printf "3.14 * $1^2n" | bc)
    diamcirc=$(printf "2 * $1n" | bc)
    circcirc=$(printf "2 * 3.14 * $1n" | bc)
    }

    #Read in radius from command line or from read
    if [[ $1 == "" ]]; then
    read -p "Enter a radius: "
    else
    printf "Radius of a cirle is $1n"
    REPLY=$1
    fi

    #Send REPLY to area function
    area $REPLY

    #Print output from variables set by area function
    printf "Diameter of a circle is $diamcircn"
    printf "Circumference of a circle is $circcircn"
    printf "Area of a circle is $areacircn"


    Example:



    terrance@terrance-ubuntu:~$ ./area.bsh 6
    Radius of a cirle is 6
    Diameter of a circle is 12
    Circumference of a circle is 37.68
    Area of a circle is 113.04


    or



    terrance@terrance-ubuntu:~$ ./area.bsh
    Enter a radius: 13
    Diameter of a circle is 26
    Circumference of a circle is 81.64
    Area of a circle is 530.66





    share|improve this answer























    • How to encapsulate the command into function area
      – JawSaw
      Apr 10 at 2:27











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    2 Answers
    2






    active

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    2 Answers
    2






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    Functions in bash do not have named parameters. You cannot do:



    area (foo) { ...
    function area (foo) { ...


    You can do:



    area () {
    local radius a # set a local variable that does not leak outside the function
    radius=$1 # Save the first parameter to local variable
    a=$(( 3 * radius * 2 ))
    echo "$a"
    }


    And then:



    echo "$(area "$REPLY")"  # use $REPLY as the first argument


    Since return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.



    Also, while bash does not support floating-point arithmetic, it does support exponentiation:



    $ bash -c 'echo $((3 * 3 ** 2))'
    27





    share|improve this answer



























      up vote
      3
      down vote



      accepted










      Functions in bash do not have named parameters. You cannot do:



      area (foo) { ...
      function area (foo) { ...


      You can do:



      area () {
      local radius a # set a local variable that does not leak outside the function
      radius=$1 # Save the first parameter to local variable
      a=$(( 3 * radius * 2 ))
      echo "$a"
      }


      And then:



      echo "$(area "$REPLY")"  # use $REPLY as the first argument


      Since return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.



      Also, while bash does not support floating-point arithmetic, it does support exponentiation:



      $ bash -c 'echo $((3 * 3 ** 2))'
      27





      share|improve this answer

























        up vote
        3
        down vote



        accepted







        up vote
        3
        down vote



        accepted






        Functions in bash do not have named parameters. You cannot do:



        area (foo) { ...
        function area (foo) { ...


        You can do:



        area () {
        local radius a # set a local variable that does not leak outside the function
        radius=$1 # Save the first parameter to local variable
        a=$(( 3 * radius * 2 ))
        echo "$a"
        }


        And then:



        echo "$(area "$REPLY")"  # use $REPLY as the first argument


        Since return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.



        Also, while bash does not support floating-point arithmetic, it does support exponentiation:



        $ bash -c 'echo $((3 * 3 ** 2))'
        27





        share|improve this answer














        Functions in bash do not have named parameters. You cannot do:



        area (foo) { ...
        function area (foo) { ...


        You can do:



        area () {
        local radius a # set a local variable that does not leak outside the function
        radius=$1 # Save the first parameter to local variable
        a=$(( 3 * radius * 2 ))
        echo "$a"
        }


        And then:



        echo "$(area "$REPLY")"  # use $REPLY as the first argument


        Since return sets the exit status of the function, whereas $(area) uses the output of the function. These are different.



        Also, while bash does not support floating-point arithmetic, it does support exponentiation:



        $ bash -c 'echo $((3 * 3 ** 2))'
        27






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Apr 10 at 2:36

























        answered Apr 10 at 2:30









        muru

        135k20289492




        135k20289492
























            up vote
            5
            down vote













            This is a quick script taking the input of the radius then feeding it to the function of area() then echoing out the return value. This works with bc or binary calculator installed.



