Shall structured binding to a copy of a const c-array be const?
up vote
18
down vote
favorite
Consider this code (demo):
#include <tuple>
#include <type_traits>
struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];
const Ag ag {};
const T t {};
const Ar ar {};
void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}
A structured binding to a copy of a const
c-array are declared const by Clang and non-const by GCC.
The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.
On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar
is accordingly to [expr.type]/1 const int[2]
.
What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.
c++ language-lawyer c++17 structured-bindings
add a comment |
up vote
18
down vote
favorite
Consider this code (demo):
#include <tuple>
#include <type_traits>
struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];
const Ag ag {};
const T t {};
const Ar ar {};
void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}
A structured binding to a copy of a const
c-array are declared const by Clang and non-const by GCC.
The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.
On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar
is accordingly to [expr.type]/1 const int[2]
.
What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.
c++ language-lawyer c++17 structured-bindings
1
Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago
3
gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago
add a comment |
up vote
18
down vote
favorite
up vote
18
down vote
favorite
Consider this code (demo):
#include <tuple>
#include <type_traits>
struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];
const Ag ag {};
const T t {};
const Ar ar {};
void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}
A structured binding to a copy of a const
c-array are declared const by Clang and non-const by GCC.
The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.
On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar
is accordingly to [expr.type]/1 const int[2]
.
What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.
c++ language-lawyer c++17 structured-bindings
Consider this code (demo):
#include <tuple>
#include <type_traits>
struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];
const Ag ag {};
const T t {};
const Ar ar {};
void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}
A structured binding to a copy of a const
c-array are declared const by Clang and non-const by GCC.
The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.
On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar
is accordingly to [expr.type]/1 const int[2]
.
What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.
c++ language-lawyer c++17 structured-bindings
c++ language-lawyer c++17 structured-bindings
edited 4 hours ago
asked 4 hours ago
Oliv
7,9631854
7,9631854
1
Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago
3
gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago
add a comment |
1
Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago
3
gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago
1
1
Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago
Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago
3
3
gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago
gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
up vote
9
down vote
The wording of the standard in [dcl.struct.bind] says:
If the assignment-expression in the initializer has array type
A
and no ref-qualifier is present,e
has type cvA
and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.
We have auto [i,j] = ar;
, ar
has array type const int[2]
, and the wording of the standard makes it clear that e
has type const int[2]
. Thus, per the wording, each binding references the element type - which is const int
. Clang is technically correct.
However, as Richard Smith points out in gcc bug 80649:
I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.
That seems right. When you write auto x = y;
you'd certainly expect x
to not be top-level const
, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.
The cv-qualification cv comes from the decl-specifier-seq ("auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers onA
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago
2
@LightnessRacesinOrbit It does - butA
is an array of const, socv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
add a comment |
up vote
4
down vote
In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.
The decl-specifier-seq ("auto
") has no cv-qualifiers (that is, you did not write const auto
), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.
[dcl.struct.bind]/1:
[..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]
[dcl.struct.bind]/3:
IfE
is an array type with element typeT
, the number of elements in the identifier-list shall be equal to the number of elements ofE
. Each vi is the name of an lvalue that refers to the elementi
of the array and whose type isT
; the referenced type isT
. [ Note: The top-level cv-qualifiers ofT
are cv. — end note ] [..]
Like you, Clang devs have interpreted the auto
here as having cv-qualification of const
, because the type inferred by it is const Ag
. But I see no standard justification for that interpretation.
Yeah, that note is misleading. Do you agree that the type of the underlying object isconst int[2]
? Then you should also agree that the element typeT
of the array isconst int
, and notint
.
– Rakete1111
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers ofT
. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago
I agree. But cv is not the only cv-qualifier that affects the type ofT
. For another example: IfU
isconst int
, then saying that the type of something iscv U
with cv being empty, it doesn't mean thatU
is notconst
.
– Rakete1111
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
|
show 2 more comments
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
9
down vote
The wording of the standard in [dcl.struct.bind] says:
If the assignment-expression in the initializer has array type
A
and no ref-qualifier is present,e
has type cvA
and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.
We have auto [i,j] = ar;
, ar
has array type const int[2]
, and the wording of the standard makes it clear that e
has type const int[2]
. Thus, per the wording, each binding references the element type - which is const int
. Clang is technically correct.
However, as Richard Smith points out in gcc bug 80649:
I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.
That seems right. When you write auto x = y;
you'd certainly expect x
to not be top-level const
, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.
