Bash remove first and last characters from a string
I have a string like that:
|abcdefg|
And i want to get a new string called in someway (like string2) with the original string without the two | at the start and at the end of it
so that i will have this
abcdefg
is that possible in bash?
bash command-line scripts
add a comment |
I have a string like that:
|abcdefg|
And i want to get a new string called in someway (like string2) with the original string without the two | at the start and at the end of it
so that i will have this
abcdefg
is that possible in bash?
bash command-line scripts
add a comment |
I have a string like that:
|abcdefg|
And i want to get a new string called in someway (like string2) with the original string without the two | at the start and at the end of it
so that i will have this
abcdefg
is that possible in bash?
bash command-line scripts
I have a string like that:
|abcdefg|
And i want to get a new string called in someway (like string2) with the original string without the two | at the start and at the end of it
so that i will have this
abcdefg
is that possible in bash?
bash command-line scripts
bash command-line scripts
edited Dec 23 '11 at 14:48
Matteo Pagliazzi
asked Dec 23 '11 at 14:29
Matteo PagliazziMatteo Pagliazzi
1,26751633
1,26751633
add a comment |
add a comment |
8 Answers
8
active
oldest
votes
You can do
string="|abcdefg|"
string2=${string#"|"}
string2=${string2%"|"}
echo $string2
Or if your string length is constant, you can do
string="|abcdefg|"
string2=${string:1:7}
echo $string2
Also, this should work
echo "|abcdefg|" | cut -d "|" -f 2
Also this
echo "|abcdefg|" | sed 's/^|(.*)|$/1/'
2
and alsoawk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
@enzotib You always have coolawk
solutions. I need to learnawk
.
– Kris Harper
Dec 23 '11 at 18:36
2
and alsoIFS='|' read string2 <<< $string
:)
– arrange
Dec 23 '11 at 20:38
9
and also, in bash 4.2 and newer,"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
Read under the "parameter expansion" section inman bash
.
– Nemo
Sep 5 '12 at 20:44
add a comment |
Here's a solution that is independent of the length of the string (bash):
string="|abcdefg|"
echo "${string:1:${#string}-2}"
add a comment |
Going off a few posts listed here it seems the simplest way to do it is:
string="|abcdefg|"
echo ${string:1:-1}
edit: works on ubuntu with bash 4.2; does not work on centOS with bash 4.1
add a comment |
Another way is to use head
& tail
commands:
$ echo -n "|abcdefg|" | tail -c +2 | head -c -2
abcdefg
1
I had a string of[something something]
with a goal to cut brackets, soecho "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!
– Ain Tohvri
Dec 13 '15 at 15:36
add a comment |
And another one:
string="|abcdefg|"
echo "${string//|/}"
add a comment |
You can also use sed to remove the | not just referencing the symbol itself but using positional references as in:
$ echo "|abcdefg|" | sed 's:^.(.*).$:1:'
abcdefg
Where ':' are the delimiters (you can replace them with / or any character not in the query, any sign following the s will do it) Here ^ (caret) means at the beginning of the input string and $ (dollar) means at the end. The . (point) that it's after the caret and the one that it's before the dollar sign represents a single character. So in other words we are deleting the first and last characters.
Take in mind this will delete any characters even if | it's not present in the string.
EX:
$ echo "abcdefg" | sed 's:^.(.*).$:1:'
bcdef
add a comment |
shell function
A bit more verbose approach, but works on any sort of first and last character, doesn't have to be the same. Basic idea is that we are taking a variable, reading it character by character, and appending only those
we want to a new variable
Here's that whole idea formatted into a nice function
crop_string_ends() {
STR="$1"
NEWSTR=""
COUNT=0
while read -n 1 CHAR
do
COUNT=$(($COUNT+1))
if [ $COUNT -eq 1 ] || [ $COUNT -eq ${#STR} ]
then
continue
fi
NEWSTR="$NEWSTR"$CHAR
done <<<"$STR"
echo $NEWSTR
}
And here is that same function in action:
$> crop_string_ends "|abcdefg|"
abcdefg
$> crop_string_ends "HelloWorld"
elloWorl
Python
>>> mystring="|abcdefg|"
>>> print(mystring[1:-1])
abcdefg
or on command line:
$ python -c 'import sys;print sys.stdin.read()[1:-2]' <<< "|abcdefg|"
abcdefg
AWK
$ echo "|abcdefg|" | awk '{print substr($0,2,length($0)-2)}'
abcdefg
Ruby
$ ruby -ne 'print $_.split("|")[1]' <<< "|abcdefg|"
abcdefg
add a comment |
Small and universal solution:
expr "|abcdef|" : '.(.*).'
