Deleting Duplicate Transactions - VBA or Function












0















Example Transaction Set:



Example Transaction Set



Note the 3 transactions shown. The two transactions highlighted in green are the ones I'd like to delete or flag (doesn't matter).



Using VBA, the code is way too clunky. The code takes forever to run because




  1. I loop through each transaction in column C until I find a negative.

  2. Set Column E as the absolute value target if not zero, else absolute value D.

  3. Define the range for a specific account so that I can begin looping through it to find value in step 2.

  4. If I find the value, I delete both rows (one containing negative and the one which isn't a negative).


My apologies for not commenting code. This was not 100% done yet.



Sub ReversalScrub()

Dim AccountNumber As String
Dim TargetAmount As Double
Dim TargetRange As Range
Dim Transactions As Range
Dim Transaction As Variant
Dim DeletionCount As Integer

Set RawTransactions = Worksheets("RawTransactions")

With RawTransactions
Set Transactions = .Range("C1", .Range("C2").End(xlDown))

End With

TransactionRow = 2

Do Until TransactionRow = Transactions.Rows.Count

If Range("C" & TransactionRow).Value < 0 Then

If Range("C" & TransactionRow).Offset(0, 2).Value < 0 Then

TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 2).Value)
Else
TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 1).Value)
End If

AccountNumber = Range("C" & TransactionRow).Offset(0, -2).Value

Set TargetRange = GetAccountRange(AccountNumber, RawTransactions)

CurrentRow = TargetRange.Row

Do Until CurrentRow = TargetRange.Rows.Count - 1
If (TargetAmount = Range("E" & CurrentRow).Value Or TargetAmount = Range("D" & CurrentRow).Value) Then
Range("A" & CurrentRow).EntireRow.Delete
Range("C" & TransactionRow).EntireRow.Delete
CurrentRow = CurrentRow - 2
Exit Do

End If
CurrentRow = CurrentRow + 1
Loop
End If
TransactionRow = TransactionRow + 1
Loop

End Sub


So then I decided to write a function to see if it would be faster.




  1. Column F: Check if the transaction is negative. If so, create a key using account number, abs(column D), abs(column E). =IF((C91<0),A91&ABS(D91)&ABS(E91))

  2. Column G: Create a key account number, column D, Column E. =A91&D91&E91

  3. Column H: Check whether column F exists within G using Match. =IFERROR(MATCH(F91,$G$1:G91,0),FALSE)

  4. Column I: Check whether actual cell row, matches that of column H from step. =IFERROR(MATCH(ROW(H91),H:H,0),FALSE)

  5. Column J: Check whether H or I are number (MATCH output), if so, they are flagged as reversals and the user can delete them.
    =IF(OR(ISNUMBER(H91),ISNUMBER(I91)),"Reversal",IF(C91=0,"Zero",""))


The problem is that this, too, crashes my computer. How can I effectively find duplicates and remove them without removing the third row?



Second solution sample:



Second solution sample










share|improve this question

























  • Have you tried using condition formatting for duplicates?

    – BillDOe
    Dec 26 '18 at 20:35











  • I cannot use conditional formatting in this case because only 2 out of 3 would be duplicates. Specifically, the 3rd transaction wouldn't be a duplicate. A payment was made (Tran1), it was then reversed (Tran2), and then the customer paid again (Tran3). So in this case, only the first 2 transactions would be removed.

    – Nahuatl_C137
    Dec 26 '18 at 20:38













  • @Nahuatl, you have made it so complicated since ultimately you are Deleting both with -ve & +ve sign Value. Write me whether you would like to delete Rows has Duplicate data in Col C or only Rows which have -ve value in C?

    – Rajesh S
    Dec 27 '18 at 9:18


















0















Example Transaction Set:



Example Transaction Set



Note the 3 transactions shown. The two transactions highlighted in green are the ones I'd like to delete or flag (doesn't matter).



Using VBA, the code is way too clunky. The code takes forever to run because




  1. I loop through each transaction in column C until I find a negative.

  2. Set Column E as the absolute value target if not zero, else absolute value D.

  3. Define the range for a specific account so that I can begin looping through it to find value in step 2.

  4. If I find the value, I delete both rows (one containing negative and the one which isn't a negative).


My apologies for not commenting code. This was not 100% done yet.