            #!/bin/bash
            function area(){
            circ=$(echo "3.14 * $1^2" | bc)
            }

            #Read in radius
            read -p "Enter a radius: "

            #Send REPLY to function
            area $REPLY

            #Print output
            echo "Area of a circle is $circ"


            Example:



            terrance@terrance-ubuntu:~$ ./circ.bsh 
            Enter a radius: 6
            Area of a circle is 113.04


            Or I have expanded on the script a little to show more of reading in a variable either from the command line or from the script itself:



            #!/bin/bash
            function area(){
            areacirc=$(printf "3.14 * $1^2n" | bc)
            diamcirc=$(printf "2 * $1n" | bc)
            circcirc=$(printf "2 * 3.14 * $1n" | bc)
            }

            #Read in radius from command line or from read
            if [[ $1 == "" ]]; then
            read -p "Enter a radius: "
            else
            printf "Radius of a cirle is $1n"
            REPLY=$1
            fi

            #Send REPLY to area function
            area $REPLY

            #Print output from variables set by area function
            printf "Diameter of a circle is $diamcircn"
            printf "Circumference of a circle is $circcircn"
            printf "Area of a circle is $areacircn"


            Example:



            terrance@terrance-ubuntu:~$ ./area.bsh 6
            Radius of a cirle is 6
            Diameter of a circle is 12
            Circumference of a circle is 37.68
            Area of a circle is 113.04


            or



            terrance@terrance-ubuntu:~$ ./area.bsh
            Enter a radius: 13
            Diameter of a circle is 26
            Circumference of a circle is 81.64
            Area of a circle is 530.66





            share|improve this answer























            • How to encapsulate the command into function area
              – JawSaw
              Apr 10 at 2:27















            up vote
            5
            down vote













            This is a quick script taking the input of the radius then feeding it to the function of area() then echoing out the return value. This works with bc or binary calculator installed.



            #!/bin/bash
            function area(){
            circ=$(echo "3.14 * $1^2" | bc)
            }

            #Read in radius
            read -p "Enter a radius: "

            #Send REPLY to function
            area $REPLY

            #Print output
            echo "Area of a circle is $circ"


            Example:



            terrance@terrance-ubuntu:~$ ./circ.bsh 
            Enter a radius: 6
            Area of a circle is 113.04


            Or I have expanded on the script a little to show more of reading in a variable either from the command line or from the script itself:



            #!/bin/bash
            function area(){
            areacirc=$(printf "3.14 * $1^2n" | bc)
            diamcirc=$(printf "2 * $1n" | bc)
            circcirc=$(printf "2 * 3.14 * $1n" | bc)
            }

            #Read in radius from command line or from read
            if [[ $1 == "" ]]; then
            read -p "Enter a radius: "
            else
            printf "Radius of a cirle is $1n"
            REPLY=$1
            fi

            #Send REPLY to area function
            area $REPLY

            #Print output from variables set by area function
            printf "Diameter of a circle is $diamcircn"
            printf "Circumference of a circle is $circcircn"
            printf "Area of a circle is $areacircn"


            Example:



            terrance@terrance-ubuntu:~$ ./area.bsh 6
            Radius of a cirle is 6
            Diameter of a circle is 12
            Circumference of a circle is 37.68
            Area of a circle is 113.04


            or



            terrance@terrance-ubuntu:~$ ./area.bsh
            Enter a radius: 13
            Diameter of a circle is 26
            Circumference of a circle is 81.64
            Area of a circle is 530.66





            share|improve this answer























            • How to encapsulate the command into function area
              – JawSaw
              Apr 10 at 2:27













            up vote
            5
            down vote










            up vote
            5
            down vote









            This is a quick script taking the input of the radius then feeding it to the function of area() then echoing out the return value. This works with bc or binary calculator installed.



