creating text file with regards to file names












0















I have a text file (digit.txt) consisting of one column includes three digit numbers whose range are 001-...365. In the same directory, I have data text files. The file name of these data files as follows, jplg3240.18i. Only the jplg part is constant. I need to order jplg data files w.r.t. the numbers in the digit.txt file using the first 5-7 characters of the file names and store them in another text file. For example:



digit.txt=
005
301
350
005
010

data files= jplg001.18i.txt, jplg005.18i.txt, jplg301.18i.txt, jplg350.18i.txt,jplg010.18i.txt, jplg365.18i.txt


Output file should be this one:



output=
jplg005.18i
jplg301.18i
jplg350.18i
jplg005.18i
jplg010.18i









share|improve this question

























  • in short you need to cycle on the content of digit.txt and for the only matched data generate a second file with the list of complete filename, is it that correct?

    – AtomiX84
    Jan 8 at 7:39













  • yes it is true.

    – deepblue_86
    Jan 8 at 7:39
















0















I have a text file (digit.txt) consisting of one column includes three digit numbers whose range are 001-...365. In the same directory, I have data text files. The file name of these data files as follows, jplg3240.18i. Only the jplg part is constant. I need to order jplg data files w.r.t. the numbers in the digit.txt file using the first 5-7 characters of the file names and store them in another text file. For example:



digit.txt=
005
301
350
005
010

data files= jplg001.18i.txt, jplg005.18i.txt, jplg301.18i.txt, jplg350.18i.txt,jplg010.18i.txt, jplg365.18i.txt


Output file should be this one:



output=
jplg005.18i
jplg301.18i
jplg350.18i
jplg005.18i
jplg010.18i









share|improve this question

























  • in short you need to cycle on the content of digit.txt and for the only matched data generate a second file with the list of complete filename, is it that correct?

    – AtomiX84
    Jan 8 at 7:39













  • yes it is true.

    – deepblue_86
    Jan 8 at 7:39














0












0








0








I have a text file (digit.txt) consisting of one column includes three digit numbers whose range are 001-...365. In the same directory, I have data text files. The file name of these data files as follows, jplg3240.18i. Only the jplg part is constant. I need to order jplg data files w.r.t. the numbers in the digit.txt file using the first 5-7 characters of the file names and store them in another text file. For example:



digit.txt=
005
301
350
005
010

data files= jplg001.18i.txt, jplg005.18i.txt, jplg301.18i.txt, jplg350.18i.txt,jplg010.18i.txt, jplg365.18i.txt


Output file should be this one:



output=
jplg005.18i
jplg301.18i
jplg350.18i
jplg005.18i
jplg010.18i









share|improve this question
















I have a text file (digit.txt) consisting of one column includes three digit numbers whose range are 001-...365. In the same directory, I have data text files. The file name of these data files as follows, jplg3240.18i. Only the jplg part is constant. I need to order jplg data files w.r.t. the numbers in the digit.txt file using the first 5-7 characters of the file names and store them in another text file. For example:



digit.txt=
005
301
350
005
010

data files= jplg001.18i.txt, jplg005.18i.txt, jplg301.18i.txt, jplg350.18i.txt,jplg010.18i.txt, jplg365.18i.txt


Output file should be this one:



output=
jplg005.18i
jplg301.18i
jplg350.18i
jplg005.18i
jplg010.18i






scripts text-processing






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 8 at 7:59







deepblue_86

















asked Jan 8 at 6:47









deepblue_86deepblue_86

5851023




5851023













  • in short you need to cycle on the content of digit.txt and for the only matched data generate a second file with the list of complete filename, is it that correct?

    – AtomiX84
    Jan 8 at 7:39













  • yes it is true.

    – deepblue_86
    Jan 8 at 7:39



















  • in short you need to cycle on the content of digit.txt and for the only matched data generate a second file with the list of complete filename, is it that correct?

    – AtomiX84
    Jan 8 at 7:39













  • yes it is true.

    – deepblue_86
    Jan 8 at 7:39

















in short you need to cycle on the content of digit.txt and for the only matched data generate a second file with the list of complete filename, is it that correct?

– AtomiX84
Jan 8 at 7:39







in short you need to cycle on the content of digit.txt and for the only matched data generate a second file with the list of complete filename, is it that correct?

– AtomiX84
Jan 8 at 7:39















yes it is true.

– deepblue_86
Jan 8 at 7:39





yes it is true.

