How can I split a string to letters with IFS and read at no space/null, space and at a character -?
up vote
3
down vote
favorite
I have a string -w o rd.
I need to split it to w o r d or to an array for 'w' 'o' 'r' 'd'
it doesn't really matter.
I have tried the following
IFS='- ' read -a string <<< "-w o rd"
echo ${string[*]}
rd isn't getting split. How can I make it get split
bash read
asked 2 hours ago
Bret Joseph
707
add a comment |
up vote
3
down vote
favorite
I have a string -w o rd.
I need to split it to w o r d or to an array for 'w' 'o' 'r' 'd'
it doesn't really matter.
I have tried the following
IFS='- ' read -a string <<< "-w o rd"
echo ${string[*]}
rd isn't getting split. How can I make it get split
bash read
asked 2 hours ago
Bret Joseph
707
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
I have a string -w o rd.
I need to split it to w o r d or to an array for 'w' 'o' 'r' 'd'
it doesn't really matter.
I have tried the following
IFS='- ' read -a string <<< "-w o rd"
echo ${string[*]}
rd isn't getting split. How can I make it get split
bash read
asked 2 hours ago
Bret Joseph
707
I have a string -w o rd.
I need to split it to w o r d or to an array for 'w' 'o' 'r' 'd'
it doesn't really matter.
I have tried the following
IFS='- ' read -a string <<< "-w o rd"
echo ${string[*]}
rd isn't getting split. How can I make it get split
bash read
bash read
asked 2 hours ago
Bret Joseph
707
asked 2 hours ago
Bret Joseph
707
asked 2 hours ago
Bret Joseph
707
asked 2 hours ago
Bret Joseph
707
asked 2 hours ago
Bret Joseph
707
707
add a comment |
add a comment |
1 Answer
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4
down vote
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You can't use IFS in bash to split on nothing (it has to be on a character). There's no characters between r and d in rd. No space and no character isn't the same as the null character.
If you want each character as a separate element in the array, one way I can think of is to read each character individually and append it to an array (and using IFS to get rid of spaces and -):
bash-4.4$ while IFS=' -' read -n1 c ; do [[ -n $c ]] && foo+=("$c"); done <<<"-w o rd"
bash-4.4$ declare -p foo
declare -a foo=([0]="w" [1]="o" [2]="r" [3]="d")
answered 2 hours ago
muru
35.5k582157
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
You can't use IFS in bash to split on nothing (it has to be on a character). There's no characters between r and d in rd. No space and no character isn't the same as the null character.
If you want each character as a separate element in the array, one way I can think of is to read each character individually and append it to an array (and using IFS to get rid of spaces and -):
bash-4.4$ while IFS=' -' read -n1 c ; do [[ -n $c ]] && foo+=("$c"); done <<<"-w o rd"
bash-4.4$ declare -p foo
declare -a foo=([0]="w" [1]="o" [2]="r" [3]="d")
answered 2 hours ago
muru
35.5k582157
add a comment |
up vote
4
down vote
accepted
You can't use IFS in bash to split on nothing (it has to be on a character). There's no characters between r and d in rd. No space and no character isn't the same as the null character.
If you want each character as a separate element in the array, one way I can think of is to read each character individually and append it to an array (and using IFS to get rid of spaces and -):
bash-4.4$ while IFS=' -' read -n1 c ; do [[ -n $c ]] && foo+=("$c"); done <<<"-w o rd"
bash-4.4$ declare -p foo
declare -a foo=([0]="w" [1]="o" [2]="r" [3]="d")
answered 2 hours ago
muru
35.5k582157
add a comment |
up vote
4
down vote
accepted
up vote
4
down vote
accepted
You can't use IFS in bash to split on nothing (it has to be on a character). There's no characters between r and d in rd. No space and no character isn't the same as the null character.
If you want each character as a separate element in the array, one way I can think of is to read each character individually and append it to an array (and using IFS to get rid of spaces and -):
bash-4.4$ while IFS=' -' read -n1 c ; do [[ -n $c ]] && foo+=("$c"); done <<<"-w o rd"
bash-4.4$ declare -p foo
declare -a foo=([0]="w" [1]="o" [2]="r" [3]="d")
answered 2 hours ago
muru
35.5k582157
You can't use IFS in bash to split on nothing (it has to be on a character). There's no characters between r and d in rd. No space and no character isn't the same as the null character.
If you want each character as a separate element in the array, one way I can think of is to read each character individually and append it to an array (and using IFS to get rid of spaces and -):
bash-4.4$ while IFS=' -' read -n1 c ; do [[ -n $c ]] && foo+=("$c"); done <<<"-w o rd"
bash-4.4$ declare -p foo
declare -a foo=([0]="w" [1]="o" [2]="r" [3]="d")
answered 2 hours ago
muru
35.5k582157
answered 2 hours ago
muru
35.5k582157
answered 2 hours ago
muru
35.5k582157
answered 2 hours ago
muru
35.5k582157
35.5k582157
add a comment |
add a comment |
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