Shall structured binding to a copy of a const c-array be const?











up vote
18
down vote

favorite
3












Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.










share|improve this question




















  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    4 hours ago








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    3 hours ago















up vote
18
down vote

favorite
3












Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.










share|improve this question




















  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    4 hours ago








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    3 hours ago













up vote
18
down vote

favorite
3









up vote
18
down vote

favorite
3






3





Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.










share|improve this question















Consider this code (demo):



#include <tuple>
#include <type_traits>

struct Ag{int i;int j;};
using T = std::tuple<int,int>;
using Ar = int[2];

const Ag ag {};
const T t {};
const Ar ar {};

void bind_ag(){
auto [i,j] = ag;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_t(){
auto [i,j] = t;
static_assert(std::is_same_v<decltype((i)),int&>);
}
void bind_ar(){
auto [i,j] = ar;
static_assert(std::is_same_v<decltype((i)),int&>); //For GCC
static_assert(std::is_same_v<decltype((i)),const int&>); //For Clang (and standard?)
}


A structured binding to a copy of a const c-array are declared const by Clang and non-const by GCC.



The behavior of GCC for c-array is consistent with the behavior observed for aggregate or tuple-like types.



On the other hand from my reading of the standard, I suppose Clang follows what is written. In [dcl.struct.bind]/1 e has type cv A where A is the type of the initializer expression and the cv is the cv-qualifier of the structured binding declaration. And the type of the initializer expression ar is accordingly to [expr.type]/1 const int[2].



What should be expected? My opinion is that Clang follows the standard. On the other hand I feel the intent was that the behaviors for array, aggregate and tuple-like types were equivalent.







c++ language-lawyer c++17 structured-bindings






share|improve this question















share|improve this question













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share|improve this question








edited 4 hours ago

























asked 4 hours ago









Oliv

7,9631854




7,9631854








  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    4 hours ago








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    3 hours ago














  • 1




    Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
    – Daniel Langr
    4 hours ago








  • 3




    gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
    – cpplearner
    3 hours ago








1




1




Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago






Isn't this note related: eel.is/c++draft/dcl.struct.bind#3.note-1?
– Daniel Langr
4 hours ago






3




3




gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago




gcc.gnu.org/bugzilla/show_bug.cgi?id=86049
– cpplearner
3 hours ago












2 Answers
2






active

oldest

votes

















up vote
9
down vote













The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer





















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    2 hours ago








  • 2




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    2 hours ago










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    2 hours ago










  • Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
    – Oliv
    1 hour ago


















up vote
4
down vote













In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.



The decl-specifier-seq ("auto") has no cv-qualifiers (that is, you did not write const auto), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.




[dcl.struct.bind]/1: [..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]



[dcl.struct.bind]/3: If E is an array type with element type T, the number of elements in the identifier-list shall be equal to the number of elements of E. Each vi is the name of an lvalue that refers to the element i of the array and whose type is T; the referenced type is T. [ Note: The top-level cv-qualifiers of T are cv. — end note ] [..]




Like you, Clang devs have interpreted the auto here as having cv-qualification of const, because the type inferred by it is const Ag. But I see no standard justification for that interpretation.






share|improve this answer





















  • Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
    – Rakete1111
    2 hours ago










  • @Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
    – Lightness Races in Orbit
    2 hours ago












  • I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
    – Rakete1111
    1 hour ago










  • @Rakete1111 Okay, that's convincing.
    – Lightness Races in Orbit
    1 hour ago










  • Either way, that note must go or we should actually fix this inconsistency.
    – Rakete1111
    1 hour ago











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2 Answers
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active

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2 Answers
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active

oldest

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active

oldest

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active

oldest

votes








up vote
9
down vote













The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer





















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    2 hours ago








  • 2




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    2 hours ago










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    2 hours ago










  • Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
    – Oliv
    1 hour ago















up vote
9
down vote













The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer





















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    2 hours ago








  • 2




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    2 hours ago










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    2 hours ago










  • Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
    – Oliv
    1 hour ago













up vote
9
down vote










up vote
9
down vote









The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.






share|improve this answer












The wording of the standard in [dcl.struct.bind] says:




If the assignment-expression in the initializer has array type A and no ref-qualifier is present, e has type cv A and each element is copy-initialized or direct-initialized from the corresponding element of the assignment-expression as specified by the form of the initializer.




