Add current date/time to ps output
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I want to log my cpu and memory usage. There are loads of posts out there giving different options using ps, top, python, etc. I really like the ps way of doing it. In my case, I call:
ps -o user -o pid -o pmem -o pcpu -u dxd9163
Which gives a nice table:
Because I'm logging this data (every ten minutes), I would like to add the date/time information to each row of the table as with:
date +%Y/%m/%d/%H:%M
I don't want the process time, how long it was running or when it was started, I just want the time the snapshot was taken. So in the figure above, a new field, time would be there with all the same info for each snapshot.
It seems the ps function has a deprecated option that may have worked before but doesn't anymore (utime).
Any idea how to do this? It's probably easy but I'm new to Linux.
My final goal is to log every 10 minutes for as long at it takes into a usage.txt file ram and cpu usage for my user.
log ps
asked Dec 6 at 14:28
Bastien
1105
add a comment |
up vote
1
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I want to log my cpu and memory usage. There are loads of posts out there giving different options using ps, top, python, etc. I really like the ps way of doing it. In my case, I call:
ps -o user -o pid -o pmem -o pcpu -u dxd9163
Which gives a nice table:
Because I'm logging this data (every ten minutes), I would like to add the date/time information to each row of the table as with:
date +%Y/%m/%d/%H:%M
I don't want the process time, how long it was running or when it was started, I just want the time the snapshot was taken. So in the figure above, a new field, time would be there with all the same info for each snapshot.
It seems the ps function has a deprecated option that may have worked before but doesn't anymore (utime).
Any idea how to do this? It's probably easy but I'm new to Linux.
My final goal is to log every 10 minutes for as long at it takes into a usage.txt file ram and cpu usage for my user.
log ps
asked Dec 6 at 14:28
Bastien
1105
Did you look atatop, it seems closer to the info you'll get by repeatedly callingps.
– pbhj
Dec 6 at 15:16
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I want to log my cpu and memory usage. There are loads of posts out there giving different options using ps, top, python, etc. I really like the ps way of doing it. In my case, I call:
ps -o user -o pid -o pmem -o pcpu -u dxd9163
Which gives a nice table:
Because I'm logging this data (every ten minutes), I would like to add the date/time information to each row of the table as with:
date +%Y/%m/%d/%H:%M
I don't want the process time, how long it was running or when it was started, I just want the time the snapshot was taken. So in the figure above, a new field, time would be there with all the same info for each snapshot.
It seems the ps function has a deprecated option that may have worked before but doesn't anymore (utime).
Any idea how to do this? It's probably easy but I'm new to Linux.
My final goal is to log every 10 minutes for as long at it takes into a usage.txt file ram and cpu usage for my user.
log ps
asked Dec 6 at 14:28
Bastien
1105
I want to log my cpu and memory usage. There are loads of posts out there giving different options using ps, top, python, etc. I really like the ps way of doing it. In my case, I call:
ps -o user -o pid -o pmem -o pcpu -u dxd9163
Which gives a nice table:
Because I'm logging this data (every ten minutes), I would like to add the date/time information to each row of the table as with:
date +%Y/%m/%d/%H:%M
I don't want the process time, how long it was running or when it was started, I just want the time the snapshot was taken. So in the figure above, a new field, time would be there with all the same info for each snapshot.
It seems the ps function has a deprecated option that may have worked before but doesn't anymore (utime).
Any idea how to do this? It's probably easy but I'm new to Linux.
My final goal is to log every 10 minutes for as long at it takes into a usage.txt file ram and cpu usage for my user.
log ps
log ps
asked Dec 6 at 14:28
Bastien
1105
asked Dec 6 at 14:28
Bastien
1105
asked Dec 6 at 14:28
Bastien
1105
asked Dec 6 at 14:28
Bastien
1105
asked Dec 6 at 14:28
Bastien
1105
1105
Did you look atatop, it seems closer to the info you'll get by repeatedly callingps.
– pbhj
Dec 6 at 15:16
add a comment |
Did you look atatop, it seems closer to the info you'll get by repeatedly callingps.
– pbhj
Dec 6 at 15:16
Did you look at
atop, it seems closer to the info you'll get by repeatedly calling ps.– pbhj
Dec 6 at 15:16
Did you look at
atop, it seems closer to the info you'll get by repeatedly calling ps.– pbhj
Dec 6 at 15:16
add a comment |
1 Answer
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One trick is to replace each "start of line"
with "start of line, timestamp ":
ps -o user -o pid -o pmem -o pcpu -u dxd9163 | sed "s#^#$(date +%Y/%m/%d/%H:%M) #"
Usually sed's substitute operator uses a slash as separator (s/…/…/) but since
the timestamp already contains slashes, this won't work. I thus used a different
separator (s#…#…#).
answered Dec 6 at 14:38
PerlDuck
5,14911231
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
One trick is to replace each "start of line"
with "start of line, timestamp ":
ps -o user -o pid -o pmem -o pcpu -u dxd9163 | sed "s#^#$(date +%Y/%m/%d/%H:%M) #"
Usually sed's substitute operator uses a slash as separator (s/…/…/) but since
the timestamp already contains slashes, this won't work. I thus used a different
separator (s#…#…#).
answered Dec 6 at 14:38
PerlDuck
5,14911231
add a comment |
up vote
2
down vote
accepted
One trick is to replace each "start of line"
with "start of line, timestamp ":
ps -o user -o pid -o pmem -o pcpu -u dxd9163 | sed "s#^#$(date +%Y/%m/%d/%H:%M) #"
Usually sed's substitute operator uses a slash as separator (s/…/…/) but since
the timestamp already contains slashes, this won't work. I thus used a different
separator (s#…#…#).
answered Dec 6 at 14:38
PerlDuck
5,14911231
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
One trick is to replace each "start of line"
with "start of line, timestamp ":
ps -o user -o pid -o pmem -o pcpu -u dxd9163 | sed "s#^#$(date +%Y/%m/%d/%H:%M) #"
Usually sed's substitute operator uses a slash as separator (s/…/…/) but since
the timestamp already contains slashes, this won't work. I thus used a different
separator (s#…#…#).
answered Dec 6 at 14:38
PerlDuck
5,14911231
One trick is to replace each "start of line"
with "start of line, timestamp ":
ps -o user -o pid -o pmem -o pcpu -u dxd9163 | sed "s#^#$(date +%Y/%m/%d/%H:%M) #"
Usually sed's substitute operator uses a slash as separator (s/…/…/) but since
the timestamp already contains slashes, this won't work. I thus used a different
separator (s#…#…#).
answered Dec 6 at 14:38
PerlDuck
5,14911231
answered Dec 6 at 14:38
PerlDuck
5,14911231
answered Dec 6 at 14:38
PerlDuck
5,14911231
answered Dec 6 at 14:38
PerlDuck
5,14911231
5,14911231
add a comment |
add a comment |
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Did you look at
atop, it seems closer to the info you'll get by repeatedly callingps.– pbhj
Dec 6 at 15:16