Special in this case and allowing that the '|' character may be there or not:
expr "|abcdef" : '|*([^|]*)|*'
add a comment |
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8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can do
string="|abcdefg|"
string2=${string#"|"}
string2=${string2%"|"}
echo $string2
Or if your string length is constant, you can do
string="|abcdefg|"
string2=${string:1:7}
echo $string2
Also, this should work
echo "|abcdefg|" | cut -d "|" -f 2
Also this
echo "|abcdefg|" | sed 's/^|(.*)|$/1/'
2
and alsoawk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
@enzotib You always have coolawk
solutions. I need to learnawk
.
– Kris Harper
Dec 23 '11 at 18:36
2
and alsoIFS='|' read string2 <<< $string
:)
– arrange
Dec 23 '11 at 20:38
9
and also, in bash 4.2 and newer,"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
Read under the "parameter expansion" section inman bash
.
– Nemo
Sep 5 '12 at 20:44
add a comment |
You can do
string="|abcdefg|"
string2=${string#"|"}
string2=${string2%"|"}
echo $string2
Or if your string length is constant, you can do
string="|abcdefg|"
string2=${string:1:7}
echo $string2
Also, this should work
echo "|abcdefg|" | cut -d "|" -f 2
Also this
echo "|abcdefg|" | sed 's/^|(.*)|$/1/'
2
and alsoawk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
@enzotib You always have coolawk
solutions. I need to learnawk
.
– Kris Harper
Dec 23 '11 at 18:36
2
and alsoIFS='|' read string2 <<< $string
:)
– arrange
Dec 23 '11 at 20:38
9
and also, in bash 4.2 and newer,"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
Read under the "parameter expansion" section inman bash
.
– Nemo
Sep 5 '12 at 20:44
add a comment |
You can do
string="|abcdefg|"
string2=${string#"|"}
string2=${string2%"|"}
echo $string2
Or if your string length is constant, you can do
string="|abcdefg|"
string2=${string:1:7}
echo $string2
Also, this should work
echo "|abcdefg|" | cut -d "|" -f 2
Also this
echo "|abcdefg|" | sed 's/^|(.*)|$/1/'
You can do
string="|abcdefg|"
string2=${string#"|"}
string2=${string2%"|"}
echo $string2
Or if your string length is constant, you can do
string="|abcdefg|"
string2=${string:1:7}
echo $string2
Also, this should work
echo "|abcdefg|" | cut -d "|" -f 2
Also this
echo "|abcdefg|" | sed 's/^|(.*)|$/1/'
edited Dec 23 '11 at 18:36
answered Dec 23 '11 at 14:49
Kris HarperKris Harper
9,629114771
9,629114771
2
and alsoawk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
@enzotib You always have coolawk
solutions. I need to learnawk
.
– Kris Harper
Dec 23 '11 at 18:36
2
and alsoIFS='|' read string2 <<< $string
:)
– arrange
Dec 23 '11 at 20:38
9
and also, in bash 4.2 and newer,"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
Read under the "parameter expansion" section inman bash
.
– Nemo
Sep 5 '12 at 20:44
add a comment |
2
and alsoawk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
@enzotib You always have coolawk
solutions. I need to learnawk
.
– Kris Harper
Dec 23 '11 at 18:36
2
and alsoIFS='|' read string2 <<< $string
:)
– arrange
Dec 23 '11 at 20:38
9
and also, in bash 4.2 and newer,"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
Read under the "parameter expansion" section inman bash
.