            #!/bin/bash
            function area(){
            circ=$(echo "3.14 * $1^2" | bc)
            }

            #Read in radius
            read -p "Enter a radius: "

            #Send REPLY to function
            area $REPLY

            #Print output
            echo "Area of a circle is $circ"


            Example:



            terrance@terrance-ubuntu:~$ ./circ.bsh 
            Enter a radius: 6
            Area of a circle is 113.04


            Or I have expanded on the script a little to show more of reading in a variable either from the command line or from the script itself:



            #!/bin/bash
            function area(){
            areacirc=$(printf "3.14 * $1^2n" | bc)
            diamcirc=$(printf "2 * $1n" | bc)
            circcirc=$(printf "2 * 3.14 * $1n" | bc)
            }

            #Read in radius from command line or from read
            if [[ $1 == "" ]]; then
            read -p "Enter a radius: "
            else
            printf "Radius of a cirle is $1n"
            REPLY=$1
            fi

            #Send REPLY to area function
            area $REPLY

            #Print output from variables set by area function
            printf "Diameter of a circle is $diamcircn"
            printf "Circumference of a circle is $circcircn"
            printf "Area of a circle is $areacircn"


            Example:



            terrance@terrance-ubuntu:~$ ./area.bsh 6
            Radius of a cirle is 6
            Diameter of a circle is 12
            Circumference of a circle is 37.68
            Area of a circle is 113.04


            or



            terrance@terrance-ubuntu:~$ ./area.bsh
            Enter a radius: 13
            Diameter of a circle is 26
            Circumference of a circle is 81.64
            Area of a circle is 530.66





            share|improve this answer














            This is a quick script taking the input of the radius then feeding it to the function of area() then echoing out the return value. This works with bc or binary calculator installed.



            #!/bin/bash
            function area(){
            circ=$(echo "3.14 * $1^2" | bc)
            }

            #Read in radius
            read -p "Enter a radius: "

            #Send REPLY to function
            area $REPLY

            #Print output
            echo "Area of a circle is $circ"


            Example:



            terrance@terrance-ubuntu:~$ ./circ.bsh 
            Enter a radius: 6
            Area of a circle is 113.04


            Or I have expanded on the script a little to show more of reading in a variable either from the command line or from the script itself:



            #!/bin/bash
            function area(){
            areacirc=$(printf "3.14 * $1^2n" | bc)
            diamcirc=$(printf "2 * $1n" | bc)
            circcirc=$(printf "2 * 3.14 * $1n" | bc)
            }

            #Read in radius from command line or from read
            if [[ $1 == "" ]]; then
            read -p "Enter a radius: "
            else
            printf "Radius of a cirle is $1n"
            REPLY=$1
            fi

            #Send REPLY to area function
            area $REPLY

            #Print output from variables set by area function
            printf "Diameter of a circle is $diamcircn"
            printf "Circumference of a circle is $circcircn"
            printf "Area of a circle is $areacircn"


            Example:



            terrance@terrance-ubuntu:~$ ./area.bsh 6
            Radius of a cirle is 6
            Diameter of a circle is 12
            Circumference of a circle is 37.68
            Area of a circle is 113.04


            or



            terrance@terrance-ubuntu:~$ ./area.bsh
            Enter a radius: 13
            Diameter of a circle is 26
            Circumference of a circle is 81.64
            Area of a circle is 530.66






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Dec 5 at 6:49

























            answered Apr 10 at 2:14









            Terrance

            18.6k34092




            18.6k34092












            • How to encapsulate the command into function area
              – JawSaw
              Apr 10 at 2:27


















            • How to encapsulate the command into function area
              – JawSaw
              Apr 10 at 2:27
















            How to encapsulate the command into function area
            – JawSaw
            Apr 10 at 2:27




            How to encapsulate the command into function area
            – JawSaw
            Apr 10 at 2:27


















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