Sub ReversalScrub()

Dim AccountNumber As String
Dim TargetAmount As Double
Dim TargetRange As Range
Dim Transactions As Range
Dim Transaction As Variant
Dim DeletionCount As Integer

Set RawTransactions = Worksheets("RawTransactions")

With RawTransactions
Set Transactions = .Range("C1", .Range("C2").End(xlDown))

End With

TransactionRow = 2

Do Until TransactionRow = Transactions.Rows.Count

If Range("C" & TransactionRow).Value < 0 Then

If Range("C" & TransactionRow).Offset(0, 2).Value < 0 Then

TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 2).Value)
Else
TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 1).Value)
End If

AccountNumber = Range("C" & TransactionRow).Offset(0, -2).Value

Set TargetRange = GetAccountRange(AccountNumber, RawTransactions)

CurrentRow = TargetRange.Row

Do Until CurrentRow = TargetRange.Rows.Count - 1
If (TargetAmount = Range("E" & CurrentRow).Value Or TargetAmount = Range("D" & CurrentRow).Value) Then
Range("A" & CurrentRow).EntireRow.Delete
Range("C" & TransactionRow).EntireRow.Delete
CurrentRow = CurrentRow - 2
Exit Do

End If
CurrentRow = CurrentRow + 1
Loop
End If
TransactionRow = TransactionRow + 1
Loop

End Sub


So then I decided to write a function to see if it would be faster.




  1. Column F: Check if the transaction is negative. If so, create a key using account number, abs(column D), abs(column E). =IF((C91<0),A91&ABS(D91)&ABS(E91))

  2. Column G: Create a key account number, column D, Column E. =A91&D91&E91

  3. Column H: Check whether column F exists within G using Match. =IFERROR(MATCH(F91,$G$1:G91,0),FALSE)

  4. Column I: Check whether actual cell row, matches that of column H from step. =IFERROR(MATCH(ROW(H91),H:H,0),FALSE)

  5. Column J: Check whether H or I are number (MATCH output), if so, they are flagged as reversals and the user can delete them.
    =IF(OR(ISNUMBER(H91),ISNUMBER(I91)),"Reversal",IF(C91=0,"Zero",""))


The problem is that this, too, crashes my computer. How can I effectively find duplicates and remove them without removing the third row?



Second solution sample:



Second solution sample










share|improve this question

























  • Have you tried using condition formatting for duplicates?

    – BillDOe
    Dec 26 '18 at 20:35











  • I cannot use conditional formatting in this case because only 2 out of 3 would be duplicates. Specifically, the 3rd transaction wouldn't be a duplicate. A payment was made (Tran1), it was then reversed (Tran2), and then the customer paid again (Tran3). So in this case, only the first 2 transactions would be removed.

    – Nahuatl_C137
    Dec 26 '18 at 20:38













  • @Nahuatl, you have made it so complicated since ultimately you are Deleting both with -ve & +ve sign Value. Write me whether you would like to delete Rows has Duplicate data in Col C or only Rows which have -ve value in C?

    – Rajesh S
    Dec 27 '18 at 9:18
















0












0








0








Example Transaction Set:



Example Transaction Set



Note the 3 transactions shown. The two transactions highlighted in green are the ones I'd like to delete or flag (doesn't matter).



Using VBA, the code is way too clunky. The code takes forever to run because




  1. I loop through each transaction in column C until I find a negative.

  2. Set Column E as the absolute value target if not zero, else absolute value D.

  3. Define the range for a specific account so that I can begin looping through it to find value in step 2.

  4. If I find the value, I delete both rows (one containing negative and the one which isn't a negative).


My apologies for not commenting code. This was not 100% done yet.



Sub ReversalScrub()

Dim AccountNumber As String
Dim TargetAmount As Double
Dim TargetRange As Range
Dim Transactions As Range
Dim Transaction As Variant
Dim DeletionCount As Integer

Set RawTransactions = Worksheets("RawTransactions")

With RawTransactions
Set Transactions = .Range("C1", .Range("C2").End(xlDown))

End With

TransactionRow = 2

Do Until TransactionRow = Transactions.Rows.Count

If Range("C" & TransactionRow).Value < 0 Then

If Range("C" & TransactionRow).Offset(0, 2).Value < 0 Then

TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 2).Value)
Else
TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 1).Value)
End If

AccountNumber = Range("C" & TransactionRow).Offset(0, -2).Value

Set TargetRange = GetAccountRange(AccountNumber, RawTransactions)

CurrentRow = TargetRange.Row

Do Until CurrentRow = TargetRange.Rows.Count - 1
If (TargetAmount = Range("E" & CurrentRow).Value Or TargetAmount = Range("D" & CurrentRow).Value) Then
Range("A" & CurrentRow).EntireRow.Delete
Range("C" & TransactionRow).EntireRow.Delete
CurrentRow = CurrentRow - 2
Exit Do

End If
CurrentRow = CurrentRow + 1
Loop
End If
TransactionRow = TransactionRow + 1
Loop

End Sub


So then I decided to write a function to see if it would be faster.