– Nemo
Sep 5 '12 at 20:44
2
2
and also
awk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
and also
awk -F| '{ print $2 }' <<<"|string|"
– enzotib
Dec 23 '11 at 17:45
@enzotib You always have cool
awk
solutions. I need to learn awk
.– Kris Harper
Dec 23 '11 at 18:36
@enzotib You always have cool
awk
solutions. I need to learn awk
.– Kris Harper
Dec 23 '11 at 18:36
2
2
and also
IFS='|' read string2 <<< $string
:)– arrange
Dec 23 '11 at 20:38
and also
IFS='|' read string2 <<< $string
:)– arrange
Dec 23 '11 at 20:38
9
9
and also, in bash 4.2 and newer,
"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
and also, in bash 4.2 and newer,
"${string:1:-1}"
– geirha
Jul 5 '12 at 12:52
Read under the "parameter expansion" section in
man bash
.– Nemo
Sep 5 '12 at 20:44
Read under the "parameter expansion" section in
man bash
.– Nemo
Sep 5 '12 at 20:44
add a comment |
Here's a solution that is independent of the length of the string (bash):
string="|abcdefg|"
echo "${string:1:${#string}-2}"
add a comment |
Here's a solution that is independent of the length of the string (bash):
string="|abcdefg|"
echo "${string:1:${#string}-2}"
add a comment |
Here's a solution that is independent of the length of the string (bash):
string="|abcdefg|"
echo "${string:1:${#string}-2}"
Here's a solution that is independent of the length of the string (bash):
string="|abcdefg|"
echo "${string:1:${#string}-2}"
edited Jul 5 '12 at 12:44
Eliah Kagan
81.9k21227364
81.9k21227364
answered Dec 24 '11 at 16:28
Samus_Samus_
76257
76257
add a comment |
add a comment |
Going off a few posts listed here it seems the simplest way to do it is:
string="|abcdefg|"
echo ${string:1:-1}
edit: works on ubuntu with bash 4.2; does not work on centOS with bash 4.1
add a comment |
Going off a few posts listed here it seems the simplest way to do it is:
string="|abcdefg|"
echo ${string:1:-1}
edit: works on ubuntu with bash 4.2; does not work on centOS with bash 4.1
add a comment |
Going off a few posts listed here it seems the simplest way to do it is:
string="|abcdefg|"
echo ${string:1:-1}
edit: works on ubuntu with bash 4.2; does not work on centOS with bash 4.1
Going off a few posts listed here it seems the simplest way to do it is:
string="|abcdefg|"
echo ${string:1:-1}
edit: works on ubuntu with bash 4.2; does not work on centOS with bash 4.1
edited Oct 16 '12 at 16:32
answered Sep 5 '12 at 20:37
jlunavtgradjlunavtgrad
33924
33924
add a comment |
add a comment |
Another way is to use head
& tail
commands:
$ echo -n "|abcdefg|" | tail -c +2 | head -c -2
abcdefg
1
I had a string of[something something]
with a goal to cut brackets, soecho "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!
– Ain Tohvri
Dec 13 '15 at 15:36
add a comment |
Another way is to use head
& tail
commands:
$ echo -n "|abcdefg|" | tail -c +2 | head -c -2
abcdefg
1
I had a string of[something something]
with a goal to cut brackets, soecho "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!
– Ain Tohvri
Dec 13 '15 at 15:36
add a comment |
Another way is to use head
& tail
commands:
$ echo -n "|abcdefg|" | tail -c +2 | head -c -2
abcdefg
Another way is to use head
& tail
commands:
$ echo -n "|abcdefg|" | tail -c +2 | head -c -2
abcdefg
edited Jan 11 at 21:26
agabrys
1034
1034
answered Nov 26 '13 at 16:16
ZaviorZavior
24124
24124
1
I had a string of[something something]
with a goal to cut brackets, soecho "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!
– Ain Tohvri
Dec 13 '15 at 15:36
add a comment |
1
I had a string of[something something]
with a goal to cut brackets, soecho "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!
– Ain Tohvri
Dec 13 '15 at 15:36
1
1
I had a string of
[something something]
with a goal to cut brackets, so echo "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!– Ain Tohvri
Dec 13 '15 at 15:36
I had a string of
[something something]
with a goal to cut brackets, so echo "[something something]" | tail -c +2 | head -c -2
worked out. Thanks for a tip!– Ain Tohvri
Dec 13 '15 at 15:36
add a comment |
And another one:
string="|abcdefg|"
echo "${string//|/}"
add a comment |
And another one:
string="|abcdefg|"
echo "${string//|/}"
add a comment |
And another one:
string="|abcdefg|"
echo "${string//|/}"
And another one:
string="|abcdefg|"
echo "${string//|/}"
edited Jul 18 '12 at 15:06
answered Jun 9 '12 at 1:03
Steven PennySteven Penny
1
1
add a comment |
add a comment |
You can also use sed to remove the | not just referencing the symbol itself but using positional references as in:
$ echo "|abcdefg|" | sed 's:^.(.*).$:1:'
abcdefg
Where ':' are the delimiters (you can replace them with / or any character not in the query, any sign following the s will do it) Here ^ (caret) means at the beginning of the input string and $ (dollar) means at the end. The . (point) that it's after the caret and the one that it's before the dollar sign represents a single character. So in other words we are deleting the first and last characters.
