What are the advantages/disavantages on using CCM or DCM in boost converter? [closed]
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When should we choose continuous conduction mode (or discontinuous) when designing a boost converter?
power-electronics
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
closed as too broad by Marcus Müller, Elliot Alderson, Andy aka, Finbarr, Dave Tweed♦ Dec 7 at 14:15
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
4
down vote
favorite
When should we choose continuous conduction mode (or discontinuous) when designing a boost converter?
power-electronics
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
closed as too broad by Marcus Müller, Elliot Alderson, Andy aka, Finbarr, Dave Tweed♦ Dec 7 at 14:15
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
To me this is too broad a topic for this site - we try to focus on specific issues and provide specific answers. To fully answer this will require an extensive discussion of both control and power electronics theory. Perhaps you should narrow your question to only one of the three you posted - either advantages/disadvantages, applications, or choice.
– Adam Lawrence
Dec 5 at 16:51
1
@AdamLawrence took your advice. Erased the part of applications and I think the choice is covered with advantages/disdvantages because one can clearly infer whether to use one or another if we are aware of the advantages of each mode.
– Miguel Duran Diaz
Dec 5 at 16:55
DCM may have HUGE RINGING on the switching node, thus huge radiated EMI, or huge electric-field interference for microseconds.
– analogsystemsrf
Dec 5 at 17:07
1
I think it's not as clear cut as your question implies. I personally believe that if you design it to be in CCM for "fuller" loads then you have to accept that it will drop into DCM on light loads hence you don't really choose BUT if, in your question you can paint scenarios for a given load voltage, load current and supply voltage range (yes the supply voltage range is very important) then a fair comparison can be made. I think you'll find that it is difficult to constrain a design with requirements that make CCM an exclusive turn-to solution.
– Andy aka
Dec 5 at 17:45
Looks like your revised question has attracted some attention now, which is all we can hope for. Good to see!
– Adam Lawrence
Dec 6 at 13:07
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
When should we choose continuous conduction mode (or discontinuous) when designing a boost converter?
power-electronics
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
When should we choose continuous conduction mode (or discontinuous) when designing a boost converter?
power-electronics
power-electronics
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
edited Dec 5 at 16:53
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
asked Dec 5 at 16:35
Miguel Duran Diaz
1008
1008
closed as too broad by Marcus Müller, Elliot Alderson, Andy aka, Finbarr, Dave Tweed♦ Dec 7 at 14:15
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as too broad by Marcus Müller, Elliot Alderson, Andy aka, Finbarr, Dave Tweed♦ Dec 7 at 14:15
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
To me this is too broad a topic for this site - we try to focus on specific issues and provide specific answers. To fully answer this will require an extensive discussion of both control and power electronics theory. Perhaps you should narrow your question to only one of the three you posted - either advantages/disadvantages, applications, or choice.
– Adam Lawrence
Dec 5 at 16:51
1
@AdamLawrence took your advice. Erased the part of applications and I think the choice is covered with advantages/disdvantages because one can clearly infer whether to use one or another if we are aware of the advantages of each mode.
– Miguel Duran Diaz
Dec 5 at 16:55
DCM may have HUGE RINGING on the switching node, thus huge radiated EMI, or huge electric-field interference for microseconds.
– analogsystemsrf
Dec 5 at 17:07
1
I think it's not as clear cut as your question implies. I personally believe that if you design it to be in CCM for "fuller" loads then you have to accept that it will drop into DCM on light loads hence you don't really choose BUT if, in your question you can paint scenarios for a given load voltage, load current and supply voltage range (yes the supply voltage range is very important) then a fair comparison can be made. I think you'll find that it is difficult to constrain a design with requirements that make CCM an exclusive turn-to solution.
– Andy aka
Dec 5 at 17:45
Looks like your revised question has attracted some attention now, which is all we can hope for. Good to see!
– Adam Lawrence
Dec 6 at 13:07
add a comment |
2
To me this is too broad a topic for this site - we try to focus on specific issues and provide specific answers. To fully answer this will require an extensive discussion of both control and power electronics theory. Perhaps you should narrow your question to only one of the three you posted - either advantages/disadvantages, applications, or choice.
– Adam Lawrence
Dec 5 at 16:51
1
@AdamLawrence took your advice. Erased the part of applications and I think the choice is covered with advantages/disdvantages because one can clearly infer whether to use one or another if we are aware of the advantages of each mode.