  1. Column F: Check if the transaction is negative. If so, create a key using account number, abs(column D), abs(column E). =IF((C91<0),A91&ABS(D91)&ABS(E91))

  2. Column G: Create a key account number, column D, Column E. =A91&D91&E91

  3. Column H: Check whether column F exists within G using Match. =IFERROR(MATCH(F91,$G$1:G91,0),FALSE)

  4. Column I: Check whether actual cell row, matches that of column H from step. =IFERROR(MATCH(ROW(H91),H:H,0),FALSE)

  5. Column J: Check whether H or I are number (MATCH output), if so, they are flagged as reversals and the user can delete them.
    =IF(OR(ISNUMBER(H91),ISNUMBER(I91)),"Reversal",IF(C91=0,"Zero",""))


The problem is that this, too, crashes my computer. How can I effectively find duplicates and remove them without removing the third row?



Second solution sample:



Second solution sample










share|improve this question
















Example Transaction Set:



Example Transaction Set



Note the 3 transactions shown. The two transactions highlighted in green are the ones I'd like to delete or flag (doesn't matter).



Using VBA, the code is way too clunky. The code takes forever to run because




  1. I loop through each transaction in column C until I find a negative.

  2. Set Column E as the absolute value target if not zero, else absolute value D.

  3. Define the range for a specific account so that I can begin looping through it to find value in step 2.

  4. If I find the value, I delete both rows (one containing negative and the one which isn't a negative).


My apologies for not commenting code. This was not 100% done yet.



Sub ReversalScrub()

Dim AccountNumber As String
Dim TargetAmount As Double
Dim TargetRange As Range
Dim Transactions As Range
Dim Transaction As Variant
Dim DeletionCount As Integer

Set RawTransactions = Worksheets("RawTransactions")

With RawTransactions
Set Transactions = .Range("C1", .Range("C2").End(xlDown))

End With

TransactionRow = 2

Do Until TransactionRow = Transactions.Rows.Count

If Range("C" & TransactionRow).Value < 0 Then

If Range("C" & TransactionRow).Offset(0, 2).Value < 0 Then

TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 2).Value)
Else
TargetAmount = Abs(Range("C" & TransactionRow).Offset(0, 1).Value)
End If

AccountNumber = Range("C" & TransactionRow).Offset(0, -2).Value

Set TargetRange = GetAccountRange(AccountNumber, RawTransactions)

CurrentRow = TargetRange.Row

Do Until CurrentRow = TargetRange.Rows.Count - 1
If (TargetAmount = Range("E" & CurrentRow).Value Or TargetAmount = Range("D" & CurrentRow).Value) Then
Range("A" & CurrentRow).EntireRow.Delete
Range("C" & TransactionRow).EntireRow.Delete
CurrentRow = CurrentRow - 2
Exit Do

End If
CurrentRow = CurrentRow + 1
Loop
End If
TransactionRow = TransactionRow + 1
Loop

End Sub


So then I decided to write a function to see if it would be faster.




  1. Column F: Check if the transaction is negative. If so, create a key using account number, abs(column D), abs(column E). =IF((C91<0),A91&ABS(D91)&ABS(E91))

  2. Column G: Create a key account number, column D, Column E. =A91&D91&E91

  3. Column H: Check whether column F exists within G using Match. =IFERROR(MATCH(F91,$G$1:G91,0),FALSE)

  4. Column I: Check whether actual cell row, matches that of column H from step. =IFERROR(MATCH(ROW(H91),H:H,0),FALSE)

  5. Column J: Check whether H or I are number (MATCH output), if so, they are flagged as reversals and the user can delete them.
    =IF(OR(ISNUMBER(H91),ISNUMBER(I91)),"Reversal",IF(C91=0,"Zero",""))


The problem is that this, too, crashes my computer. How can I effectively find duplicates and remove them without removing the third row?



