Initialize Map instance from Map entries
Say I have some map entries like so:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.of(a,b,c); // error here
I get this error:
Cannot resolve method
'of(java.util.Map.Entry,
java.util.Map.Entry,
java.util.Map.Entry)'
I just want to make a new Map from entries in a map, how can I do this?
Not the question is specifically about how to init a Map given Map.Entry instances.
java hashmap java-10
asked Feb 4 at 5:32
rakimrakim
403211
|
show 2 more comments
Say I have some map entries like so:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.of(a,b,c); // error here
I get this error:
Cannot resolve method
'of(java.util.Map.Entry,
java.util.Map.Entry,
java.util.Map.Entry)'
I just want to make a new Map from entries in a map, how can I do this?
Not the question is specifically about how to init a Map given Map.Entry instances.
java hashmap java-10
asked Feb 4 at 5:32
rakimrakim
403211
1
I think Map.ofEntries will suffice. Suprising that Map.of is not overloaded to support entries, but I guess I know why.
– rakim
Feb 4 at 5:34
1
@RobbyCornelissen it is Java version 11, the var keyword was introduced, please
– rakim
Feb 4 at 5:34
5
more preciselyjava-9
– Common Man
Feb 4 at 5:48
2
@CommonMan Thevarkeyword was introduced in Java 10 not Java 9.
– Mark Rotteveel
Feb 4 at 10:07
1
You're lucky you passed an odd number of arguments toMap.of. If you had passed an even number of arguments,mwould have been a map of entry to entry, specifically,Map<Map.Entry<String,Object>,Map.Entry<String,Object>>.
– Stuart Marks
Feb 13 at 20:05
|
show 2 more comments
Say I have some map entries like so:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.of(a,b,c); // error here
I get this error:
Cannot resolve method
'of(java.util.Map.Entry,
java.util.Map.Entry,
java.util.Map.Entry)'
I just want to make a new Map from entries in a map, how can I do this?
Not the question is specifically about how to init a Map given Map.Entry instances.
java hashmap java-10
asked Feb 4 at 5:32
rakimrakim
403211
Say I have some map entries like so:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.of(a,b,c); // error here
I get this error:
Cannot resolve method
'of(java.util.Map.Entry,
java.util.Map.Entry,
java.util.Map.Entry)'
I just want to make a new Map from entries in a map, how can I do this?
Not the question is specifically about how to init a Map given Map.Entry instances.
java hashmap java-10
java hashmap java-10
asked Feb 4 at 5:32
rakimrakim
403211
asked Feb 4 at 5:32
rakimrakim
403211
edited Feb 5 at 2:50
rakim
asked Feb 4 at 5:32
rakimrakim
403211
asked Feb 4 at 5:32
rakimrakim
403211
asked Feb 4 at 5:32
rakimrakim
403211
403211
1
I think Map.ofEntries will suffice. Suprising that Map.of is not overloaded to support entries, but I guess I know why.
– rakim
Feb 4 at 5:34
1
@RobbyCornelissen it is Java version 11, the var keyword was introduced, please
– rakim
Feb 4 at 5:34
5
more preciselyjava-9
– Common Man
Feb 4 at 5:48
2
@CommonMan Thevarkeyword was introduced in Java 10 not Java 9.
– Mark Rotteveel
Feb 4 at 10:07
1
You're lucky you passed an odd number of arguments toMap.of. If you had passed an even number of arguments,mwould have been a map of entry to entry, specifically,Map<Map.Entry<String,Object>,Map.Entry<String,Object>>.
– Stuart Marks
Feb 13 at 20:05
|
show 2 more comments
1
I think Map.ofEntries will suffice. Suprising that Map.of is not overloaded to support entries, but I guess I know why.
– rakim
Feb 4 at 5:34
1
@RobbyCornelissen it is Java version 11, the var keyword was introduced, please
– rakim
Feb 4 at 5:34
5
more preciselyjava-9
– Common Man
Feb 4 at 5:48
2
@CommonMan Thevarkeyword was introduced in Java 10 not Java 9.
