Python 3.6+ function to ask for a multiple-choice answer
$begingroup$
# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer
I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?
python python-3.x validation
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer
I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?
python python-3.x validation
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
"The loop will never reach it's end ... Is thewhile Truecondition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
11 hours ago
1
$begingroup$
Side note:for x in len(options):will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, usefor x in range(len(options)):if you really need to loop a certain number of times. This takes thelen(options)integer and creates an interable out of it.
$endgroup$
– JDG
9 hours ago
add a comment |
$begingroup$
# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer
I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?
python python-3.x validation
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in range(len(options)):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer
I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?
python python-3.x validation
python python-3.x validation
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 13 mins ago
Holyprogrammer
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
asked 11 hours ago
HolyprogrammerHolyprogrammer
1568
1568
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
"The loop will never reach it's end ... Is thewhile Truecondition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
11 hours ago
1
$begingroup$
Side note:for x in len(options):will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, usefor x in range(len(options)):if you really need to loop a certain number of times. This takes thelen(options)integer and creates an interable out of it.
$endgroup$
– JDG
9 hours ago
add a comment |
$begingroup$
"The loop will never reach it's end ... Is thewhile Truecondition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
11 hours ago
1
$begingroup$
Side note:for x in len(options):will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, usefor x in range(len(options)):if you really need to loop a certain number of times. This takes thelen(options)integer and creates an interable out of it.
$endgroup$
– JDG
9 hours ago
$begingroup$
"The loop will never reach it's end ... Is the
while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?$endgroup$
– Mast
11 hours ago
$begingroup$
"The loop will never reach it's end ... Is the
while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?$endgroup$
– Mast
11 hours ago
1
1
$begingroup$
Side note:
for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.$endgroup$
– JDG
9 hours ago
$begingroup$
Side note:
for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.$endgroup$
– JDG
9 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.
PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.
The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.
def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print(f'{i}. {option}')
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")
edited 31 secs ago
Holyprogrammer
1568
answered 11 hours ago
200_success200_success
130k16153419
$endgroup$
2
$begingroup$
Is it standard now in python 3.x to use f-strings?print(f'{i}. {option}')
$endgroup$
– JDG
9 hours ago
add a comment |
$begingroup$
I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:
print("Enter the number of your choice -",
*(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
sep='n', end='nn')
Explanation:
from the docs we see that following signature for the print function:
print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)
we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.
answered 5 hours ago
magu_magu_
4931519
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.
PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.
The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.
def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print(f'{i}. {option}')
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")
edited 31 secs ago
Holyprogrammer
1568
answered 11 hours ago
200_success200_success
130k16153419
$endgroup$
2
$begingroup$
Is it standard now in python 3.x to use f-strings?print(f'{i}. {option}')
$endgroup$
– JDG
9 hours ago
add a comment |
$begingroup$
The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.
PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.
The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.
def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print(f'{i}. {option}')
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")
edited 31 secs ago
Holyprogrammer
1568
answered 11 hours ago
200_success200_success
130k16153419
$endgroup$
2
$begingroup$
Is it standard now in python 3.x to use f-strings?print(f'{i}. {option}')
$endgroup$
– JDG
9 hours ago
add a comment |
$begingroup$
The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.
PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.
The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.
def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print(f'{i}. {option}')
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")
edited 31 secs ago
Holyprogrammer
1568
answered 11 hours ago
200_success200_success
130k16153419
$endgroup$
The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.
PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.
The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.
def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print(f'{i}. {option}')
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")
edited 31 secs ago
Holyprogrammer
1568
answered 11 hours ago
200_success200_success
130k16153419
edited 31 secs ago
Holyprogrammer
1568
edited 31 secs ago
Holyprogrammer
1568
edited 31 secs ago
Holyprogrammer
1568
1568
answered 11 hours ago
200_success200_success
130k16153419
answered 11 hours ago
200_success200_success
130k16153419
answered 11 hours ago
200_success200_success
130k16153419
130k16153419
2
$begingroup$
Is it standard now in python 3.x to use f-strings?print(f'{i}. {option}')
$endgroup$
– JDG
9 hours ago
add a comment |
2
$begingroup$
Is it standard now in python 3.x to use f-strings?print(f'{i}. {option}')
$endgroup$
– JDG
9 hours ago
2
2
$begingroup$
Is it standard now in python 3.x to use f-strings?
print(f'{i}. {option}')$endgroup$
– JDG
9 hours ago
$begingroup$
Is it standard now in python 3.x to use f-strings?
print(f'{i}. {option}')$endgroup$
– JDG
9 hours ago
add a comment |
$begingroup$
I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:
print("Enter the number of your choice -",
*(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
sep='n', end='nn')
Explanation:
from the docs we see that following signature for the print function:
print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)
we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.
answered 5 hours ago
magu_magu_
4931519
$endgroup$
add a comment |
$begingroup$
I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:
print("Enter the number of your choice -",
*(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
sep='n', end='nn')
Explanation:
from the docs we see that following signature for the print function:
print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)
we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.
answered 5 hours ago
magu_magu_
4931519
$endgroup$
add a comment |
$begingroup$
I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:
print("Enter the number of your choice -",
*(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
sep='n', end='nn')
Explanation:
from the docs we see that following signature for the print function:
print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)
we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.
answered 5 hours ago
magu_magu_
4931519
$endgroup$
I think that 200_success already covered most points. I would however like to add an alternative idea for the printing part:
print("Enter the number of your choice -",
*(f'{i}. {opt}' for i, opt in enumerate(options, 1)),
sep='n', end='nn')
Explanation:
from the docs we see that following signature for the print function:
print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)
we can therefore print everything with a single print call instead of three individual ones. I leave it up to you which one you perceive easier to use.
answered 5 hours ago
magu_magu_
4931519
answered 5 hours ago
magu_magu_
4931519
answered 5 hours ago
magu_magu_
4931519
answered 5 hours ago
magu_magu_
4931519
4931519
add a comment |
add a comment |
Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.
Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.
Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.
Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
"The loop will never reach it's end ... Is the
while Truecondition appropriate for it?" That depends on whether that is the intended behaviour. Is it?$endgroup$
– Mast
11 hours ago
1
$begingroup$
Side note:
for x in len(options):will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, usefor x in range(len(options)):if you really need to loop a certain number of times. This takes thelen(options)integer and creates an interable out of it.$endgroup$
– JDG
9 hours ago