How to combine similar characters in a list?












7















I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python







share|improve this question









New contributor




Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

























    7















    I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



    test = 'hello###_world###test#test123##'
    
splitter = re.split("(#)", test)
    
splitter = filter(None, splitter)


    Which returns this in the splitter variable:



    ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


    I'm trying to combine the hashes so the list turns into this:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    Thanks for any help!






    python







    share|improve this question









    New contributor




    Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      7












      7








      7








      I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



      test = 'hello###_world###test#test123##'
      
splitter = re.split("(#)", test)
      
splitter = filter(None, splitter)


      Which returns this in the splitter variable:



      ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


      I'm trying to combine the hashes so the list turns into this:



      ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


      Thanks for any help!






      python







      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



      test = 'hello###_world###test#test123##'
      
splitter = re.split("(#)", test)
      
splitter = filter(None, splitter)


      Which returns this in the splitter variable:



      ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


      I'm trying to combine the hashes so the list turns into this:



      ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


      Thanks for any help!






      python




      python






      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 50 mins ago









      Ajax1234

      41.4k42853




      41.4k42853






      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 50 mins ago









      GregGreg

      362




      362




      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.
























          3 Answers
          3






          active

          oldest

          votes


















          5














          Try:



          splitter = re.split("(#+)", test)





          share|improve this answer



















          • 1





            It gives an empty string at the end.

            – AkshayNevrekar
            27 mins ago






          • 2





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            24 mins ago











          • This works for me. Thanks for the help!

            – Greg
            18 mins ago



















          1














          Add + at the end of the regular expression and filtering None values will do the trick



          >>> import re
          
>>> test = 'hello###_world###test#test123##'
          
>>> splitter = re.split("(#+)", test)
          
>>> splitter
          
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
          
>>> splitter = list(filter(None, splitter))
          
>>> splitter
          
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
          
>>>





          share|improve this answer































            1














            You can use itertools.groupby:



            import itertools
            
test = 'hello###_world###test#test123##'
            
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


            You can also use re.findall:



            import re
            
result = re.findall('#+|[^#]+', test)


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





            share|improve this answer


























            • This one also does the job. Thanks for the help!

              – Greg
              16 mins ago











            Your Answer






            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "1"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });






            Greg is a new contributor. Be nice, and check out our Code of Conduct.










            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54603094%2fhow-to-combine-similar-characters-in-a-list%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            5














            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer



















            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              27 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              24 mins ago











            • This works for me. Thanks for the help!

              – Greg
              18 mins ago
















            5














            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer



















            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              27 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              24 mins ago











            • This works for me. Thanks for the help!

              – Greg
              18 mins ago














            5












            5








            5







            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer













            Try:



            splitter = re.split("(#+)", test)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 32 mins ago









            mingganzmingganz

            1986




            1986








            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              27 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              24 mins ago











            • This works for me. Thanks for the help!

              – Greg
              18 mins ago














            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              27 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              24 mins ago











            • This works for me. Thanks for the help!

              – Greg
              18 mins ago








            1




            1





            It gives an empty string at the end.

            – AkshayNevrekar
            27 mins ago





            It gives an empty string at the end.

            – AkshayNevrekar
            27 mins ago




            2




            2





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            24 mins ago





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            24 mins ago













            This works for me. Thanks for the help!

            – Greg
            18 mins ago





            This works for me. Thanks for the help!

            – Greg
            18 mins ago













            1














            Add + at the end of the regular expression and filtering None values will do the trick



            >>> import re
            
>>> test = 'hello###_world###test#test123##'
            
>>> splitter = re.split("(#+)", test)
            
>>> splitter
            
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
            
>>> splitter = list(filter(None, splitter))
            
>>> splitter
            
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
            
>>>





            share|improve this answer




























              1














              Add + at the end of the regular expression and filtering None values will do the trick



              >>> import re
              
>>> test = 'hello###_world###test#test123##'
              
>>> splitter = re.split("(#+)", test)
              
>>> splitter
              
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
              
>>> splitter = list(filter(None, splitter))
              
>>> splitter
              
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
              
>>>





              share|improve this answer


























                1












                1








                1







                Add + at the end of the regular expression and filtering None values will do the trick



                >>> import re
                
>>> test = 'hello###_world###test#test123##'
                
>>> splitter = re.split("(#+)", test)
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
                
>>> splitter = list(filter(None, splitter))
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
                
>>>





                share|improve this answer













                Add + at the end of the regular expression and filtering None values will do the trick



                >>> import re
                
>>> test = 'hello###_world###test#test123##'
                
>>> splitter = re.split("(#+)", test)
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
                
>>> splitter = list(filter(None, splitter))
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
                
>>>






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 21 mins ago









                Bodhi94Bodhi94

                901520




                901520























                    1














                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





                    share|improve this answer


























                    • This one also does the job. Thanks for the help!

                      – Greg
                      16 mins ago
















                    1














                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





                    share|improve this answer


























                    • This one also does the job. Thanks for the help!

                      – Greg
                      16 mins ago














                    1












                    1








                    1







                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





                    share|improve this answer















                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 13 mins ago

























                    answered 48 mins ago









                    Ajax1234Ajax1234

                    41.4k42853




                    41.4k42853













                    • This one also does the job. Thanks for the help!

                      – Greg
                      16 mins ago



















                    • This one also does the job. Thanks for the help!

                      – Greg
                      16 mins ago

















                    This one also does the job. Thanks for the help!

                    – Greg
                    16 mins ago





                    This one also does the job. Thanks for the help!

