Regex expression to extract numbers from “12234 x 344 x 3545”
0
Need a regex expression to extract first, second and third set of numbers from below examples
- 522×318×495mm K
- 365×320×320mm A
- 465×235×145
- 480×250×465mm
- 420×235×145mm
regex
asked Feb 7 at 11:01
TeeTee
52
add a comment |
0
Need a regex expression to extract first, second and third set of numbers from below examples
- 522×318×495mm K
- 365×320×320mm A
- 465×235×145
- 480×250×465mm
- 420×235×145mm
regex
asked Feb 7 at 11:01
TeeTee
52
add a comment |
0
0
0
Need a regex expression to extract first, second and third set of numbers from below examples
- 522×318×495mm K
- 365×320×320mm A
- 465×235×145
- 480×250×465mm
- 420×235×145mm
regex
asked Feb 7 at 11:01
TeeTee
52
Need a regex expression to extract first, second and third set of numbers from below examples
- 522×318×495mm K
- 365×320×320mm A
- 465×235×145
- 480×250×465mm
- 420×235×145mm
regex
regex
asked Feb 7 at 11:01
TeeTee
52
asked Feb 7 at 11:01
TeeTee
52
asked Feb 7 at 11:01
TeeTee
52
asked Feb 7 at 11:01
TeeTee
52
asked Feb 7 at 11:01
TeeTee
52
52
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
3
This should do what you ask for:
/(d+)×(d+)×(d+)/
You can play with the pattern and get nice explanation what is captured here.
The numbers will be in the capturing group, depending on which tools you use, there will be different way of getting to the results. For example in Perl:
perl -n -e '/^(d+)×(d+)×(d+)/ && print "$1 $2 $3"'
answered Feb 7 at 11:14
MiroslavMiroslav
1461
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
Exactly and if you want to accept one or more of such characters, you can do:(d+)[^0-9]+(d+)[^1-9]+(d+)- this would also match "123xxx234xx567".
– Miroslav
Feb 8 at 16:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
The expression(d+)[^0-9]+(d+)[^1-9]+(d+)that I posted in the previous comment also matches spaces, so it works as it is. The key is[^0-9]+which essentially means "anything but number, one or more characters" so this also includes spaces and such.
– Miroslav
Feb 8 at 17:13
|
show 2 more comments
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
This should do what you ask for:
/(d+)×(d+)×(d+)/
You can play with the pattern and get nice explanation what is captured here.
The numbers will be in the capturing group, depending on which tools you use, there will be different way of getting to the results. For example in Perl:
perl -n -e '/^(d+)×(d+)×(d+)/ && print "$1 $2 $3"'
answered Feb 7 at 11:14
MiroslavMiroslav
1461
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
Exactly and if you want to accept one or more of such characters, you can do:(d+)[^0-9]+(d+)[^1-9]+(d+)- this would also match "123xxx234xx567".
– Miroslav
Feb 8 at 16:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
The expression(d+)[^0-9]+(d+)[^1-9]+(d+)that I posted in the previous comment also matches spaces, so it works as it is. The key is[^0-9]+which essentially means "anything but number, one or more characters" so this also includes spaces and such.
– Miroslav
Feb 8 at 17:13
|
show 2 more comments
3
This should do what you ask for:
/(d+)×(d+)×(d+)/
You can play with the pattern and get nice explanation what is captured here.
The numbers will be in the capturing group, depending on which tools you use, there will be different way of getting to the results. For example in Perl:
perl -n -e '/^(d+)×(d+)×(d+)/ && print "$1 $2 $3"'
answered Feb 7 at 11:14
MiroslavMiroslav
1461
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
Exactly and if you want to accept one or more of such characters, you can do:(d+)[^0-9]+(d+)[^1-9]+(d+)- this would also match "123xxx234xx567".
– Miroslav
Feb 8 at 16:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
The expression(d+)[^0-9]+(d+)[^1-9]+(d+)that I posted in the previous comment also matches spaces, so it works as it is. The key is[^0-9]+which essentially means "anything but number, one or more characters" so this also includes spaces and such.
– Miroslav
Feb 8 at 17:13
|
show 2 more comments
3
3
3
This should do what you ask for:
/(d+)×(d+)×(d+)/
You can play with the pattern and get nice explanation what is captured here.
The numbers will be in the capturing group, depending on which tools you use, there will be different way of getting to the results. For example in Perl:
perl -n -e '/^(d+)×(d+)×(d+)/ && print "$1 $2 $3"'
answered Feb 7 at 11:14
MiroslavMiroslav
1461
This should do what you ask for:
/(d+)×(d+)×(d+)/
You can play with the pattern and get nice explanation what is captured here.
The numbers will be in the capturing group, depending on which tools you use, there will be different way of getting to the results. For example in Perl:
perl -n -e '/^(d+)×(d+)×(d+)/ && print "$1 $2 $3"'
answered Feb 7 at 11:14
MiroslavMiroslav
1461
answered Feb 7 at 11:14
MiroslavMiroslav
1461
answered Feb 7 at 11:14
MiroslavMiroslav
1461
answered Feb 7 at 11:14
MiroslavMiroslav
1461
1461
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
Exactly and if you want to accept one or more of such characters, you can do:(d+)[^0-9]+(d+)[^1-9]+(d+)- this would also match "123xxx234xx567".
– Miroslav
Feb 8 at 16:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
The expression(d+)[^0-9]+(d+)[^1-9]+(d+)that I posted in the previous comment also matches spaces, so it works as it is. The key is[^0-9]+which essentially means "anything but number, one or more characters" so this also includes spaces and such.
– Miroslav
Feb 8 at 17:13
|
show 2 more comments
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
Exactly and if you want to accept one or more of such characters, you can do:(d+)[^0-9]+(d+)[^1-9]+(d+)- this would also match "123xxx234xx567".
– Miroslav
Feb 8 at 16:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
The expression(d+)[^0-9]+(d+)[^1-9]+(d+)that I posted in the previous comment also matches spaces, so it works as it is. The key is[^0-9]+which essentially means "anything but number, one or more characters" so this also includes spaces and such.
– Miroslav
Feb 8 at 17:13
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
Instead of "x" can it be any non-numeral character?
– Tee
Feb 8 at 13:09
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
(d+)[^0-9](d+)[^1-9](d+) Now need to remove spaces
– Tee
Feb 8 at 13:43
Exactly and if you want to accept one or more of such characters, you can do:
(d+)[^0-9]+(d+)[^1-9]+(d+) - this would also match "123xxx234xx567".– Miroslav
Feb 8 at 16:07
Exactly and if you want to accept one or more of such characters, you can do:
(d+)[^0-9]+(d+)[^1-9]+(d+) - this would also match "123xxx234xx567".– Miroslav
Feb 8 at 16:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
how do you match 1234 xx 2333 xx x 4444 So first we need to trim all spaces
– Tee
Feb 8 at 17:07
The expression
(d+)[^0-9]+(d+)[^1-9]+(d+) that I posted in the previous comment also matches spaces, so it works as it is. The key is [^0-9]+ which essentially means "anything but number, one or more characters" so this also includes spaces and such.– Miroslav
Feb 8 at 17:13
The expression
(d+)[^0-9]+(d+)[^1-9]+(d+) that I posted in the previous comment also matches spaces, so it works as it is. The key is [^0-9]+ which essentially means "anything but number, one or more characters" so this also includes spaces and such.– Miroslav
Feb 8 at 17:13
|
show 2 more comments
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