Take in mind this will delete any characters even if | it's not present in the string.
EX:
$ echo "abcdefg" | sed 's:^.(.*).$:1:'
bcdef
add a comment |
You can also use sed to remove the | not just referencing the symbol itself but using positional references as in:
$ echo "|abcdefg|" | sed 's:^.(.*).$:1:'
abcdefg
Where ':' are the delimiters (you can replace them with / or any character not in the query, any sign following the s will do it) Here ^ (caret) means at the beginning of the input string and $ (dollar) means at the end. The . (point) that it's after the caret and the one that it's before the dollar sign represents a single character. So in other words we are deleting the first and last characters.
Take in mind this will delete any characters even if | it's not present in the string.
EX:
$ echo "abcdefg" | sed 's:^.(.*).$:1:'
bcdef
add a comment |
You can also use sed to remove the | not just referencing the symbol itself but using positional references as in:
$ echo "|abcdefg|" | sed 's:^.(.*).$:1:'
abcdefg
Where ':' are the delimiters (you can replace them with / or any character not in the query, any sign following the s will do it) Here ^ (caret) means at the beginning of the input string and $ (dollar) means at the end. The . (point) that it's after the caret and the one that it's before the dollar sign represents a single character. So in other words we are deleting the first and last characters.
Take in mind this will delete any characters even if | it's not present in the string.
EX:
$ echo "abcdefg" | sed 's:^.(.*).$:1:'
bcdef
You can also use sed to remove the | not just referencing the symbol itself but using positional references as in:
$ echo "|abcdefg|" | sed 's:^.(.*).$:1:'
abcdefg
Where ':' are the delimiters (you can replace them with / or any character not in the query, any sign following the s will do it) Here ^ (caret) means at the beginning of the input string and $ (dollar) means at the end. The . (point) that it's after the caret and the one that it's before the dollar sign represents a single character. So in other words we are deleting the first and last characters.
Take in mind this will delete any characters even if | it's not present in the string.
EX:
$ echo "abcdefg" | sed 's:^.(.*).$:1:'
bcdef
answered Feb 8 '12 at 1:44
MetafanielMetafaniel
1893
1893
add a comment |
add a comment |
shell function
A bit more verbose approach, but works on any sort of first and last character, doesn't have to be the same. Basic idea is that we are taking a variable, reading it character by character, and appending only those
we want to a new variable
Here's that whole idea formatted into a nice function
crop_string_ends() {
STR="$1"
NEWSTR=""
COUNT=0
while read -n 1 CHAR
do
COUNT=$(($COUNT+1))
if [ $COUNT -eq 1 ] || [ $COUNT -eq ${#STR} ]
then
continue
fi
NEWSTR="$NEWSTR"$CHAR
done <<<"$STR"
echo $NEWSTR
}
And here is that same function in action:
$> crop_string_ends "|abcdefg|"
abcdefg
$> crop_string_ends "HelloWorld"
elloWorl
Python
>>> mystring="|abcdefg|"
>>> print(mystring[1:-1])
abcdefg
or on command line:
$ python -c 'import sys;print sys.stdin.read()[1:-2]' <<< "|abcdefg|"
abcdefg
AWK
$ echo "|abcdefg|" | awk '{print substr($0,2,length($0)-2)}'
abcdefg
Ruby
$ ruby -ne 'print $_.split("|")[1]' <<< "|abcdefg|"
abcdefg
add a comment |
shell function
A bit more verbose approach, but works on any sort of first and last character, doesn't have to be the same. Basic idea is that we are taking a variable, reading it character by character, and appending only those
we want to a new variable