Second solution sample:



Second solution sample







microsoft-excel worksheet-function vba microsoft-excel-2016






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 26 '18 at 20:39







Nahuatl_C137

















asked Dec 26 '18 at 20:09









Nahuatl_C137Nahuatl_C137

33




33













  • Have you tried using condition formatting for duplicates?

    – BillDOe
    Dec 26 '18 at 20:35











  • I cannot use conditional formatting in this case because only 2 out of 3 would be duplicates. Specifically, the 3rd transaction wouldn't be a duplicate. A payment was made (Tran1), it was then reversed (Tran2), and then the customer paid again (Tran3). So in this case, only the first 2 transactions would be removed.

    – Nahuatl_C137
    Dec 26 '18 at 20:38













  • @Nahuatl, you have made it so complicated since ultimately you are Deleting both with -ve & +ve sign Value. Write me whether you would like to delete Rows has Duplicate data in Col C or only Rows which have -ve value in C?

    – Rajesh S
    Dec 27 '18 at 9:18





















  • Have you tried using condition formatting for duplicates?

    – BillDOe
    Dec 26 '18 at 20:35











  • I cannot use conditional formatting in this case because only 2 out of 3 would be duplicates. Specifically, the 3rd transaction wouldn't be a duplicate. A payment was made (Tran1), it was then reversed (Tran2), and then the customer paid again (Tran3). So in this case, only the first 2 transactions would be removed.

    – Nahuatl_C137
    Dec 26 '18 at 20:38













  • @Nahuatl, you have made it so complicated since ultimately you are Deleting both with -ve & +ve sign Value. Write me whether you would like to delete Rows has Duplicate data in Col C or only Rows which have -ve value in C?

    – Rajesh S
    Dec 27 '18 at 9:18



















Have you tried using condition formatting for duplicates?

– BillDOe
Dec 26 '18 at 20:35





Have you tried using condition formatting for duplicates?

– BillDOe
Dec 26 '18 at 20:35













I cannot use conditional formatting in this case because only 2 out of 3 would be duplicates. Specifically, the 3rd transaction wouldn't be a duplicate. A payment was made (Tran1), it was then reversed (Tran2), and then the customer paid again (Tran3). So in this case, only the first 2 transactions would be removed.

– Nahuatl_C137
Dec 26 '18 at 20:38







I cannot use conditional formatting in this case because only 2 out of 3 would be duplicates. Specifically, the 3rd transaction wouldn't be a duplicate. A payment was made (Tran1), it was then reversed (Tran2), and then the customer paid again (Tran3). So in this case, only the first 2 transactions would be removed.

– Nahuatl_C137
Dec 26 '18 at 20:38















@Nahuatl, you have made it so complicated since ultimately you are Deleting both with -ve & +ve sign Value. Write me whether you would like to delete Rows has Duplicate data in Col C or only Rows which have -ve value in C?

– Rajesh S
Dec 27 '18 at 9:18







@Nahuatl, you have made it so complicated since ultimately you are Deleting both with -ve & +ve sign Value. Write me whether you would like to delete Rows has Duplicate data in Col C or only Rows which have -ve value in C?

– Rajesh S
Dec 27 '18 at 9:18












1 Answer
1






active

oldest

votes


















1














This seems to work with a small data set. Try it and adjust as needed. I'm flagging cell F with a reversal message.



This looks through column C until it finds an empty cell. If you have empty cells you will need to adjust the Do Until loop.



I am skipping cells that have been flagged previously (not empty cell F)



Note it will only flag 1 cell as matching.



Sub FlagReversals()

