using sed replace the new line with character












3














I am using sed to remove the new line and replace with <br> but I am not able to get the desired output.



I wrote:



find . -name $1 -print0 | xargs -0 sed -i '' -e 's|n|ABC|g'


...but this doesn't work.










share|improve this question
























  • possible duplicate of Find and replace text within a file using commands
    – Pandya
    Sep 26 '14 at 16:01










  • You can invoke programs on find results a bit more elegantly with the -exec action: find . -name $1 -exec sed -i '' -e 's|n|ABC|g' {} +
    – David Foerster
    Sep 26 '14 at 16:12










  • @Pandya I don't believe this is a duplicate, the OP is already using what that question would suggest, he just needs help getting the exact command for his specific environment correct, which that question won't provide.
    – Seth
    Sep 26 '14 at 16:19






  • 1




    You can use tr 'n' '<br>' < file
    – Pandya
    Sep 27 '14 at 2:14
















3














I am using sed to remove the new line and replace with <br> but I am not able to get the desired output.



I wrote:



find . -name $1 -print0 | xargs -0 sed -i '' -e 's|n|ABC|g'


...but this doesn't work.










share|improve this question
























  • possible duplicate of Find and replace text within a file using commands
    – Pandya
    Sep 26 '14 at 16:01










  • You can invoke programs on find results a bit more elegantly with the -exec action: find . -name $1 -exec sed -i '' -e 's|n|ABC|g' {} +
    – David Foerster
    Sep 26 '14 at 16:12










  • @Pandya I don't believe this is a duplicate, the OP is already using what that question would suggest, he just needs help getting the exact command for his specific environment correct, which that question won't provide.
    – Seth
    Sep 26 '14 at 16:19






  • 1




    You can use tr 'n' '<br>' < file
    – Pandya
    Sep 27 '14 at 2:14














3












3








3







I am using sed to remove the new line and replace with <br> but I am not able to get the desired output.



I wrote:



find . -name $1 -print0 | xargs -0 sed -i '' -e 's|n|ABC|g'


...but this doesn't work.










share|improve this question















I am using sed to remove the new line and replace with <br> but I am not able to get the desired output.



I wrote:



find . -name $1 -print0 | xargs -0 sed -i '' -e 's|n|ABC|g'


...but this doesn't work.







scripts sed text-processing






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 25 '18 at 9:27









agc

1409




1409










asked Sep 26 '14 at 14:21









abhijeetmoteabhijeetmote

236




236












  • possible duplicate of Find and replace text within a file using commands
    – Pandya
    Sep 26 '14 at 16:01










  • You can invoke programs on find results a bit more elegantly with the -exec action: find . -name $1 -exec sed -i '' -e 's|n|ABC|g' {} +
    – David Foerster
    Sep 26 '14 at 16:12










  • @Pandya I don't believe this is a duplicate, the OP is already using what that question would suggest, he just needs help getting the exact command for his specific environment correct, which that question won't provide.
    – Seth
    Sep 26 '14 at 16:19






  • 1




    You can use tr 'n' '<br>' < file
    – Pandya
    Sep 27 '14 at 2:14


















  • possible duplicate of Find and replace text within a file using commands
    – Pandya
    Sep 26 '14 at 16:01










  • You can invoke programs on find results a bit more elegantly with the -exec action: find . -name $1 -exec sed -i '' -e 's|n|ABC|g' {} +
    – David Foerster
    Sep 26 '14 at 16:12










  • @Pandya I don't believe this is a duplicate, the OP is already using what that question would suggest, he just needs help getting the exact command for his specific environment correct, which that question won't provide.
    – Seth
    Sep 26 '14 at 16:19






  • 1




    You can use tr 'n' '<br>' < file
    – Pandya
    Sep 27 '14 at 2:14
















possible duplicate of Find and replace text within a file using commands
– Pandya
Sep 26 '14 at 16:01




possible duplicate of Find and replace text within a file using commands
– Pandya
Sep 26 '14 at 16:01












You can invoke programs on find results a bit more elegantly with the -exec action: find . -name $1 -exec sed -i '' -e 's|n|ABC|g' {} +
– David Foerster
Sep 26 '14 at 16:12