Here's that whole idea formatted into a nice function
crop_string_ends() {
STR="$1"
NEWSTR=""
COUNT=0
while read -n 1 CHAR
do
COUNT=$(($COUNT+1))
if [ $COUNT -eq 1 ] || [ $COUNT -eq ${#STR} ]
then
continue
fi
NEWSTR="$NEWSTR"$CHAR
done <<<"$STR"
echo $NEWSTR
}
And here is that same function in action:
$> crop_string_ends "|abcdefg|"
abcdefg
$> crop_string_ends "HelloWorld"
elloWorl
Python
>>> mystring="|abcdefg|"
>>> print(mystring[1:-1])
abcdefg
or on command line:
$ python -c 'import sys;print sys.stdin.read()[1:-2]' <<< "|abcdefg|"
abcdefg
AWK
$ echo "|abcdefg|" | awk '{print substr($0,2,length($0)-2)}'
abcdefg
Ruby
$ ruby -ne 'print $_.split("|")[1]' <<< "|abcdefg|"
abcdefg
add a comment |
shell function
A bit more verbose approach, but works on any sort of first and last character, doesn't have to be the same. Basic idea is that we are taking a variable, reading it character by character, and appending only those
we want to a new variable
Here's that whole idea formatted into a nice function
crop_string_ends() {
STR="$1"
NEWSTR=""
COUNT=0
while read -n 1 CHAR
do
COUNT=$(($COUNT+1))
if [ $COUNT -eq 1 ] || [ $COUNT -eq ${#STR} ]
then
continue
fi
NEWSTR="$NEWSTR"$CHAR
done <<<"$STR"
echo $NEWSTR
}
And here is that same function in action:
$> crop_string_ends "|abcdefg|"
abcdefg
$> crop_string_ends "HelloWorld"
elloWorl
Python
>>> mystring="|abcdefg|"
>>> print(mystring[1:-1])
abcdefg
or on command line:
$ python -c 'import sys;print sys.stdin.read()[1:-2]' <<< "|abcdefg|"
abcdefg
AWK
$ echo "|abcdefg|" | awk '{print substr($0,2,length($0)-2)}'
abcdefg
Ruby
$ ruby -ne 'print $_.split("|")[1]' <<< "|abcdefg|"
abcdefg
shell function
A bit more verbose approach, but works on any sort of first and last character, doesn't have to be the same. Basic idea is that we are taking a variable, reading it character by character, and appending only those
we want to a new variable
Here's that whole idea formatted into a nice function
crop_string_ends() {
STR="$1"
NEWSTR=""
COUNT=0
while read -n 1 CHAR
do
COUNT=$(($COUNT+1))
if [ $COUNT -eq 1 ] || [ $COUNT -eq ${#STR} ]
then
continue
fi
NEWSTR="$NEWSTR"$CHAR
done <<<"$STR"
echo $NEWSTR
}
And here is that same function in action:
$> crop_string_ends "|abcdefg|"
abcdefg
$> crop_string_ends "HelloWorld"
elloWorl
Python
>>> mystring="|abcdefg|"
>>> print(mystring[1:-1])
abcdefg
or on command line:
$ python -c 'import sys;print sys.stdin.read()[1:-2]' <<< "|abcdefg|"
abcdefg
AWK
$ echo "|abcdefg|" | awk '{print substr($0,2,length($0)-2)}'
abcdefg
Ruby
$ ruby -ne 'print $_.split("|")[1]' <<< "|abcdefg|"
abcdefg
edited Dec 24 '16 at 21:14
answered Apr 6 '16 at 13:58
Sergiy KolodyazhnyySergiy Kolodyazhnyy
71.5k9147313
71.5k9147313
add a comment |
add a comment |
Small and universal solution:
expr "|abcdef|" : '.(.*).'
Special in this case and allowing that the '|' character may be there or not:
expr "|abcdef" : '|*([^|]*)|*'
add a comment |
Small and universal solution:
expr "|abcdef|" : '.(.*).'
Special in this case and allowing that the '|' character may be there or not:
expr "|abcdef" : '|*([^|]*)|*'
add a comment |
Small and universal solution:
expr "|abcdef|" : '.(.*).'
Special in this case and allowing that the '|' character may be there or not:
expr "|abcdef" : '|*([^|]*)|*'
Small and universal solution:
expr "|abcdef|" : '.(.*).'
Special in this case and allowing that the '|' character may be there or not:
expr "|abcdef" : '|*([^|]*)|*'
edited Jul 8 '17 at 23:37
answered Jul 8 '17 at 23:29
Tosi DoTosi Do
112
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