– Miguel Duran Diaz
Dec 5 at 16:55
DCM may have HUGE RINGING on the switching node, thus huge radiated EMI, or huge electric-field interference for microseconds.
– analogsystemsrf
Dec 5 at 17:07
1
I think it's not as clear cut as your question implies. I personally believe that if you design it to be in CCM for "fuller" loads then you have to accept that it will drop into DCM on light loads hence you don't really choose BUT if, in your question you can paint scenarios for a given load voltage, load current and supply voltage range (yes the supply voltage range is very important) then a fair comparison can be made. I think you'll find that it is difficult to constrain a design with requirements that make CCM an exclusive turn-to solution.
– Andy aka
Dec 5 at 17:45
Looks like your revised question has attracted some attention now, which is all we can hope for. Good to see!
– Adam Lawrence
Dec 6 at 13:07
2
2
To me this is too broad a topic for this site - we try to focus on specific issues and provide specific answers. To fully answer this will require an extensive discussion of both control and power electronics theory. Perhaps you should narrow your question to only one of the three you posted - either advantages/disadvantages, applications, or choice.
– Adam Lawrence
Dec 5 at 16:51
To me this is too broad a topic for this site - we try to focus on specific issues and provide specific answers. To fully answer this will require an extensive discussion of both control and power electronics theory. Perhaps you should narrow your question to only one of the three you posted - either advantages/disadvantages, applications, or choice.
– Adam Lawrence
Dec 5 at 16:51
1
1
@AdamLawrence took your advice. Erased the part of applications and I think the choice is covered with advantages/disdvantages because one can clearly infer whether to use one or another if we are aware of the advantages of each mode.
– Miguel Duran Diaz
Dec 5 at 16:55
@AdamLawrence took your advice. Erased the part of applications and I think the choice is covered with advantages/disdvantages because one can clearly infer whether to use one or another if we are aware of the advantages of each mode.
– Miguel Duran Diaz
Dec 5 at 16:55
DCM may have HUGE RINGING on the switching node, thus huge radiated EMI, or huge electric-field interference for microseconds.
– analogsystemsrf
Dec 5 at 17:07
DCM may have HUGE RINGING on the switching node, thus huge radiated EMI, or huge electric-field interference for microseconds.
– analogsystemsrf
Dec 5 at 17:07
1
1
I think it's not as clear cut as your question implies. I personally believe that if you design it to be in CCM for "fuller" loads then you have to accept that it will drop into DCM on light loads hence you don't really choose BUT if, in your question you can paint scenarios for a given load voltage, load current and supply voltage range (yes the supply voltage range is very important) then a fair comparison can be made. I think you'll find that it is difficult to constrain a design with requirements that make CCM an exclusive turn-to solution.
– Andy aka
Dec 5 at 17:45
I think it's not as clear cut as your question implies. I personally believe that if you design it to be in CCM for "fuller" loads then you have to accept that it will drop into DCM on light loads hence you don't really choose BUT if, in your question you can paint scenarios for a given load voltage, load current and supply voltage range (yes the supply voltage range is very important) then a fair comparison can be made. I think you'll find that it is difficult to constrain a design with requirements that make CCM an exclusive turn-to solution.
– Andy aka
Dec 5 at 17:45
Looks like your revised question has attracted some attention now, which is all we can hope for. Good to see!
– Adam Lawrence
Dec 6 at 13:07
Looks like your revised question has attracted some attention now, which is all we can hope for. Good to see!
– Adam Lawrence
Dec 6 at 13:07
add a comment |
1 Answer
1
active
oldest
votes
up vote
7
down vote
accepted
DCM: more ripple current and inductor losses but easier to make stable. e.g. flyback but not scaleable > 200W , easy for no load. ( 1st order control system)
CCM: ideal for more constant loads with less input noise and less output ripple spectrum but more attention to fast reverse recovery diode losses.
- 2nd order system stability effects more difficult with wide load (gain) range.
Feedforward methods permit multiple outputs with tight magnetic coupling so on the main output needs to be regulated.
- Interleave both methods for wide load range higher efficiency
add more phases to reduce ripple and more efficiency with load sharing.