You can invoke programs on find results a bit more elegantly with the -exec action: find . -name $1 -exec sed -i '' -e 's|n|ABC|g' {} +
– David Foerster
Sep 26 '14 at 16:12












@Pandya I don't believe this is a duplicate, the OP is already using what that question would suggest, he just needs help getting the exact command for his specific environment correct, which that question won't provide.
– Seth
Sep 26 '14 at 16:19




@Pandya I don't believe this is a duplicate, the OP is already using what that question would suggest, he just needs help getting the exact command for his specific environment correct, which that question won't provide.
– Seth
Sep 26 '14 at 16:19




1




1




You can use tr 'n' '<br>' < file
– Pandya
Sep 27 '14 at 2:14




You can use tr 'n' '<br>' < file
– Pandya
Sep 27 '14 at 2:14










4 Answers
4






active

oldest

votes


















2














Your sed expression is treating each line separately - so it doesn't actually read the newline character into the pattern buffer and hence can't replace it. If you just want to add <br> while retaining the actual newline as well, you can just use the end-of-line marker $ and do



sed -i'' 's|$|<br>|' file


Note that the empty backup file name - if you use it - must directly follow the -i like -i''; also the -e is not necessary when using a single expression.



OTOH if you really want to replace actual newline characters, you need to jump through some extra hoops, for example



sed -i'' -e :a -e '$!N;s/n/<br>/;ta' -e 'P;D' file


or, more compactly



sed -i'' ':a; $!N; s|n|<br>|; ta; P;D' file


which read successive pairs of lines into the pattern buffer and then replace the intervening newline - see Famous Sed One-Liners Explained.






share|improve this answer





























    0














    If you want to replace the new line and with <br>, you can use



     find . -name $1 -print0 | xargs -0 sed -i 's/.*$/&<br>/'





    share|improve this answer





























      0














      Why not just



      find . -name $1 | xargs sed -ri "s/$/<br>/"



      ?



      (Try without the i, first ;-) )






      share|improve this answer





























        0














        To replace inline n with <br>, just use perl (or sed), needless to call find for that task:



        perl -pi -e "s/$/<br>/" myfile


        Or for an alias:



        alias brtag='perl -pi -e "s/$/<br>/" $1'





        share|improve this answer





















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          4 Answers
          4






          active

          oldest

          votes








          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          Your sed expression is treating each line separately - so it doesn't actually read the newline character into the pattern buffer and hence can't replace it. If you just want to add <br> while retaining the actual newline as well, you can just use the end-of-line marker $ and do



          sed -i'' 's|$|<br>|' file


          Note that the empty backup file name - if you use it - must directly follow the -i like -i''; also the -e is not necessary when using a single expression.



          OTOH if you really want to replace actual newline characters, you need to jump through some extra hoops, for example



          sed -i'' -e :a -e '$!N;s/n/<br>/;ta' -e 'P;D' file


          or, more compactly



          sed -i'' ':a; $!N; s|n|<br>|; ta; P;D' file


          which read successive pairs of lines into the pattern buffer and then replace the intervening newline - see Famous Sed One-Liners Explained.






          share|improve this answer


























            2














            Your sed expression is treating each line separately - so it doesn't actually read the newline character into the pattern buffer and hence can't replace it. If you just want to add <br> while retaining the actual newline as well, you can just use the end-of-line marker $ and do



            sed -i'' 's|$|<br>|' file


            Note that the empty backup file name - if you use it - must directly follow the -i like -i''; also the -e is not necessary when using a single expression.



            OTOH if you really want to replace actual newline characters, you need to jump through some extra hoops, for example



            sed -i'' -e :a -e '$!N;s/n/<br>/;ta' -e 'P;D' file


            or, more compactly



            sed -i'' ':a; $!N; s|n|<br>|; ta; P;D' file


            which read successive pairs of lines into the pattern buffer and then replace the intervening newline - see Famous Sed One-Liners Explained.






            share|improve this answer
























              2












              2








              2






              Your sed expression is treating each line separately - so it doesn't actually read the newline character into the pattern buffer and hence can't replace it. If you just want to add <br> while retaining the actual newline as well, you can just use the end-of-line marker $ and do



              sed -i'' 's|$|<br>|' file


              Note that the empty backup file name - if you use it - must directly follow the -i like -i''; also the -e is not necessary when using a single expression.