Dim MyExit As String
Dim PosLoc
Dim NegLoc
Dim NegAmt
Dim PosAmt

Range("C2").Select

Do Until IsEmpty(ActiveCell)
If ActiveCell.Value < 0 And IsEmpty(ActiveCell.Offset(0, 3).Value) Then
NegLoc = ActiveCell.Address
Acct = ActiveCell.Offset(0, -2)
NegAmt = ActiveCell.Value
PosAmt = Abs(ActiveCell.Value)
MyExit = "False"
Do Until MyExit = "True"
If ActiveCell.Offset(-1, 0).Row > 1 Then
ActiveCell.Offset(-1, 0).Select
Else
Range(NegLoc).Select
ActiveCell.Offset(1, 0).Select
MyExit = "True"
End If
If Acct = ActiveCell.Offset(0, -2) And IsEmpty(ActiveCell.Offset(0, 3).Value) And MyExit = "False" Then
If PosAmt = ActiveCell.Value Then
' found the match (by account and value)
ActiveCell.Offset(0, 3).Value = "Reversal from address " & NegLoc
PosLoc = ActiveCell.Address
Range(NegLoc).Select
ActiveCell.Offset(0, 3).Value = "Reversal from address " & PosLoc
MyExit = "True"
End If
End If
Loop
End If
ActiveCell.Offset(1, 0).Select
Loop

End Sub


Edit: Cleaned up infinite loop when no match found.






share|improve this answer


























  • Great solution and very easy to follow!

    – Nahuatl_C137
    Dec 27 '18 at 14:48











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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














This seems to work with a small data set. Try it and adjust as needed. I'm flagging cell F with a reversal message.



This looks through column C until it finds an empty cell. If you have empty cells you will need to adjust the Do Until loop.



I am skipping cells that have been flagged previously (not empty cell F)



Note it will only flag 1 cell as matching.



Sub FlagReversals()

Dim MyExit As String
Dim PosLoc
Dim NegLoc
Dim NegAmt
Dim PosAmt

Range("C2").Select

Do Until IsEmpty(ActiveCell)
If ActiveCell.Value < 0 And IsEmpty(ActiveCell.Offset(0, 3).Value) Then
NegLoc = ActiveCell.Address
Acct = ActiveCell.Offset(0, -2)
NegAmt = ActiveCell.Value
PosAmt = Abs(ActiveCell.Value)
MyExit = "False"
Do Until MyExit = "True"
If ActiveCell.Offset(-1, 0).Row > 1 Then
ActiveCell.Offset(-1, 0).Select
Else
Range(NegLoc).Select
ActiveCell.Offset(1, 0).Select
MyExit = "True"
End If
If Acct = ActiveCell.Offset(0, -2) And IsEmpty(ActiveCell.Offset(0, 3).Value) And MyExit = "False" Then
If PosAmt = ActiveCell.Value Then
' found the match (by account and value)
ActiveCell.Offset(0, 3).Value = "Reversal from address " & NegLoc
PosLoc = ActiveCell.Address
Range(NegLoc).Select
ActiveCell.Offset(0, 3).Value = "Reversal from address " & PosLoc
MyExit = "True"
End If
End If
Loop
End If
ActiveCell.Offset(1, 0).Select
Loop

End Sub


Edit: Cleaned up infinite loop when no match found.






share|improve this answer


























  • Great solution and very easy to follow!

    – Nahuatl_C137
    Dec 27 '18 at 14:48
















1














This seems to work with a small data set. Try it and adjust as needed. I'm flagging cell F with a reversal message.



This looks through column C until it finds an empty cell. If you have empty cells you will need to adjust the Do Until loop.



I am skipping cells that have been flagged previously (not empty cell F)



Note it will only flag 1 cell as matching.



Sub FlagReversals()

Dim MyExit As String
Dim PosLoc
Dim NegLoc
Dim NegAmt
Dim PosAmt

Range("C2").Select

Do Until IsEmpty(ActiveCell)
If ActiveCell.Value < 0 And IsEmpty(ActiveCell.Offset(0, 3).Value) Then
NegLoc = ActiveCell.Address
Acct = ActiveCell.Offset(0, -2)
NegAmt = ActiveCell.Value
PosAmt = Abs(ActiveCell.Value)
MyExit = "False"
Do Until MyExit = "True"
If ActiveCell.Offset(-1, 0).Row > 1 Then
ActiveCell.Offset(-1, 0).Select
Else
Range(NegLoc).Select
ActiveCell.Offset(1, 0).Select
MyExit = "True"
End If
If Acct = ActiveCell.Offset(0, -2) And IsEmpty(ActiveCell.Offset(0, 3).Value) And MyExit = "False" Then
If PosAmt = ActiveCell.Value Then
' found the match (by account and value)
ActiveCell.Offset(0, 3).Value = "Reversal from address " & NegLoc
PosLoc = ActiveCell.Address
Range(NegLoc).Select
ActiveCell.Offset(0, 3).Value = "Reversal from address " & PosLoc
MyExit = "True"
End If
End If
Loop
End If
ActiveCell.Offset(1, 0).Select
Loop

End Sub


Edit: Cleaned up infinite loop when no match found.






share|improve this answer


























  • Great solution and very easy to follow!