                    – Greg
                    16 mins ago










                    Greg is a new contributor. Be nice, and check out our Code of Conduct.










                    draft saved

                    draft discarded


















                    Greg is a new contributor. Be nice, and check out our Code of Conduct.













                    Greg is a new contributor. Be nice, and check out our Code of Conduct.












                    Greg is a new contributor. Be nice, and check out our Code of Conduct.
















                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid …



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54603094%2fhow-to-combine-similar-characters-in-a-list%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    -

                    Popular posts from this blog

                    flock() on closed filehandle LOCK_FILE at /usr/bin/apt-mirror

                    Image
                    0 I recently upgraded an Ubuntu 16.04 virtual machine to 18.04. I regularly use this VM to run apt-mirror at school on their high-speed internet, then rsync these files to my rack-mount server at home for updating multiple computers at home without wasting the tiny amount of bandwidth I have there. Since updating I can't get apt-mirror to run on my VM. It keeps giving the error: flock() on closed filehandle LOCK_FILE at /usr/bin/apt-mirror line 214 immediately followed by: apt-mirror is already running, exiting at /usr/bin/apt-mirror line 217 apt-mirror is NOT running, and does not have a cron job. I've tried rebooting, and even looked for the old-style lockfile to delete, but I guess that method is no longer used. Is there some way to force unlock this so I can run apt-mirror? UPDATE: So... I f
                    Read more

                    Mangá

                    Image
                      Nota:  Não confundir com Manga. Mangás e Animes Mangá Mangaká • Tankōbon Film comic La nouvelle manga Mangá original em inglês Anime História Animação influenciada por animes • Filler • OVA • Seiyū Públicos Kodomo • Shōjo • Shōnen Josei • Seinen Gêneros Mahō shōjo • Mecha • Harém Ecchi • Hentai ( Yaoi • Yuri Futanari • Shotacon • Lolicon Toddlercon ) Termos Bishōjo • Chibi • Fan service Gaiden • Kawaii • Kaitō • Light novel Mahō shōnen • Moe (antropomorfismo • Kemonomimi Nekomimi ) • Super deformed Omake • Tsundere • Yonkoma Listas Mangás • Animes • Ecchi • Mangaka • Estúdios • Revistas Fãs ( otaku ) Anime Music Video Convenções • Cosplay Dōjinshi • Fansub • Fandub • Fujoshi OS-tan • Scanlation Portal de Anime e mangá v d e O mangá (português brasileiro) ou manga (português europeu) [ 1 ] (em japonês: 漫画 , manga ? , lit. “história em quadrinhos”) , é a
                    Read more

                     ⁒  ․,‪⁊‑⁙ ⁖, ⁇‒※‌, †,⁖‗‌⁝    ‾‸⁘,‖⁔⁣,⁂‾
”‑,‥–,‬ ,⁀‹⁋‴⁑ ‒ ,‴⁋”‼ ⁨,‷⁔„ ‰′,‐‚ ‥‡‎“‷⁃⁨⁅⁣,⁔
⁇‘⁔⁡⁏⁌⁡‿‶‏⁨ ⁣⁕⁖⁨⁩⁥‽⁀  ‴‬⁜‟ ⁃‣‧⁕‮ …‍⁨‴ ⁩,⁚⁖‫ ,‵ ⁀,‮⁝‣‣ ⁑  ⁂– ․, ‾‽ ‏⁁“⁗‸ ‾… ‹‡⁌⁎‸‘ ‡⁏⁌‪ ‵⁛ ‎⁨ ―⁦⁤⁄⁕

                    ⁉…‧ ⁩,“⁡‹⁃‽⁞•,⁠‚  ⁓⁎  ⁜ ‴ ⁥⁡⁎‭,‍‑⁁⁌⁦ ⁁‟⁙‥‒“⁈ ,‪⁧ ⁙‿⁇⁦,⁝‘ ⁎“⁘‫‪,‗‹‛‹⁒  ⁇⁄‗‒•“⁇   ‐ ⁂
‘‛, ‶⁦ ⁇ ​⁞‧ 
,⁏ …‹–⁗⁡⁘⁄ ‏‿‬‟″ ‏⁢⁦⁗⁚⁝‬⁢⁏,⁧″⁍′‖⁂※⁄‘– ‵⁡ ‭⁢⁚,⁅‧,‼‛⁗,⁡⁗“⁔⁃⁍‷⁏‗‱⁌‚  
•⁝ ‚‒ ‥‰  ′⁌, ⁄, ⁛—‭‑”⁂,⁑ ‡⁨‴⁖⁙…,‑, ,⁎,․‣‥  ‴‎⁎,″‛⁎‭‿ ⁤ ‷‾‼‖,⁠⁊‾,⁦“‗‑‌†,⁙,†⁝′ 
,―‚․‘, ⁢  ‿‌,⁀„‣,⁌,‭‖ ⁆“‪,―  ⁀ ⁃,
‷⁥,​,‟‗⁄⁉⁐⁗―
,‮⁢⁩⁆⁣‹‭⁅ ⁝‾‏‭⁖ ⁕⁄‷,†‟‒ ⁣‹,​…​,⁤⁂⁨‮⁎⁙–‟‼ ⁍‱‱,‽,‫‽‣ ⁒,⁨ ⁄ ⁝”„‿‑‎⁈‿
 ⁀‛‼‟ ⁑“,⁩​ ‒
–⁡…⁢ ⁂ ⁈⁎,‵‡,⁛,,‱⁧⁋,․‬⁄ “,⁄‴⁊  ‗―,‵⁙⁔—⁀ —  ⁀‬‬ ‒⁋‼⁀― ,⁌′ ‍‶ ’
                    Read more