Other modes: critical conduction mode and non-minimum phase (NMP) characteristic from right-hand pole (RHP)
CCM problem
2nd Order Effects means that if the loop phase margin drops to zero, it oscillates ( unstable). When you think adding a low ESR capacitor will help, consider the input capacitor, it reduces ripple but also phase margin. This problem was solved by design of the input filter, discovered by R. David Middlebrook at Caltech 1975.
"The Middlebrook Criterion is a graphical method for determining if the input filter of a switching mode power supply will cause instability or degrade performance parameters of a duty-ratio (voltage) programmed dc-to-dc converter switching-mode power supply. As usually applied, the output impedance of the input filter is overlaid on the open-loop input impedance of the switching-mode power supply at the worse-case conditions of low-line and full-load and low-line with shorted output."
Ref
The key solution is to place the input filter resonance from P5 towards P4 to the left of P3 of the output filter.
The best authors in SMPS design were the late Abraham Pressman with updates by Keith Billings. Older versions are free at archive.org.
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
7
down vote
accepted
DCM: more ripple current and inductor losses but easier to make stable. e.g. flyback but not scaleable > 200W , easy for no load. ( 1st order control system)
CCM: ideal for more constant loads with less input noise and less output ripple spectrum but more attention to fast reverse recovery diode losses.
- 2nd order system stability effects more difficult with wide load (gain) range.
Feedforward methods permit multiple outputs with tight magnetic coupling so on the main output needs to be regulated.
- Interleave both methods for wide load range higher efficiency
add more phases to reduce ripple and more efficiency with load sharing.
Other modes: critical conduction mode and non-minimum phase (NMP) characteristic from right-hand pole (RHP)
CCM problem
2nd Order Effects means that if the loop phase margin drops to zero, it oscillates ( unstable). When you think adding a low ESR capacitor will help, consider the input capacitor, it reduces ripple but also phase margin. This problem was solved by design of the input filter, discovered by R. David Middlebrook at Caltech 1975.
"The Middlebrook Criterion is a graphical method for determining if the input filter of a switching mode power supply will cause instability or degrade performance parameters of a duty-ratio (voltage) programmed dc-to-dc converter switching-mode power supply. As usually applied, the output impedance of the input filter is overlaid on the open-loop input impedance of the switching-mode power supply at the worse-case conditions of low-line and full-load and low-line with shorted output."
Ref
The key solution is to place the input filter resonance from P5 towards P4 to the left of P3 of the output filter.
The best authors in SMPS design were the late Abraham Pressman with updates by Keith Billings. Older versions are free at archive.org.
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
add a comment |
up vote
7
down vote
accepted
DCM: more ripple current and inductor losses but easier to make stable. e.g. flyback but not scaleable > 200W , easy for no load. ( 1st order control system)
CCM: ideal for more constant loads with less input noise and less output ripple spectrum but more attention to fast reverse recovery diode losses.
- 2nd order system stability effects more difficult with wide load (gain) range.
Feedforward methods permit multiple outputs with tight magnetic coupling so on the main output needs to be regulated.
- Interleave both methods for wide load range higher efficiency
add more phases to reduce ripple and more efficiency with load sharing.
Other modes: critical conduction mode and non-minimum phase (NMP) characteristic from right-hand pole (RHP)
CCM problem
2nd Order Effects means that if the loop phase margin drops to zero, it oscillates ( unstable). When you think adding a low ESR capacitor will help, consider the input capacitor, it reduces ripple but also phase margin. This problem was solved by design of the input filter, discovered by R. David Middlebrook at Caltech 1975.
"The Middlebrook Criterion is a graphical method for determining if the input filter of a switching mode power supply will cause instability or degrade performance parameters of a duty-ratio (voltage) programmed dc-to-dc converter switching-mode power supply. As usually applied, the output impedance of the input filter is overlaid on the open-loop input impedance of the switching-mode power supply at the worse-case conditions of low-line and full-load and low-line with shorted output."
Ref
The key solution is to place the input filter resonance from P5 towards P4 to the left of P3 of the output filter.
The best authors in SMPS design were the late Abraham Pressman with updates by Keith Billings. Older versions are free at archive.org.
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
add a comment |
up vote
7
down vote
accepted
up vote
7
down vote
accepted
DCM: more ripple current and inductor losses but easier to make stable. e.g. flyback but not scaleable > 200W , easy for no load. ( 1st order control system)
CCM: ideal for more constant loads with less input noise and less output ripple spectrum but more attention to fast reverse recovery diode losses.