– Mark Rotteveel
Feb 4 at 10:07
1
You're lucky you passed an odd number of arguments toMap.of. If you had passed an even number of arguments,mwould have been a map of entry to entry, specifically,Map<Map.Entry<String,Object>,Map.Entry<String,Object>>.
– Stuart Marks
Feb 13 at 20:05
1
1
I think Map.ofEntries will suffice. Suprising that Map.of is not overloaded to support entries, but I guess I know why.
– rakim
Feb 4 at 5:34
I think Map.ofEntries will suffice. Suprising that Map.of is not overloaded to support entries, but I guess I know why.
– rakim
Feb 4 at 5:34
1
1
@RobbyCornelissen it is Java version 11, the var keyword was introduced, please
– rakim
Feb 4 at 5:34
@RobbyCornelissen it is Java version 11, the var keyword was introduced, please
– rakim
Feb 4 at 5:34
5
5
more precisely
java-9– Common Man
Feb 4 at 5:48
more precisely
java-9– Common Man
Feb 4 at 5:48
2
2
@CommonMan The
var keyword was introduced in Java 10 not Java 9.– Mark Rotteveel
Feb 4 at 10:07
@CommonMan The
var keyword was introduced in Java 10 not Java 9.– Mark Rotteveel
Feb 4 at 10:07
1
1
You're lucky you passed an odd number of arguments to
Map.of. If you had passed an even number of arguments, m would have been a map of entry to entry, specifically, Map<Map.Entry<String,Object>,Map.Entry<String,Object>>.– Stuart Marks
Feb 13 at 20:05
You're lucky you passed an odd number of arguments to
Map.of. If you had passed an even number of arguments, m would have been a map of entry to entry, specifically, Map<Map.Entry<String,Object>,Map.Entry<String,Object>>.– Stuart Marks
Feb 13 at 20:05
|
show 2 more comments
5 Answers
5
active
oldest
votes
Replace
Map.of(a,b,c);
with
Map.ofEntries(a,b,c);
If you want to still use Map.of() then you shall paste keys and values explicitly.
Map.Entry()returns an immutableMap.Entrycontaining the given
key and value. These entries are suitable for populating Map instances
using theMap.ofEntries()method.
When to use Map.of() and when to use Map.ofEntries()
edited Feb 4 at 5:52
nullpointer
43.2k10101200
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
add a comment |
From jdk-9 you can use Map.of() to create Map with key value pairs
Map<String, Object> map = Map.of("a", new Object(), "b", new Object(), "c", new Object());
And also by using SimpleEntry
Map<String, Object> map = Map.ofEntries(
new AbstractMap.SimpleEntry<>("a", new Object()),
new AbstractMap.SimpleEntry<>("b", new Object()),
new AbstractMap.SimpleEntry<>("c", new Object()));
Or by using Map.ofEntries OP suggestion
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
add a comment |
The simple answer is:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c); // ! use Map.ofEntries not Map.of
And the type of Map.entry(key,val) is Map.Entry<K,V>, in case you were wondering.
answered Feb 4 at 5:39
rakimrakim
403211
add a comment |
Use this
var m = Map.ofEntries(a, b, c);
instead of
var m = Map.of(a,b,c);
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
add a comment |
To create a map from entries Use either:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c);
or:
var m = Map.ofEntries(
entry("a", new Object()),
entry("b", new Object()),
entry("c", new Object()));
You can also create the map without explicitly creating the entries:
var m = Map.of("a", new Object(),
"b", new Object(),
"c", new Object());
answered Feb 4 at 7:59
ETOETO
2,6281628
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Replace
Map.of(a,b,c);
with
Map.ofEntries(a,b,c);
If you want to still use Map.of() then you shall paste keys and values explicitly.
Map.Entry()returns an immutableMap.Entrycontaining the given
key and value. These entries are suitable for populating Map instances
using theMap.ofEntries()method.
When to use Map.of() and when to use Map.ofEntries()
edited Feb 4 at 5:52
nullpointer
43.2k10101200
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
add a comment |
Replace
Map.of(a,b,c);
with
Map.ofEntries(a,b,c);
If you want to still use Map.of() then you shall paste keys and values explicitly.
