How to take list to number?
up vote
1
down vote
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I have a list such as:
a = {1, 2, 4, 3};
and I want to get the 'number' of the list. For this example, I want to get this number: 1243. I do not know how to get it easily. For now, my solution is:
a[[1]]*10^3+a[[2]]*10^2+a[[3]]*10^1+a[[4]];
It works. But it is too complex. I want to know a way more convenient.
functions special-functions
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
asked 1 hour ago
user61054
161
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up vote
1
down vote
favorite
I have a list such as:
a = {1, 2, 4, 3};
and I want to get the 'number' of the list. For this example, I want to get this number: 1243. I do not know how to get it easily. For now, my solution is:
a[[1]]*10^3+a[[2]]*10^2+a[[3]]*10^1+a[[4]];
It works. But it is too complex. I want to know a way more convenient.
functions special-functions
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
asked 1 hour ago
user61054
161
New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have a list such as:
a = {1, 2, 4, 3};
and I want to get the 'number' of the list. For this example, I want to get this number: 1243. I do not know how to get it easily. For now, my solution is:
a[[1]]*10^3+a[[2]]*10^2+a[[3]]*10^1+a[[4]];
It works. But it is too complex. I want to know a way more convenient.
functions special-functions
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
asked 1 hour ago
user61054
161
New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have a list such as:
a = {1, 2, 4, 3};
and I want to get the 'number' of the list. For this example, I want to get this number: 1243. I do not know how to get it easily. For now, my solution is:
a[[1]]*10^3+a[[2]]*10^2+a[[3]]*10^1+a[[4]];
It works. But it is too complex. I want to know a way more convenient.
functions special-functions
functions special-functions
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
asked 1 hour ago
user61054
161
New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
asked 1 hour ago
user61054
161
New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
edited 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
3,6431927
asked 1 hour ago
user61054
161
New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
user61054
161
asked 1 hour ago
user61054
161
161
New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
user61054 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
add a comment |
4 Answers
4
active
oldest
votes
up vote
2
down vote
a={1,2,4,3};
FromDigits[a]
(* 1234 *)
answered 1 hour ago
Mike Honeychurch
30.8k268143
add a comment |
up vote
1
down vote
Other than the built-in FromDigits, we can build our wheel
Fold[{10, 1}.{##} &, a]
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
add a comment |
up vote
0
down vote
Best way would be to use build-in function FromDigits as shown above.
But just in case you'd like a convoluted way to do it, here is another option
a = {1, 2, 4, 3};
ToExpression[StringJoin[ToString[#] & /@ a]]
answered 15 mins ago
Nasser
57.1k486205
add a comment |
up vote
0
down vote
These are some methods I would not recommend:
lst = {1, 2, 3, 4};
f = (Curry[StringRiffle][""] /* ToExpression);
g = (Through[{
Identity,
Length /* Range /* Reverse /* Curry[Plus][-1] /* Curry[Power, 2][10]
}[#]] & /* MapThread[Times] /* Total);
f[lst] (* 1234 *)
g[lst] (* 1234 *)
answered 3 mins ago
Shredderroy
1,4181115
add a comment |
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
a={1,2,4,3};
FromDigits[a]
(* 1234 *)
answered 1 hour ago
Mike Honeychurch
30.8k268143
add a comment |
up vote
2
down vote
a={1,2,4,3};
FromDigits[a]
(* 1234 *)
answered 1 hour ago
Mike Honeychurch
30.8k268143
add a comment |
up vote
2
down vote
up vote
2
down vote
a={1,2,4,3};
FromDigits[a]
(* 1234 *)
answered 1 hour ago
Mike Honeychurch
30.8k268143
a={1,2,4,3};
FromDigits[a]
(* 1234 *)
answered 1 hour ago
Mike Honeychurch
30.8k268143
answered 1 hour ago
Mike Honeychurch
30.8k268143
answered 1 hour ago
Mike Honeychurch
30.8k268143
answered 1 hour ago
Mike Honeychurch
30.8k268143
30.8k268143
add a comment |
add a comment |
up vote
1
down vote
Other than the built-in FromDigits, we can build our wheel
Fold[{10, 1}.{##} &, a]
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
add a comment |
up vote
1
down vote
Other than the built-in FromDigits, we can build our wheel
Fold[{10, 1}.{##} &, a]
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
add a comment |
up vote
1
down vote
up vote
1
down vote
Other than the built-in FromDigits, we can build our wheel
Fold[{10, 1}.{##} &, a]
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
Other than the built-in FromDigits, we can build our wheel
Fold[{10, 1}.{##} &, a]
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
answered 1 hour ago
Αλέξανδρος Ζεγγ
3,6431927
3,6431927
add a comment |
add a comment |
up vote
0
down vote
Best way would be to use build-in function FromDigits as shown above.