We have auto [i,j] = ar;, ar has array type const int[2], and the wording of the standard makes it clear that e has type const int[2]. Thus, per the wording, each binding references the element type - which is const int. Clang is technically correct.



However, as Richard Smith points out in gcc bug 80649:




I think this is a bug in the standard. The cv-qualifiers of the array type should be discarded, as they would be for any normal auto deduction.




That seems right. When you write auto x = y; you'd certainly expect x to not be top-level const, but here we have a situation where it still is. I don't think there's a Core issue open for this yet, but there should be.







share|improve this answer












share|improve this answer



share|improve this answer










answered 3 hours ago









Barry

175k18298553




175k18298553












  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    2 hours ago








  • 2




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    2 hours ago










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    2 hours ago










  • Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
    – Oliv
    1 hour ago


















  • The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
    – Lightness Races in Orbit
    2 hours ago








  • 2




    @LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
    – Barry
    2 hours ago










  • Mm, I could be persuaded by that.
    – Lightness Races in Orbit
    2 hours ago










  • Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
    – Oliv
    1 hour ago
















The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago






The cv-qualification cv comes from the decl-specifier-seq ("auto") not the initialiser ("ar"), no? Unless it's saying that the qualifiers on A are merged into cv. But I don't follow why that would be the case; without a ref-qualifier, why would it want to maintain constness? It doesn't do that anywhere else.
– Lightness Races in Orbit
2 hours ago






2




2




@LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago




@LightnessRacesinOrbit It does - but A is an array of const, so cv A is still an array of const. I don't think we want to maintain constness, hence Core issue.
– Barry
2 hours ago












Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago




Mm, I could be persuaded by that.
– Lightness Races in Orbit
2 hours ago












Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago




Thank you, viewed the comment I think I am going to takes both answer (I am not in a comfortable to put a thick on one or the other).
– Oliv
1 hour ago












up vote
4
down vote













In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.



The decl-specifier-seq ("auto") has no cv-qualifiers (that is, you did not write const auto), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.




[dcl.struct.bind]/1: [..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]



[dcl.struct.bind]/3: If E is an array type with element type T, the number of elements in the identifier-list shall be equal to the number of elements of E. Each vi is the name of an lvalue that refers to the element i of the array and whose type is T; the referenced type is T. [ Note: The top-level cv-qualifiers of T are cv. — end note ] [..]




Like you, Clang devs have interpreted the auto here as having cv-qualification of const, because the type inferred by it is const Ag. But I see no standard justification for that interpretation.






share|improve this answer





















  • Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
    – Rakete1111
    2 hours ago










  • @Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
    – Lightness Races in Orbit
    2 hours ago












  • I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
    – Rakete1111
    1 hour ago










  • @Rakete1111 Okay, that's convincing.
    – Lightness Races in Orbit
    1 hour ago










  • Either way, that note must go or we should actually fix this inconsistency.
    – Rakete1111
    1 hour ago















up vote
4
down vote













In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.



The decl-specifier-seq ("auto") has no cv-qualifiers (that is, you did not write const auto), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.




[dcl.struct.bind]/1: [..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]



[dcl.struct.bind]/3: If E is an array type with element type T, the number of elements in the identifier-list shall be equal to the number of elements of E. Each vi is the name of an lvalue that refers to the element i of the array and whose type is T; the referenced type is T. [ Note: The top-level cv-qualifiers of T are cv. — end note ] [..]