The cv-qualification cv comes from the decl-specifier-seq ("auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers onA
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago
2
@LightnessRacesinOrbit It does - butA
is an array of const, socv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
add a comment |
up vote
9
down vote
The wording of the standard in [dcl.struct.bind] says:
If the assignment-expression in the initializer has array type
A
and no ref-qualifier is present,e
has type cvA
and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.
We have auto [i,j] = ar;
, ar
has array type const int[2]
, and the wording of the standard makes it clear that e
has type const int[2]
. Thus, per the wording, each binding references the element type - which is const int
. Clang is technically correct.
However, as Richard Smith points out in gcc bug 80649:
I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.
That seems right. When you write auto x = y;
you'd certainly expect x
to not be top-level const
, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.
The cv-qualification cv comes from the decl-specifier-seq ("auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers onA
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago
2
@LightnessRacesinOrbit It does - butA
is an array of const, socv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
add a comment |
up vote
9
down vote
up vote
9
down vote
The wording of the standard in [dcl.struct.bind] says:
If the assignment-expression in the initializer has array type
A
and no ref-qualifier is present,e
has type cvA
and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.
We have auto [i,j] = ar;
, ar
has array type const int[2]
, and the wording of the standard makes it clear that e
has type const int[2]
. Thus, per the wording, each binding references the element type - which is const int
. Clang is technically correct.
However, as Richard Smith points out in gcc bug 80649:
I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.
That seems right. When you write auto x = y;
you'd certainly expect x
to not be top-level const
, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.
The wording of the standard in [dcl.struct.bind] says:
If the assignment-expression in the initializer has array type
A
and no ref-qualifier is present,e
has type cvA
and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.
We have auto [i,j] = ar;
, ar
has array type const int[2]
, and the wording of the standard makes it clear that e
has type const int[2]
. Thus, per the wording, each binding references the element type - which is const int
. Clang is technically correct.
However, as Richard Smith points out in gcc bug 80649:
I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.
That seems right. When you write auto x = y;
you'd certainly expect x
to not be top-level const
, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.
answered 3 hours ago
Barry
175k18298553
175k18298553
The cv-qualification cv comes from the decl-specifier-seq ("auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers onA
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago
2
@LightnessRacesinOrbit It does - butA
is an array of const, socv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
add a comment |
The cv-qualification cv comes from the decl-specifier-seq ("auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers onA
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago
2
@LightnessRacesinOrbit It does - butA
is an array of const, socv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
The cv-qualification cv comes from the decl-specifier-seq ("
auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers on A
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.– Lightness Races in Orbit
2 hours ago
The cv-qualification cv comes from the decl-specifier-seq ("
auto
") not the initialiser ("ar
"), no? Unless it's saying that the qualifiers on A
are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.– Lightness Races in Orbit
2 hours ago
2
2
@LightnessRacesinOrbit It does - but
A
is an array of const, so cv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.– Barry
2 hours ago
@LightnessRacesinOrbit It does - but
A
is an array of const, so cv A
is still an array of const. I don't think we want to maintain constness, hence Core issue.– Barry
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago
add a comment |
up vote
4
down vote
In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.
The decl-specifier-seq ("auto
") has no cv-qualifiers (that is, you did not write const auto
), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.
[dcl.struct.bind]/1:
[..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]
[dcl.struct.bind]/3:
IfE
is an array type with element typeT
, the number of elements in the identifier-list shall be equal to the number of elements ofE
. Each vi is the name of an lvalue that refers to the elementi
of the array and whose type isT
; the referenced type isT
. [ Note: The top-level cv-qualifiers ofT
are cv. — end note ] [..]
Like you, Clang devs have interpreted the auto
here as having cv-qualification of const
, because the type inferred by it is const Ag
. But I see no standard justification for that interpretation.
Yeah, that note is misleading. Do you agree that the type of the underlying object isconst int[2]
? Then you should also agree that the element typeT
of the array isconst int
, and notint
.
– Rakete1111
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers ofT
. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago
I agree. But cv is not the only cv-qualifier that affects the type ofT
. For another example: IfU
isconst int
, then saying that the type of something iscv U
with cv being empty, it doesn't mean thatU
is notconst
.
– Rakete1111
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
|
show 2 more comments
up vote
4
down vote
In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.
The decl-specifier-seq ("auto
") has no cv-qualifiers (that is, you did not write const auto
), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.
