Is it possible to rotate the Isolines on a Surface Using `MeshFunction`?
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This came up in a different context but some expertise in 3D surfaces or the graphic options would be appreciated. I'm trying to extrapolate the curves from any given surface and things seem to be going quite smoothly. All the curves can be grabbed in one more step as a GraphicsComplex. Perfect for more processing. However, now I'm trying to rotate the isolines to get even more control. This is possible in other software but I'm not sure how it was achieved. I assume there is some way to use the MeshFunction to rotate the Mesh through at least 45 degrees but all my searching hasn't brought up anything helpful. A less practical approach might be to find the intersecting curve of a regularly spaced vertical planes.
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8},
BoxRatios->{4,8,1},
Boxed->False,
Axes->False,
ImageSize->Large,
Mesh->{3,8},
PlotStyle->Directive[Lighting->"Neutral",FaceForm[White,Specularity[0.2,10]]]]
plotting graphics
asked 2 hours ago
BBirdsellBBirdsell
430313
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add a comment |
$begingroup$
This came up in a different context but some expertise in 3D surfaces or the graphic options would be appreciated. I'm trying to extrapolate the curves from any given surface and things seem to be going quite smoothly. All the curves can be grabbed in one more step as a GraphicsComplex. Perfect for more processing. However, now I'm trying to rotate the isolines to get even more control. This is possible in other software but I'm not sure how it was achieved. I assume there is some way to use the MeshFunction to rotate the Mesh through at least 45 degrees but all my searching hasn't brought up anything helpful. A less practical approach might be to find the intersecting curve of a regularly spaced vertical planes.
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8},
BoxRatios->{4,8,1},
Boxed->False,
Axes->False,
ImageSize->Large,
Mesh->{3,8},
PlotStyle->Directive[Lighting->"Neutral",FaceForm[White,Specularity[0.2,10]]]]
plotting graphics
asked 2 hours ago
BBirdsellBBirdsell
430313
$endgroup$
add a comment |
$begingroup$
This came up in a different context but some expertise in 3D surfaces or the graphic options would be appreciated. I'm trying to extrapolate the curves from any given surface and things seem to be going quite smoothly. All the curves can be grabbed in one more step as a GraphicsComplex. Perfect for more processing. However, now I'm trying to rotate the isolines to get even more control. This is possible in other software but I'm not sure how it was achieved. I assume there is some way to use the MeshFunction to rotate the Mesh through at least 45 degrees but all my searching hasn't brought up anything helpful. A less practical approach might be to find the intersecting curve of a regularly spaced vertical planes.
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8},
BoxRatios->{4,8,1},
Boxed->False,
Axes->False,
ImageSize->Large,
Mesh->{3,8},
PlotStyle->Directive[Lighting->"Neutral",FaceForm[White,Specularity[0.2,10]]]]
plotting graphics
asked 2 hours ago
BBirdsellBBirdsell
430313
$endgroup$
This came up in a different context but some expertise in 3D surfaces or the graphic options would be appreciated. I'm trying to extrapolate the curves from any given surface and things seem to be going quite smoothly. All the curves can be grabbed in one more step as a GraphicsComplex. Perfect for more processing. However, now I'm trying to rotate the isolines to get even more control. This is possible in other software but I'm not sure how it was achieved. I assume there is some way to use the MeshFunction to rotate the Mesh through at least 45 degrees but all my searching hasn't brought up anything helpful. A less practical approach might be to find the intersecting curve of a regularly spaced vertical planes.
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8},
BoxRatios->{4,8,1},
Boxed->False,
Axes->False,
ImageSize->Large,
Mesh->{3,8},
PlotStyle->Directive[Lighting->"Neutral",FaceForm[White,Specularity[0.2,10]]]]
plotting graphics
plotting graphics
asked 2 hours ago
BBirdsellBBirdsell
430313
asked 2 hours ago
BBirdsellBBirdsell
430313
asked 2 hours ago
BBirdsellBBirdsell
430313
asked 2 hours ago
BBirdsellBBirdsell
430313
asked 2 hours ago
BBirdsellBBirdsell
430313
430313
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2 Answers
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Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> {4, 8, 1},
Boxed -> False, Axes -> False, ImageSize -> Large,
MeshFunctions -> {# + #2 &, # - #2 &},
Mesh -> {3, 8},
PlotStyle -> Directive[Lighting -> "Neutral", FaceForm[White, Specularity[0.2, 10]]]]
answered 2 hours ago
kglrkglr
185k10202421
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Since we have the identity
RotationMatrix[θ] == {AngleVector[-θ], AngleVector[π/2 - θ]}
one can use this to construct a mesh that is arbitrarily oriented; e.g.
With[{θ = π/4},
Plot3D[Cos[x y/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> Automatic,
MeshFunctions -> {AngleVector[-θ].{#, #2} &,
AngleVector[π/2 - θ].{#, #2} &}]]
and you can change the value of θ for other orientations.
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
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(If anyone is kind enough to edit my post to include the resulting image, please do so.)