- 2nd order system stability effects more difficult with wide load (gain) range.
Feedforward methods permit multiple outputs with tight magnetic coupling so on the main output needs to be regulated.
- Interleave both methods for wide load range higher efficiency
add more phases to reduce ripple and more efficiency with load sharing.
Other modes: critical conduction mode and non-minimum phase (NMP) characteristic from right-hand pole (RHP)
CCM problem
2nd Order Effects means that if the loop phase margin drops to zero, it oscillates ( unstable). When you think adding a low ESR capacitor will help, consider the input capacitor, it reduces ripple but also phase margin. This problem was solved by design of the input filter, discovered by R. David Middlebrook at Caltech 1975.
"The Middlebrook Criterion is a graphical method for determining if the input filter of a switching mode power supply will cause instability or degrade performance parameters of a duty-ratio (voltage) programmed dc-to-dc converter switching-mode power supply. As usually applied, the output impedance of the input filter is overlaid on the open-loop input impedance of the switching-mode power supply at the worse-case conditions of low-line and full-load and low-line with shorted output."
Ref
The key solution is to place the input filter resonance from P5 towards P4 to the left of P3 of the output filter.
The best authors in SMPS design were the late Abraham Pressman with updates by Keith Billings. Older versions are free at archive.org.
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
DCM: more ripple current and inductor losses but easier to make stable. e.g. flyback but not scaleable > 200W , easy for no load. ( 1st order control system)
CCM: ideal for more constant loads with less input noise and less output ripple spectrum but more attention to fast reverse recovery diode losses.
- 2nd order system stability effects more difficult with wide load (gain) range.
Feedforward methods permit multiple outputs with tight magnetic coupling so on the main output needs to be regulated.
- Interleave both methods for wide load range higher efficiency
add more phases to reduce ripple and more efficiency with load sharing.
Other modes: critical conduction mode and non-minimum phase (NMP) characteristic from right-hand pole (RHP)
CCM problem
2nd Order Effects means that if the loop phase margin drops to zero, it oscillates ( unstable). When you think adding a low ESR capacitor will help, consider the input capacitor, it reduces ripple but also phase margin. This problem was solved by design of the input filter, discovered by R. David Middlebrook at Caltech 1975.
"The Middlebrook Criterion is a graphical method for determining if the input filter of a switching mode power supply will cause instability or degrade performance parameters of a duty-ratio (voltage) programmed dc-to-dc converter switching-mode power supply. As usually applied, the output impedance of the input filter is overlaid on the open-loop input impedance of the switching-mode power supply at the worse-case conditions of low-line and full-load and low-line with shorted output."
Ref
The key solution is to place the input filter resonance from P5 towards P4 to the left of P3 of the output filter.
The best authors in SMPS design were the late Abraham Pressman with updates by Keith Billings. Older versions are free at archive.org.
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
edited Dec 5 at 17:34
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
answered Dec 5 at 17:00
Tony EE rocketscientist
60.9k22192
60.9k22192
add a comment |
add a comment |
2
To me this is too broad a topic for this site - we try to focus on specific issues and provide specific answers. To fully answer this will require an extensive discussion of both control and power electronics theory. Perhaps you should narrow your question to only one of the three you posted - either advantages/disadvantages, applications, or choice.
– Adam Lawrence
Dec 5 at 16:51
1
@AdamLawrence took your advice. Erased the part of applications and I think the choice is covered with advantages/disdvantages because one can clearly infer whether to use one or another if we are aware of the advantages of each mode.
– Miguel Duran Diaz
Dec 5 at 16:55
DCM may have HUGE RINGING on the switching node, thus huge radiated EMI, or huge electric-field interference for microseconds.
– analogsystemsrf
Dec 5 at 17:07
1
I think it's not as clear cut as your question implies. I personally believe that if you design it to be in CCM for "fuller" loads then you have to accept that it will drop into DCM on light loads hence you don't really choose BUT if, in your question you can paint scenarios for a given load voltage, load current and supply voltage range (yes the supply voltage range is very important) then a fair comparison can be made. I think you'll find that it is difficult to constrain a design with requirements that make CCM an exclusive turn-to solution.
– Andy aka
Dec 5 at 17:45
Looks like your revised question has attracted some attention now, which is all we can hope for. Good to see!
– Adam Lawrence
Dec 6 at 13:07