How can I use a reference call variable in a Hyperlink as part of the file name to be opened?











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The following solution worked perfect except that I want to only include a specific part of the file name in the cell being referenced.



=HYPERLINK("D:My DocumentsCoin PicturesGraded Coins" & [@[Agency File]] & ".JPG" , "File" )


In the above [@[Agency]] is a number like "123456-001" in a table.
This works perfect if I change the file name to "123456-001.JPG".



The JPEG file name actually has more detail leading up to the "Agency Number".
Such as "NIUE, Star Wars, Silver, 1, 2, NGC, 123456-001.JPG".



I tried variants of adding & "*" & before the reference to the Agency File Number cell.
All assistance would be appreciated.










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  • Do you try the INDIRECT function?
    – Lee
    Nov 26 at 8:28















up vote
0
down vote

favorite












The following solution worked perfect except that I want to only include a specific part of the file name in the cell being referenced.



=HYPERLINK("D:My DocumentsCoin PicturesGraded Coins" & [@[Agency File]] & ".JPG" , "File" )


In the above [@[Agency]] is a number like "123456-001" in a table.
This works perfect if I change the file name to "123456-001.JPG".



The JPEG file name actually has more detail leading up to the "Agency Number".
Such as "NIUE, Star Wars, Silver, 1, 2, NGC, 123456-001.JPG".



I tried variants of adding & "*" & before the reference to the Agency File Number cell.
All assistance would be appreciated.










share|improve this question









New contributor




Randy H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Do you try the INDIRECT function?
    – Lee
    Nov 26 at 8:28













up vote
0
down vote

favorite









up vote
0
down vote

favorite











The following solution worked perfect except that I want to only include a specific part of the file name in the cell being referenced.



=HYPERLINK("D:My DocumentsCoin PicturesGraded Coins" & [@[Agency File]] & ".JPG" , "File" )


In the above [@[Agency]] is a number like "123456-001" in a table.
This works perfect if I change the file name to "123456-001.JPG".



The JPEG file name actually has more detail leading up to the "Agency Number".
Such as "NIUE, Star Wars, Silver, 1, 2, NGC, 123456-001.JPG".



I tried variants of adding & "*" & before the reference to the Agency File Number cell.
All assistance would be appreciated.










share|improve this question









New contributor




Randy H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











The following solution worked perfect except that I want to only include a specific part of the file name in the cell being referenced.



=HYPERLINK("D:My DocumentsCoin PicturesGraded Coins" & [@[Agency File]] & ".JPG" , "File" )


In the above [@[Agency]] is a number like "123456-001" in a table.
This works perfect if I change the file name to "123456-001.JPG".



The JPEG file name actually has more detail leading up to the "Agency Number".
Such as "NIUE, Star Wars, Silver, 1, 2, NGC, 123456-001.JPG".



I tried variants of adding & "*" & before the reference to the Agency File Number cell.
All assistance would be appreciated.







microsoft-excel hyperlink






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edited 2 days ago









PeterH

3,14132245




3,14132245






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asked Nov 25 at 17:51









Randy H

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  • Do you try the INDIRECT function?
    – Lee
    Nov 26 at 8:28


















  • Do you try the INDIRECT function?
    – Lee
    Nov 26 at 8:28
















Do you try the INDIRECT function?
– Lee
Nov 26 at 8:28




Do you try the INDIRECT function?
– Lee
Nov 26 at 8:28















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