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– J. M. is computer-less♦
21 mins ago
add a comment |
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2 Answers
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active
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2 Answers
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$begingroup$
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> {4, 8, 1},
Boxed -> False, Axes -> False, ImageSize -> Large,
MeshFunctions -> {# + #2 &, # - #2 &},
Mesh -> {3, 8},
PlotStyle -> Directive[Lighting -> "Neutral", FaceForm[White, Specularity[0.2, 10]]]]
answered 2 hours ago
kglrkglr
185k10202421
$endgroup$
add a comment |
$begingroup$
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> {4, 8, 1},
Boxed -> False, Axes -> False, ImageSize -> Large,
MeshFunctions -> {# + #2 &, # - #2 &},
Mesh -> {3, 8},
PlotStyle -> Directive[Lighting -> "Neutral", FaceForm[White, Specularity[0.2, 10]]]]
answered 2 hours ago
kglrkglr
185k10202421
$endgroup$
add a comment |
$begingroup$
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> {4, 8, 1},
Boxed -> False, Axes -> False, ImageSize -> Large,
MeshFunctions -> {# + #2 &, # - #2 &},
Mesh -> {3, 8},
PlotStyle -> Directive[Lighting -> "Neutral", FaceForm[White, Specularity[0.2, 10]]]]
answered 2 hours ago
kglrkglr
185k10202421
$endgroup$
Plot3D[Cos[(x y)/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> {4, 8, 1},
Boxed -> False, Axes -> False, ImageSize -> Large,
MeshFunctions -> {# + #2 &, # - #2 &},
Mesh -> {3, 8},
PlotStyle -> Directive[Lighting -> "Neutral", FaceForm[White, Specularity[0.2, 10]]]]
answered 2 hours ago
kglrkglr
185k10202421
answered 2 hours ago
kglrkglr
185k10202421
answered 2 hours ago
kglrkglr
185k10202421
answered 2 hours ago
kglrkglr
185k10202421
185k10202421
add a comment |
add a comment |
$begingroup$
Since we have the identity
RotationMatrix[θ] == {AngleVector[-θ], AngleVector[π/2 - θ]}
one can use this to construct a mesh that is arbitrarily oriented; e.g.
With[{θ = π/4},
Plot3D[Cos[x y/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> Automatic,
MeshFunctions -> {AngleVector[-θ].{#, #2} &,
AngleVector[π/2 - θ].{#, #2} &}]]
and you can change the value of θ for other orientations.
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
$endgroup$
$begingroup$
(If anyone is kind enough to edit my post to include the resulting image, please do so.)
$endgroup$
– J. M. is computer-less♦
21 mins ago
add a comment |
$begingroup$
Since we have the identity
RotationMatrix[θ] == {AngleVector[-θ], AngleVector[π/2 - θ]}
one can use this to construct a mesh that is arbitrarily oriented; e.g.
With[{θ = π/4},
Plot3D[Cos[x y/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> Automatic,
MeshFunctions -> {AngleVector[-θ].{#, #2} &,
AngleVector[π/2 - θ].{#, #2} &}]]
and you can change the value of θ for other orientations.
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
$endgroup$
$begingroup$
(If anyone is kind enough to edit my post to include the resulting image, please do so.)
$endgroup$
– J. M. is computer-less♦
21 mins ago
add a comment |
$begingroup$
Since we have the identity
RotationMatrix[θ] == {AngleVector[-θ], AngleVector[π/2 - θ]}
one can use this to construct a mesh that is arbitrarily oriented; e.g.
With[{θ = π/4},
Plot3D[Cos[x y/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> Automatic,
MeshFunctions -> {AngleVector[-θ].{#, #2} &,
AngleVector[π/2 - θ].{#, #2} &}]]
and you can change the value of θ for other orientations.
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
$endgroup$
Since we have the identity
RotationMatrix[θ] == {AngleVector[-θ], AngleVector[π/2 - θ]}
one can use this to construct a mesh that is arbitrarily oriented; e.g.
With[{θ = π/4},
Plot3D[Cos[x y/2], {x, 0, 4}, {y, 0, 8}, BoxRatios -> Automatic,
MeshFunctions -> {AngleVector[-θ].{#, #2} &,
AngleVector[π/2 - θ].{#, #2} &}]]
and you can change the value of θ for other orientations.
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
answered 22 mins ago
J. M. is computer-less♦J. M. is computer-less
96.8k10303462
96.8k10303462
$begingroup$
(If anyone is kind enough to edit my post to include the resulting image, please do so.)
$endgroup$
– J. M. is computer-less♦
21 mins ago
add a comment |
$begingroup$
(If anyone is kind enough to edit my post to include the resulting image, please do so.)
$endgroup$
– J. M. is computer-less♦
21 mins ago
$begingroup$
(If anyone is kind enough to edit my post to include the resulting image, please do so.)
$endgroup$
– J. M. is computer-less♦
21 mins ago
$begingroup$
(If anyone is kind enough to edit my post to include the resulting image, please do so.)
$endgroup$
– J. M. is computer-less♦
21 mins ago
add a comment |
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