– deepblue_86
Jan 8 at 7:39










2 Answers
2






active

oldest

votes


















2














here the while cycle could be good for reach your goal:



while read element
do
if [ -f jplg${element}* ]; then
echo jplg${element}* >> datafiles.txt
fi
done < digit.txt


Code is supposed to be run in to the path were the files are and give you as per result a file list in the file datafiles.txt with the complete name of the file if was matched in the list in the file digit.txt






share|improve this answer


























  • I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

    – deepblue_86
    Jan 8 at 7:55













  • Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

    – AtomiX84
    Jan 8 at 8:21



















0














If you question is concatenate the data from the files listed in digit.txt then an answer is:



ls jplg* | grep -f digit.txt | xargs cat >out.dat


In slo-mo:





  • ls jplg*: lists a superset of all the files you want (you can make that more restrictive if needed)


  • grep -f digit.txt keeps only the lines that contain one number in digit.txt (this assumes that the three digits don't appear anywhere else in file names)


  • xargs cat: applies cat to all the files listed in the grep output






share|improve this answer























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    here the while cycle could be good for reach your goal:



    while read element
    do
    if [ -f jplg${element}* ]; then
    echo jplg${element}* >> datafiles.txt
    fi
    done < digit.txt


    Code is supposed to be run in to the path were the files are and give you as per result a file list in the file datafiles.txt with the complete name of the file if was matched in the list in the file digit.txt






    share|improve this answer


























    • I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

      – deepblue_86
      Jan 8 at 7:55













    • Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

      – AtomiX84
      Jan 8 at 8:21
















    2














    here the while cycle could be good for reach your goal:



    while read element
    do
    if [ -f jplg${element}* ]; then
    echo jplg${element}* >> datafiles.txt
    fi
    done < digit.txt


    Code is supposed to be run in to the path were the files are and give you as per result a file list in the file datafiles.txt with the complete name of the file if was matched in the list in the file digit.txt






    share|improve this answer


























    • I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

      – deepblue_86
      Jan 8 at 7:55













    • Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

      – AtomiX84
      Jan 8 at 8:21














    2












    2








    2







    here the while cycle could be good for reach your goal:



    while read element
    do
    if [ -f jplg${element}* ]; then
    echo jplg${element}* >> datafiles.txt
    fi
    done < digit.txt


    Code is supposed to be run in to the path were the files are and give you as per result a file list in the file datafiles.txt with the complete name of the file if was matched in the list in the file digit.txt






    share|improve this answer















    here the while cycle could be good for reach your goal:



    while read element
    do
    if [ -f jplg${element}* ]; then
    echo jplg${element}* >> datafiles.txt
    fi
    done < digit.txt


    Code is supposed to be run in to the path were the files are and give you as per result a file list in the file datafiles.txt with the complete name of the file if was matched in the list in the file digit.txt







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 8 at 8:18

























    answered Jan 8 at 7:48









    AtomiX84AtomiX84

    68019




    68019













    • I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

      – deepblue_86
      Jan 8 at 7:55













    • Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

      – AtomiX84
      Jan 8 at 8:21



















    • I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

      – deepblue_86
      Jan 8 at 7:55













    • Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

      – AtomiX84
      Jan 8 at 8:21

















    I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

    – deepblue_86
    Jan 8 at 7:55







    I think my question was understood slightly wrong. I have lots of data files in the directory and the name of these files starts with jplg. The contents of these data files are not related the jplg string.

    – deepblue_86
    Jan 8 at 7:55















    Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

    – AtomiX84
    Jan 8 at 8:21





    Update the answer, now only jplg* data will added in the datafiles.txt, anyway was not clear in you original question to me. Sorry for my misunderstanding.

    – AtomiX84
    Jan 8 at 8:21













    0














    If you question is concatenate the data from the files listed in digit.txt then an answer is:



    ls jplg* | grep -f digit.txt | xargs cat >out.dat


    In slo-mo:





    • ls jplg*: lists a superset of all the files you want (you can make that more restrictive if needed)


    • grep -f digit.txt keeps only the lines that contain one number in digit.txt (this assumes that the three digits don't appear anywhere else in file names)


    • xargs cat: applies cat to all the files listed in the grep output






    share|improve this answer




























      0














      If you question is concatenate the data from the files listed in digit.txt then an answer is:



      ls jplg* | grep -f digit.txt | xargs cat >out.dat


      In slo-mo:





      • ls jplg*: lists a superset of all the files you want (you can make that more restrictive if needed)


      • grep -f digit.txt keeps only the lines that contain one number in digit.txt (this assumes that the three digits don't appear anywhere else in file names)


      • xargs cat: applies cat to all the files listed in the grep output






      share|improve this answer


























        0












        0








        0







        If you question is concatenate the data from the files listed in digit.txt then an answer is:



        ls jplg* | grep -f digit.txt | xargs cat >out.dat


        In slo-mo:





        • ls jplg*: lists a superset of all the files you want (you can make that more restrictive if needed)


        • grep -f digit.txt keeps only the lines that contain one number in digit.txt (this assumes that the three digits don't appear anywhere else in file names)


        • xargs cat: applies cat to all the files listed in the grep output






        share|improve this answer













        If you question is concatenate the data from the files listed in digit.txt then an answer is:



        ls jplg* | grep -f digit.txt | xargs cat >out.dat


        In slo-mo:





        • ls jplg*: lists a superset of all the files you want (you can make that more restrictive if needed)


        • grep -f digit.txt keeps only the lines that contain one number in digit.txt (this assumes that the three digits don't appear anywhere else in file names)


        • xargs cat: applies cat to all the files listed in the grep output







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 8 at 9:46









        xenoidxenoid

        1,4691415




        1,4691415






























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