But just in case you'd like a convoluted way to do it, here is another option
a = {1, 2, 4, 3};
ToExpression[StringJoin[ToString[#] & /@ a]]
answered 15 mins ago
Nasser
57.1k486205
add a comment |
up vote
0
down vote
Best way would be to use build-in function FromDigits as shown above.
But just in case you'd like a convoluted way to do it, here is another option
a = {1, 2, 4, 3};
ToExpression[StringJoin[ToString[#] & /@ a]]
answered 15 mins ago
Nasser
57.1k486205
add a comment |
up vote
0
down vote
up vote
0
down vote
Best way would be to use build-in function FromDigits as shown above.
But just in case you'd like a convoluted way to do it, here is another option
a = {1, 2, 4, 3};
ToExpression[StringJoin[ToString[#] & /@ a]]
answered 15 mins ago
Nasser
57.1k486205
Best way would be to use build-in function FromDigits as shown above.
But just in case you'd like a convoluted way to do it, here is another option
a = {1, 2, 4, 3};
ToExpression[StringJoin[ToString[#] & /@ a]]
answered 15 mins ago
Nasser
57.1k486205
answered 15 mins ago
Nasser
57.1k486205
answered 15 mins ago
Nasser
57.1k486205
answered 15 mins ago
Nasser
57.1k486205
57.1k486205
add a comment |
add a comment |
up vote
0
down vote
These are some methods I would not recommend:
lst = {1, 2, 3, 4};
f = (Curry[StringRiffle][""] /* ToExpression);
g = (Through[{
Identity,
Length /* Range /* Reverse /* Curry[Plus][-1] /* Curry[Power, 2][10]
}[#]] & /* MapThread[Times] /* Total);
f[lst] (* 1234 *)
g[lst] (* 1234 *)
answered 3 mins ago
Shredderroy
1,4181115
add a comment |
up vote
0
down vote
These are some methods I would not recommend:
lst = {1, 2, 3, 4};
f = (Curry[StringRiffle][""] /* ToExpression);
g = (Through[{
Identity,
Length /* Range /* Reverse /* Curry[Plus][-1] /* Curry[Power, 2][10]
}[#]] & /* MapThread[Times] /* Total);
f[lst] (* 1234 *)
g[lst] (* 1234 *)
answered 3 mins ago
Shredderroy
1,4181115
add a comment |
up vote
0
down vote
up vote
0
down vote
These are some methods I would not recommend:
lst = {1, 2, 3, 4};
f = (Curry[StringRiffle][""] /* ToExpression);
g = (Through[{
Identity,
Length /* Range /* Reverse /* Curry[Plus][-1] /* Curry[Power, 2][10]
}[#]] & /* MapThread[Times] /* Total);
f[lst] (* 1234 *)
g[lst] (* 1234 *)
answered 3 mins ago
Shredderroy
1,4181115
These are some methods I would not recommend:
lst = {1, 2, 3, 4};
f = (Curry[StringRiffle][""] /* ToExpression);
g = (Through[{
Identity,
Length /* Range /* Reverse /* Curry[Plus][-1] /* Curry[Power, 2][10]
}[#]] & /* MapThread[Times] /* Total);
f[lst] (* 1234 *)
g[lst] (* 1234 *)
answered 3 mins ago
Shredderroy
1,4181115
answered 3 mins ago
Shredderroy
1,4181115
answered 3 mins ago
Shredderroy
1,4181115
answered 3 mins ago
Shredderroy
1,4181115
1,4181115
add a comment |
add a comment |
user61054 is a new contributor. Be nice, and check out our Code of Conduct.
user61054 is a new contributor. Be nice, and check out our Code of Conduct.
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