Like you, Clang devs have interpreted the auto here as having cv-qualification of const, because the type inferred by it is const Ag. But I see no standard justification for that interpretation.






share|improve this answer





















  • Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
    – Rakete1111
    2 hours ago










  • @Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
    – Lightness Races in Orbit
    2 hours ago












  • I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
    – Rakete1111
    1 hour ago










  • @Rakete1111 Okay, that's convincing.
    – Lightness Races in Orbit
    1 hour ago










  • Either way, that note must go or we should actually fix this inconsistency.
    – Rakete1111
    1 hour ago













up vote
4
down vote










up vote
4
down vote









In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.



The decl-specifier-seq ("auto") has no cv-qualifiers (that is, you did not write const auto), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.




[dcl.struct.bind]/1: [..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]



[dcl.struct.bind]/3: If E is an array type with element type T, the number of elements in the identifier-list shall be equal to the number of elements of E. Each vi is the name of an lvalue that refers to the element i of the array and whose type is T; the referenced type is T. [ Note: The top-level cv-qualifiers of T are cv. — end note ] [..]




Like you, Clang devs have interpreted the auto here as having cv-qualification of const, because the type inferred by it is const Ag. But I see no standard justification for that interpretation.






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In my opinion, GCC is correct (and, as you pointed out, more intuitive), though certainly some people disagree.



The decl-specifier-seq ("auto") has no cv-qualifiers (that is, you did not write const auto), and that should be what is considered as cv when deciding what qualifiers to put on the bindings.




[dcl.struct.bind]/1: [..] Let cv denote the cv-qualifiers in the decl-specifier-seq. [..]



[dcl.struct.bind]/3: If E is an array type with element type T, the number of elements in the identifier-list shall be equal to the number of elements of E. Each vi is the name of an lvalue that refers to the element i of the array and whose type is T; the referenced type is T. [ Note: The top-level cv-qualifiers of T are cv. — end note ] [..]




Like you, Clang devs have interpreted the auto here as having cv-qualification of const, because the type inferred by it is const Ag. But I see no standard justification for that interpretation.







share|improve this answer












share|improve this answer



share|improve this answer










answered 3 hours ago









Lightness Races in Orbit

281k51453769




281k51453769












  • Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
    – Rakete1111
    2 hours ago










  • @Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
    – Lightness Races in Orbit
    2 hours ago












  • I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
    – Rakete1111
    1 hour ago










  • @Rakete1111 Okay, that's convincing.
    – Lightness Races in Orbit
    1 hour ago










  • Either way, that note must go or we should actually fix this inconsistency.
    – Rakete1111
    1 hour ago


















  • Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
    – Rakete1111
    2 hours ago










  • @Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
    – Lightness Races in Orbit
    2 hours ago












  • I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
    – Rakete1111
    1 hour ago










  • @Rakete1111 Okay, that's convincing.
    – Lightness Races in Orbit
    1 hour ago










  • Either way, that note must go or we should actually fix this inconsistency.
    – Rakete1111
    1 hour ago
















Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
– Rakete1111
2 hours ago




Yeah, that note is misleading. Do you agree that the type of the underlying object is const int[2]? Then you should also agree that the element type T of the array is const int, and not int.
– Rakete1111
2 hours ago












@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago






@Rakete1111 Yes, but the cv-qualifiers in the decl-specifier-seq, and thus cv, are none-ness. And it is cv that determines the cv-qualifiers of T. Or it could be that I'm being thrown off by the phrase "top-level".
– Lightness Races in Orbit
2 hours ago














I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
– Rakete1111
1 hour ago




I agree. But cv is not the only cv-qualifier that affects the type of T. For another example: If U is const int, then saying that the type of something is cv U with cv being empty, it doesn't mean that U is not const.
– Rakete1111
1 hour ago












@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago




@Rakete1111 Okay, that's convincing.
– Lightness Races in Orbit
1 hour ago












Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago




Either way, that note must go or we should actually fix this inconsistency.
– Rakete1111
1 hour ago


















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