Bdtyktl

I have two or more network interface at the same time and want to use each network for sending special requests over it.

for example :
I want to see a video by "network-1" and other requests I want to send with "network-2"

ifconfig

output:

enx0c5b8f279a64: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500

    inet 192.168.8.100  netmask 255.255.255.0  broadcast 192.168.8.255

    inet6 fe80::af19:e5c2:350e:ad09  prefixlen 64  scopeid 0x20<link>

    ether 0c:5b:8f:27:9a:64  txqueuelen 1000  (Ethernet)

    RX packets 74  bytes 16183 (16.1 KB)

    RX errors 0  dropped 0  overruns 0  frame 0

    TX packets 122  bytes 16282 (16.2 KB)

    TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0



lo: flags=73<UP,LOOPBACK,RUNNING>  mtu 65536

    inet 127.0.0.1  netmask 255.0.0.0

    inet6 ::1  prefixlen 128  scopeid 0x10<host>

    loop  txqueuelen 1000  (Local Loopback)

    RX packets 5290686  bytes 3859055101 (3.8 GB)

    RX errors 0  dropped 0  overruns 0  frame 0

    TX packets 5290686  bytes 3859055101 (3.8 GB)

    TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0



ppp0: flags=4305<UP,POINTOPOINT,RUNNING,NOARP,MULTICAST>  mtu 1400

    inet 81.31.179.204  netmask 255.255.255.255  destination 172.17.1.230

    ppp  txqueuelen 3  (Point-to-Point Protocol)

    RX packets 292544  bytes 336720863 (336.7 MB)

    RX errors 0  dropped 0  overruns 0  frame 0

    TX packets 178723  bytes 16928573 (16.9 MB)

    TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0



wlp2s0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500

    inet 192.168.1.2  netmask 255.255.255.0  broadcast 192.168.1.255

    inet6 fe80::a71b:2220:7e40:1948  prefixlen 64  scopeid 0x20<link>

    ether e4:70:b8:cf:4f:81  txqueuelen 1000  (Ethernet)

    RX packets 4691632  bytes 4626078058 (4.6 GB)

    RX errors 0  dropped 0  overruns 0  frame 0

    TX packets 4675065  bytes 704065262 (704.0 MB)

    TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0

and my IP route is

ip route show

output:

default dev ppp0 proto static scope link metric 50 

default via 192.168.8.1 dev enx0c5b8f279a64 proto dhcp metric 20100 

default via 192.168.1.1 dev wlp2s0 proto dhcp metric 20600 

169.254.0.0/16 dev wlp2s0 scope link metric 1000 

172.17.1.230 via 192.168.1.1 dev wlp2s0 src 192.168.1.2 

172.17.1.230 dev ppp0 proto kernel scope link src 81.31.179.204 metric 50 

172.17.1.230 via 192.168.1.1 dev wlp2s0 proto static metric 600 

192.168.1.0/24 dev wlp2s0 proto kernel scope link src 192.168.1.2 metric 600 

192.168.1.1 dev wlp2s0 proto static scope link metric 600 

192.168.8.0/24 dev enx0c5b8f279a64 proto kernel scope link src 

192.168.8.100 metric 100 

at that time wlp2s0 and enx0c5b8f279a64 are my two network interface and my data sends default through wlp2s0.

I want to send some of my requests (e.g. YouTube.com) through enx0c5b8f279a64 and others through wlp2s0.

I think this is a good idea (maybe)

I think (probably) opening a port in local for forwarding my packets to one of them (i.e. enx0c5b8f279a64) is a good idea (but I don't know other ways)
then i can set my browser proxy on this ip/port (i.e. 'localhost'/'a_port') and set up its setting to use this proxy just for YouTube.com

A proxy is the solution to your goal, yes. As a far I know squid should you permit to redirect traffic based on the destination URL and also to define the outgoing address.

For examples, to set the outgoing address for youtube the squid acl will like some think like:

....

acl viaVideo dstdomain youtube.com

tcp_outgoing_address 192.168.1.1 viaVideo

....

the previously rules will says to squid to send via 192.168.1.1 all request performed to youtube.com