Map.Entry()returns an immutableMap.Entrycontaining the given
key and value. These entries are suitable for populating Map instances
using theMap.ofEntries()method.
When to use Map.of() and when to use Map.ofEntries()
edited Feb 4 at 5:52
nullpointer
43.2k10101200
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
add a comment |
Replace
Map.of(a,b,c);
with
Map.ofEntries(a,b,c);
If you want to still use Map.of() then you shall paste keys and values explicitly.
Map.Entry()returns an immutableMap.Entrycontaining the given
key and value. These entries are suitable for populating Map instances
using theMap.ofEntries()method.
When to use Map.of() and when to use Map.ofEntries()
edited Feb 4 at 5:52
nullpointer
43.2k10101200
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
Replace
Map.of(a,b,c);
with
Map.ofEntries(a,b,c);
If you want to still use Map.of() then you shall paste keys and values explicitly.
Map.Entry()returns an immutableMap.Entrycontaining the given
key and value. These entries are suitable for populating Map instances
using theMap.ofEntries()method.
When to use Map.of() and when to use Map.ofEntries()
edited Feb 4 at 5:52
nullpointer
43.2k10101200
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
edited Feb 4 at 5:52
nullpointer
43.2k10101200
edited Feb 4 at 5:52
nullpointer
43.2k10101200
edited Feb 4 at 5:52
nullpointer
43.2k10101200
43.2k10101200
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
answered Feb 4 at 5:41
Common ManCommon Man
1,80021328
1,80021328
add a comment |
add a comment |
From jdk-9 you can use Map.of() to create Map with key value pairs
Map<String, Object> map = Map.of("a", new Object(), "b", new Object(), "c", new Object());
And also by using SimpleEntry
Map<String, Object> map = Map.ofEntries(
new AbstractMap.SimpleEntry<>("a", new Object()),
new AbstractMap.SimpleEntry<>("b", new Object()),
new AbstractMap.SimpleEntry<>("c", new Object()));
Or by using Map.ofEntries OP suggestion
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
add a comment |
From jdk-9 you can use Map.of() to create Map with key value pairs
Map<String, Object> map = Map.of("a", new Object(), "b", new Object(), "c", new Object());
And also by using SimpleEntry
Map<String, Object> map = Map.ofEntries(
new AbstractMap.SimpleEntry<>("a", new Object()),
new AbstractMap.SimpleEntry<>("b", new Object()),
new AbstractMap.SimpleEntry<>("c", new Object()));
Or by using Map.ofEntries OP suggestion
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
add a comment |
From jdk-9 you can use Map.of() to create Map with key value pairs
Map<String, Object> map = Map.of("a", new Object(), "b", new Object(), "c", new Object());
And also by using SimpleEntry
Map<String, Object> map = Map.ofEntries(
new AbstractMap.SimpleEntry<>("a", new Object()),
new AbstractMap.SimpleEntry<>("b", new Object()),
new AbstractMap.SimpleEntry<>("c", new Object()));
Or by using Map.ofEntries OP suggestion
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
From jdk-9 you can use Map.of() to create Map with key value pairs
Map<String, Object> map = Map.of("a", new Object(), "b", new Object(), "c", new Object());
And also by using SimpleEntry
Map<String, Object> map = Map.ofEntries(
new AbstractMap.SimpleEntry<>("a", new Object()),
new AbstractMap.SimpleEntry<>("b", new Object()),
new AbstractMap.SimpleEntry<>("c", new Object()));
Or by using Map.ofEntries OP suggestion
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
edited Feb 4 at 5:49
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
answered Feb 4 at 5:38
DeadpoolDeadpool
6,4692628
6,4692628
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
add a comment |
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
Map.ofEntries was what I was looking for
– rakim
Feb 4 at 5:39
add a comment |
The simple answer is:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c); // ! use Map.ofEntries not Map.of
And the type of Map.entry(key,val) is Map.Entry<K,V>, in case you were wondering.
