Integral of the inverse to $f(x)$











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The formula $$f(x)=sin(x)+frac{2x}{pi}$$ defines the function$ f:[0, frac{pi}{2}] rightarrow [0, 2] $.



How should you go about finding: $int_{0}^{2}f^{-1}(y)dy$?










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    up vote
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    down vote

    favorite












    The formula $$f(x)=sin(x)+frac{2x}{pi}$$ defines the function$ f:[0, frac{pi}{2}] rightarrow [0, 2] $.



    How should you go about finding: $int_{0}^{2}f^{-1}(y)dy$?










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      The formula $$f(x)=sin(x)+frac{2x}{pi}$$ defines the function$ f:[0, frac{pi}{2}] rightarrow [0, 2] $.



      How should you go about finding: $int_{0}^{2}f^{-1}(y)dy$?










      share|cite|improve this question















      The formula $$f(x)=sin(x)+frac{2x}{pi}$$ defines the function$ f:[0, frac{pi}{2}] rightarrow [0, 2] $.



      How should you go about finding: $int_{0}^{2}f^{-1}(y)dy$?







      calculus integration inverse-function






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      edited yesterday









      TheSimpliFire

      11.6k62256




      11.6k62256










      asked yesterday









      Curl

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      6012






















          3 Answers
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          Hint:
          First use substitution $y=f(x)$
          $$int_{0}^{2}f^{-1}(y)dy=int_{f^{-1}(0)}^{f^{-1}(2)}xf'(x) dx$$
          and then apply integration by parts.






          share|cite|improve this answer





















          • It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
            – Acccumulation
            yesterday










          • Yeah, A good point!
            – Nosrati
            yesterday


















          up vote
          6
          down vote













          Hint: Think geometrically. That integral represents some area in the plane. You can easily calculate the area of a certain rectangle containing that area, and with a little effort the remaining part of the rectangle.






          share|cite|improve this answer






























            up vote
            0
            down vote













            Use substitution $y=f(x)$ and integrate by parts.






            share|cite|improve this answer








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            • This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
              – hardmath
              yesterday











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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            6
            down vote













            Hint:
            First use substitution $y=f(x)$
            $$int_{0}^{2}f^{-1}(y)dy=int_{f^{-1}(0)}^{f^{-1}(2)}xf'(x) dx$$
            and then apply integration by parts.






            share|cite|improve this answer





















            • It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
              – Acccumulation
              yesterday










            • Yeah, A good point!
              – Nosrati
              yesterday















            up vote
            6
            down vote













            Hint:
            First use substitution $y=f(x)$
            $$int_{0}^{2}f^{-1}(y)dy=int_{f^{-1}(0)}^{f^{-1}(2)}xf'(x) dx$$
            and then apply integration by parts.






            share|cite|improve this answer





















            • It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
              – Acccumulation
              yesterday










            • Yeah, A good point!
              – Nosrati
              yesterday













            up vote
            6
            down vote










            up vote
            6
            down vote









            Hint:
            First use substitution $y=f(x)$
            $$int_{0}^{2}f^{-1}(y)dy=int_{f^{-1}(0)}^{f^{-1}(2)}xf'(x) dx$$
            and then apply integration by parts.






            share|cite|improve this answer












            Hint:
            First use substitution $y=f(x)$
            $$int_{0}^{2}f^{-1}(y)dy=int_{f^{-1}(0)}^{f^{-1}(2)}xf'(x) dx$$
            and then apply integration by parts.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered yesterday









            Nosrati

            25.8k62252




            25.8k62252












            • It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
              – Acccumulation
              yesterday










            • Yeah, A good point!
              – Nosrati
              yesterday


















            • It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
              – Acccumulation
              yesterday










            • Yeah, A good point!
              – Nosrati
              yesterday
















            It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
            – Acccumulation
            yesterday




            It's important to note that one should check whether the function is monotonic over the interval before applying this procedure.
            – Acccumulation
            yesterday












            Yeah, A good point!
            – Nosrati
            yesterday




            Yeah, A good point!
            – Nosrati
            yesterday










            up vote
            6
            down vote













            Hint: Think geometrically. That integral represents some area in the plane. You can easily calculate the area of a certain rectangle containing that area, and with a little effort the remaining part of the rectangle.






            share|cite|improve this answer



























              up vote
              6
              down vote













              Hint: Think geometrically. That integral represents some area in the plane. You can easily calculate the area of a certain rectangle containing that area, and with a little effort the remaining part of the rectangle.






              share|cite|improve this answer

























                up vote
                6
                down vote










                up vote
                6
                down vote









                Hint: Think geometrically. That integral represents some area in the plane. You can easily calculate the area of a certain rectangle containing that area, and with a little effort the remaining part of the rectangle.






                share|cite|improve this answer














                Hint: Think geometrically. That integral represents some area in the plane. You can easily calculate the area of a certain rectangle containing that area, and with a little effort the remaining part of the rectangle.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited yesterday

























                answered yesterday









                Arthur

                108k7103186




                108k7103186






















                    up vote
                    0
                    down vote













                    Use substitution $y=f(x)$ and integrate by parts.






                    share|cite|improve this answer








                    New contributor




                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.


















                    • This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
                      – hardmath
                      yesterday















                    up vote
                    0
                    down vote













                    Use substitution $y=f(x)$ and integrate by parts.






                    share|cite|improve this answer








                    New contributor




                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.


















                    • This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
                      – hardmath
                      yesterday













                    up vote
                    0
                    down vote










                    up vote
                    0
                    down vote









                    Use substitution $y=f(x)$ and integrate by parts.






                    share|cite|improve this answer








                    New contributor




                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.









                    Use substitution $y=f(x)$ and integrate by parts.







                    share|cite|improve this answer








                    New contributor




                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.









                    share|cite|improve this answer



                    share|cite|improve this answer






                    New contributor




                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.









                    answered yesterday









                    Loara

                    1




                    1




                    New contributor




                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.





                    New contributor





                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    Loara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.












                    • This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
                      – hardmath
                      yesterday


















                    • This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
                      – hardmath
                      yesterday
















                    This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
                    – hardmath
                    yesterday




                    This would be more useful if you showed the steps to carry out this program. Details like the change in limits of integration are important here (for the definite integral).
                    – hardmath
                    yesterday


















                     

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