    – Nahuatl_C137
    Dec 27 '18 at 14:48














1












1








1







This seems to work with a small data set. Try it and adjust as needed. I'm flagging cell F with a reversal message.



This looks through column C until it finds an empty cell. If you have empty cells you will need to adjust the Do Until loop.



I am skipping cells that have been flagged previously (not empty cell F)



Note it will only flag 1 cell as matching.



Sub FlagReversals()

Dim MyExit As String
Dim PosLoc
Dim NegLoc
Dim NegAmt
Dim PosAmt

Range("C2").Select

Do Until IsEmpty(ActiveCell)
If ActiveCell.Value < 0 And IsEmpty(ActiveCell.Offset(0, 3).Value) Then
NegLoc = ActiveCell.Address
Acct = ActiveCell.Offset(0, -2)
NegAmt = ActiveCell.Value
PosAmt = Abs(ActiveCell.Value)
MyExit = "False"
Do Until MyExit = "True"
If ActiveCell.Offset(-1, 0).Row > 1 Then
ActiveCell.Offset(-1, 0).Select
Else
Range(NegLoc).Select
ActiveCell.Offset(1, 0).Select
MyExit = "True"
End If
If Acct = ActiveCell.Offset(0, -2) And IsEmpty(ActiveCell.Offset(0, 3).Value) And MyExit = "False" Then
If PosAmt = ActiveCell.Value Then
' found the match (by account and value)
ActiveCell.Offset(0, 3).Value = "Reversal from address " & NegLoc
PosLoc = ActiveCell.Address
Range(NegLoc).Select
ActiveCell.Offset(0, 3).Value = "Reversal from address " & PosLoc
MyExit = "True"
End If
End If
Loop
End If
ActiveCell.Offset(1, 0).Select
Loop

End Sub


Edit: Cleaned up infinite loop when no match found.






share|improve this answer















This seems to work with a small data set. Try it and adjust as needed. I'm flagging cell F with a reversal message.



This looks through column C until it finds an empty cell. If you have empty cells you will need to adjust the Do Until loop.



I am skipping cells that have been flagged previously (not empty cell F)



Note it will only flag 1 cell as matching.



Sub FlagReversals()

Dim MyExit As String
Dim PosLoc
Dim NegLoc
Dim NegAmt
Dim PosAmt

Range("C2").Select

Do Until IsEmpty(ActiveCell)
If ActiveCell.Value < 0 And IsEmpty(ActiveCell.Offset(0, 3).Value) Then
NegLoc = ActiveCell.Address
Acct = ActiveCell.Offset(0, -2)
NegAmt = ActiveCell.Value
PosAmt = Abs(ActiveCell.Value)
MyExit = "False"
Do Until MyExit = "True"
If ActiveCell.Offset(-1, 0).Row > 1 Then
ActiveCell.Offset(-1, 0).Select
Else
Range(NegLoc).Select
ActiveCell.Offset(1, 0).Select
MyExit = "True"
End If
If Acct = ActiveCell.Offset(0, -2) And IsEmpty(ActiveCell.Offset(0, 3).Value) And MyExit = "False" Then
If PosAmt = ActiveCell.Value Then
' found the match (by account and value)
ActiveCell.Offset(0, 3).Value = "Reversal from address " & NegLoc
PosLoc = ActiveCell.Address
Range(NegLoc).Select
ActiveCell.Offset(0, 3).Value = "Reversal from address " & PosLoc
MyExit = "True"
End If
End If
Loop
End If
ActiveCell.Offset(1, 0).Select
Loop

End Sub


Edit: Cleaned up infinite loop when no match found.







share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 27 '18 at 0:06

























answered Dec 26 '18 at 23:03









BrianBrian

1445




1445













  • Great solution and very easy to follow!

    – Nahuatl_C137
    Dec 27 '18 at 14:48



















  • Great solution and very easy to follow!

    – Nahuatl_C137
    Dec 27 '18 at 14:48

















Great solution and very easy to follow!

– Nahuatl_C137
Dec 27 '18 at 14:48





Great solution and very easy to follow!

– Nahuatl_C137
Dec 27 '18 at 14:48


















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