answered Feb 4 at 5:39
rakimrakim
403211
add a comment |
The simple answer is:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c); // ! use Map.ofEntries not Map.of
And the type of Map.entry(key,val) is Map.Entry<K,V>, in case you were wondering.
answered Feb 4 at 5:39
rakimrakim
403211
add a comment |
The simple answer is:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c); // ! use Map.ofEntries not Map.of
And the type of Map.entry(key,val) is Map.Entry<K,V>, in case you were wondering.
answered Feb 4 at 5:39
rakimrakim
403211
The simple answer is:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c); // ! use Map.ofEntries not Map.of
And the type of Map.entry(key,val) is Map.Entry<K,V>, in case you were wondering.
answered Feb 4 at 5:39
rakimrakim
403211
answered Feb 4 at 5:39
rakimrakim
403211
answered Feb 4 at 5:39
rakimrakim
403211
answered Feb 4 at 5:39
rakimrakim
403211
403211
add a comment |
add a comment |
Use this
var m = Map.ofEntries(a, b, c);
instead of
var m = Map.of(a,b,c);
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
add a comment |
Use this
var m = Map.ofEntries(a, b, c);
instead of
var m = Map.of(a,b,c);
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
add a comment |
Use this
var m = Map.ofEntries(a, b, c);
instead of
var m = Map.of(a,b,c);
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
Use this
var m = Map.ofEntries(a, b, c);
instead of
var m = Map.of(a,b,c);
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
answered Feb 4 at 5:42
Mukit09Mukit09
1,05011023
1,05011023
add a comment |
add a comment |
To create a map from entries Use either:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c);
or:
var m = Map.ofEntries(
entry("a", new Object()),
entry("b", new Object()),
entry("c", new Object()));
You can also create the map without explicitly creating the entries:
var m = Map.of("a", new Object(),
"b", new Object(),
"c", new Object());
answered Feb 4 at 7:59
ETOETO
2,6281628
add a comment |
To create a map from entries Use either:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c);
or:
var m = Map.ofEntries(
entry("a", new Object()),
entry("b", new Object()),
entry("c", new Object()));
You can also create the map without explicitly creating the entries:
var m = Map.of("a", new Object(),
"b", new Object(),
"c", new Object());
answered Feb 4 at 7:59
ETOETO
2,6281628
add a comment |
To create a map from entries Use either:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c);
or:
var m = Map.ofEntries(
entry("a", new Object()),
entry("b", new Object()),
entry("c", new Object()));
You can also create the map without explicitly creating the entries:
var m = Map.of("a", new Object(),
"b", new Object(),
"c", new Object());
answered Feb 4 at 7:59
ETOETO
2,6281628
To create a map from entries Use either:
var a = Map.entry("a", new Object());
var b = Map.entry("b", new Object());
var c = Map.entry("c", new Object());
var m = Map.ofEntries(a,b,c);
or:
var m = Map.ofEntries(
entry("a", new Object()),
entry("b", new Object()),
entry("c", new Object()));
You can also create the map without explicitly creating the entries:
var m = Map.of("a", new Object(),
"b", new Object(),
"c", new Object());
answered Feb 4 at 7:59
ETOETO
2,6281628
answered Feb 4 at 7:59
ETOETO
2,6281628
answered Feb 4 at 7:59
ETOETO
2,6281628
answered Feb 4 at 7:59
ETOETO
2,6281628
2,6281628
add a comment |
add a comment |
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1
I think Map.ofEntries will suffice. Suprising that Map.of is not overloaded to support entries, but I guess I know why.
– rakim
Feb 4 at 5:34
1
@RobbyCornelissen it is Java version 11, the var keyword was introduced, please
– rakim
Feb 4 at 5:34
5
more precisely
java-9– Common Man
Feb 4 at 5:48
2
@CommonMan The
varkeyword was introduced in Java 10 not Java 9.– Mark Rotteveel
Feb 4 at 10:07
1
You're lucky you passed an odd number of arguments to
Map.of. If you had passed an even number of arguments,mwould have been a map of entry to entry, specifically,Map<Map.Entry<String,Object>,Map.Entry<String,Object>>.– Stuart Marks
Feb 13 at 20:05