Bdtyktl

Currently, I have an Automator script (Shell Script) which allows me to select multiple files and then create an individual zip file for each.

for f in "$@"

do

    zip -j "$f.zip" "$f"

done

What I'd like to do is the same thing, but to set a password for each individual file as well. Any help is appreciated!

Since you're using a shell script already, I was assuming you have access to bash's read command to read input to a variable, and a similar zip command to Debian's, so you could first store the password to the variable $pass with:

read -rsp "enter password" pass

Where the options mean (from man bash or help read):

-p prompt output the string PROMPT without a trailing newline before

          attempting to read

-r        do not allow backslashes to escape any characters

-s        do not echo input coming from a terminal

If you're using a more basic shell like /bin/sh / dash, it's read command does not have the -s option.

Then zip the files with:

zip -j -e -P "$pass" "$f.zip" "$f"

Note from zip's man page:

-P password
--password password

Use password to encrypt zipfile entries (if any). THIS IS INSECURE! Many multi-user operating systems provide ways for any user to see the current command line
of any other user; even on stand-alone systems there is always the threat of over-the-shoulder peeking. Storing the plaintext password as part of a command line in
an automated script is even worse. Whenever possible, use the non-echoing, inter‐
active prompt to enter passwords. (And where security is truly important, use
strong encryption such as Pretty Good Privacy instead of the relatively weak standard encryption provided by zipfile utilities.)

If you're on your own private secure computer with no one watching you, then I wouldn't worry about the potential insecurity of using a password like this.

Or you could omit the password storing & zip's -P option, and let zip prompt you for the password (twice) for each file.

All together, asking for a password once would look like this:

read -rsp "enter password" pass

# If you don't mind seeing the password, it would be safe to verify it:

echo -e "nUsing this password: $pass"

read -r -n1 -p "Press any key to continue..."

echo



for f in "$@"

do

    zip -j -e -P "$pass" "$f.zip" "$f"

done

Or read the password twice in a loop, until the two passwords match:

until [ "$pass" == "$pass2" ]; do

  read -r  -p "Enter password" pass

  read -r  -p "Enter password again" pass2

done



for f in "$@"

do

    zip -j -e -P "$pass" "$f.zip" "$f"

done

It appears there was a problem with the assumption that bash's read would work, your automator script isn't running in a regular terminal so you can't get to it's standard input. Here's some other ideas that might work.

Use bash to ask for more input

From https://discussions.apple.com/thread/7216062?answerId=28893979022#28893979022

Hiroto User level: Level 5 (7,463 points)

Sep 15, 2015 2:57 AM in response to Scotsman

Hello

Also you might do everything from shell. Something like this.

#!/bin/bash



ask () {

    osascript <<EOF - 2>/dev/null

tell application "SystemUIServer"

    activate

    text returned of (display dialog "$1" default answer "")

end tell

EOF

}



FROM=$( ask 'Enter value for --from' ) || exit

CREDITS=$( ask 'Enter value for --credits' ) || exit

CAPACITY=$( ask 'Enter value for --capacity' ) || exit

LY_PER=$( ask 'Enter value for --ly-per' ) || exit



trade.py run --from "$FROM" --credits "$CREDITS" --capacity "$CAPACITY" --ly-per "$LY_PER"

Regards,

H

• Once you've got the ask function working, you could only ask for the password (the above example looks like it asks for parameters to run python or something, all you'd need is the ask).

Run the whole script in a terminal

If you could have it run in a terminal then read should work.

Get automator to ask you for more input

Apparently this question on apple.stackexchange.com looks there's a way to have automator "Ask for text" to try getting another variable.