              OTOH if you really want to replace actual newline characters, you need to jump through some extra hoops, for example



              sed -i'' -e :a -e '$!N;s/n/<br>/;ta' -e 'P;D' file


              or, more compactly



              sed -i'' ':a; $!N; s|n|<br>|; ta; P;D' file


              which read successive pairs of lines into the pattern buffer and then replace the intervening newline - see Famous Sed One-Liners Explained.






              share|improve this answer












              Your sed expression is treating each line separately - so it doesn't actually read the newline character into the pattern buffer and hence can't replace it. If you just want to add <br> while retaining the actual newline as well, you can just use the end-of-line marker $ and do



              sed -i'' 's|$|<br>|' file


              Note that the empty backup file name - if you use it - must directly follow the -i like -i''; also the -e is not necessary when using a single expression.



              OTOH if you really want to replace actual newline characters, you need to jump through some extra hoops, for example



              sed -i'' -e :a -e '$!N;s/n/<br>/;ta' -e 'P;D' file


              or, more compactly



              sed -i'' ':a; $!N; s|n|<br>|; ta; P;D' file


              which read successive pairs of lines into the pattern buffer and then replace the intervening newline - see Famous Sed One-Liners Explained.







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Sep 26 '14 at 14:57









              steeldriversteeldriver

              66k11105178




              66k11105178

























                  0














                  If you want to replace the new line and with <br>, you can use



                   find . -name $1 -print0 | xargs -0 sed -i 's/.*$/&<br>/'





                  share|improve this answer


























                    0














                    If you want to replace the new line and with <br>, you can use



                     find . -name $1 -print0 | xargs -0 sed -i 's/.*$/&<br>/'





                    share|improve this answer
























                      0












                      0








                      0






                      If you want to replace the new line and with <br>, you can use



                       find . -name $1 -print0 | xargs -0 sed -i 's/.*$/&<br>/'





                      share|improve this answer












                      If you want to replace the new line and with <br>, you can use



                       find . -name $1 -print0 | xargs -0 sed -i 's/.*$/&<br>/'






                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered Sep 26 '14 at 14:42









                      g_pg_p

                      12.5k24461




                      12.5k24461























                          0














                          Why not just



                          find . -name $1 | xargs sed -ri "s/$/<br>/"



                          ?



                          (Try without the i, first ;-) )






                          share|improve this answer


























                            0














                            Why not just



                            find . -name $1 | xargs sed -ri "s/$/<br>/"



                            ?



                            (Try without the i, first ;-) )






                            share|improve this answer
























                              0












                              0








                              0






                              Why not just



                              find . -name $1 | xargs sed -ri "s/$/<br>/"



                              ?



                              (Try without the i, first ;-) )






                              share|improve this answer












                              Why not just



                              find . -name $1 | xargs sed -ri "s/$/<br>/"



                              ?



                              (Try without the i, first ;-) )







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Sep 26 '14 at 14:44









                              laruisslaruiss

                              1112




                              1112























                                  0














                                  To replace inline n with <br>, just use perl (or sed), needless to call find for that task:



                                  perl -pi -e "s/$/<br>/" myfile


                                  Or for an alias:



                                  alias brtag='perl -pi -e "s/$/<br>/" $1'





                                  share|improve this answer


























                                    0














                                    To replace inline n with <br>, just use perl (or sed), needless to call find for that task:



                                    perl -pi -e "s/$/<br>/" myfile


                                    Or for an alias:



                                    alias brtag='perl -pi -e "s/$/<br>/" $1'





                                    share|improve this answer
























                                      0












                                      0








                                      0






                                      To replace inline n with <br>, just use perl (or sed), needless to call find for that task:



                                      perl -pi -e "s/$/<br>/" myfile


                                      Or for an alias:



                                      alias brtag='perl -pi -e "s/$/<br>/" $1'





                                      share|improve this answer












                                      To replace inline n with <br>, just use perl (or sed), needless to call find for that task:



                                      perl -pi -e "s/$/<br>/" myfile


                                      Or for an alias:



                                      alias brtag='perl -pi -e "s/$/<br>/" $1'






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered Sep 26 '14 at 14:53









                                      Sylvain PineauSylvain Pineau

                                      48.4k16104149




                                      48.4k16104149






























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