[dcl.struct.bind]/1:
[..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]
[dcl.struct.bind]/3:
IfE
is an array type with element typeT
, the number of elements in the identifier-list shall be equal to the number of elements ofE
. Each vi is the name of an lvalue that refers to the elementi
of the array and whose type isT
; the referenced type isT
. [ Note: The top-level cv-qualifiers ofT
are cv. — end note ] [..]
Like you, Clang devs have interpreted the auto
here as having cv-qualification of const
, because the type inferred by it is const Ag
. But I see no standard justification for that interpretation.
Yeah, that note is misleading. Do you agree that the type of the underlying object isconst int[2]
? Then you should also agree that the element typeT
of the array isconst int
, and notint
.
– Rakete1111
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers ofT
. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago
I agree. But cv is not the only cv-qualifier that affects the type ofT
. For another example: IfU
isconst int
, then saying that the type of something iscv U
with cv being empty, it doesn't mean thatU
is notconst
.
– Rakete1111
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
|
show 2 more comments
up vote
4
down vote
up vote
4
down vote
In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.
The decl-specifier-seq ("auto
") has no cv-qualifiers (that is, you did not write const auto
), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.
[dcl.struct.bind]/1:
[..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]
[dcl.struct.bind]/3:
IfE
is an array type with element typeT
, the number of elements in the identifier-list shall be equal to the number of elements ofE
. Each vi is the name of an lvalue that refers to the elementi
of the array and whose type isT
; the referenced type isT
. [ Note: The top-level cv-qualifiers ofT
are cv. — end note ] [..]
Like you, Clang devs have interpreted the auto
here as having cv-qualification of const
, because the type inferred by it is const Ag
. But I see no standard justification for that interpretation.
In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.
The decl-specifier-seq ("auto
") has no cv-qualifiers (that is, you did not write const auto
), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.
[dcl.struct.bind]/1:
[..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]
[dcl.struct.bind]/3:
IfE
is an array type with element typeT
, the number of elements in the identifier-list shall be equal to the number of elements ofE
. Each vi is the name of an lvalue that refers to the elementi
of the array and whose type isT
; the referenced type isT
. [ Note: The top-level cv-qualifiers ofT
are cv. — end note ] [..]
Like you, Clang devs have interpreted the auto
here as having cv-qualification of const
, because the type inferred by it is const Ag
. But I see no standard justification for that interpretation.
answered 3 hours ago
Lightness Races in Orbit
281k51453769
281k51453769
Yeah, that note is misleading. Do you agree that the type of the underlying object isconst int[2]
? Then you should also agree that the element typeT
of the array isconst int
, and notint
.
– Rakete1111
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers ofT
. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago
I agree. But cv is not the only cv-qualifier that affects the type ofT
. For another example: IfU
isconst int
, then saying that the type of something iscv U
with cv being empty, it doesn't mean thatU
is notconst
.
– Rakete1111
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
|
show 2 more comments
Yeah, that note is misleading. Do you agree that the type of the underlying object isconst int[2]
? Then you should also agree that the element typeT
of the array isconst int
, and notint
.
– Rakete1111
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers ofT
. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago
I agree. But cv is not the only cv-qualifier that affects the type ofT
. For another example: IfU
isconst int
, then saying that the type of something iscv U
with cv being empty, it doesn't mean thatU
is notconst
.
– Rakete1111
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
Yeah, that note is misleading. Do you agree that the type of the underlying object is
const int[2]
? Then you should also agree that the element type T
of the array is const int
, and not int
.– Rakete1111
2 hours ago
Yeah, that note is misleading. Do you agree that the type of the underlying object is
const int[2]
? Then you should also agree that the element type T
of the array is const int
, and not int
.– Rakete1111
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of
T
. Or it could be that I'm being thrown off by the phrase "top-level".– Lightness Races in Orbit
2 hours ago
@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of
T
. Or it could be that I'm being thrown off by the phrase "top-level".– Lightness Races in Orbit
2 hours ago
I agree. But cv is not the only cv-qualifier that affects the type of
T
. For another example: If U
is const int
, then saying that the type of something is cv U
with cv being empty, it doesn't mean that U
is not const
.– Rakete1111
1 hour ago
I agree. But cv is not the only cv-qualifier that affects the type of
T
. For another example: If U
is const int
, then saying that the type of something is cv U
with cv being empty, it doesn't mean that U
is not const
.– Rakete1111
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago
|
show 2 more comments
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53726135%2fshall-structured-binding-to-a-copy-of-a-const-c-array-be-const%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago
3
gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago